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WGU Introduction-to-Cryptography Exam Syllabus Topics:

SectionObjectives
Applied Cryptography- Cryptographic Best Practices
- VPN Security
- PGP and Email Encryption
- SSL/TLS Protocols
Hashing and Digital Signatures- Digital Signature Standards
- Message Authentication Codes (MAC)
- Hash Functions (MD5, SHA-1, SHA-256)
Cryptography Fundamentals- Cryptographic Terminology
- Symmetric vs Asymmetric Encryption
- History and Evolution of Cryptography
Asymmetric Cryptography- Public Key Infrastructure (PKI)
- Elliptic Curve Cryptography (ECC)
- RSA Algorithm
- Diffie-Hellman Key Exchange
Symmetric Cryptography- Initialization Vectors (IV)
- Stream Ciphers
- Block Ciphers (AES, DES, 3DES)
- Key Management
Cryptanalysis and Attacks- Common Attack Vectors
- Brute Force and Dictionary Attacks
- Social Engineering Prevention

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WGU Introduction to Cryptography HNO1 Sample Questions (Q48-Q53):

NEW QUESTION # 48
(What is the correlation between the number of rounds and the key length used in the AES algorithm?)

Answer: B

Explanation:
In AES, the number of rounds is explicitly tied to the key length. AES-128 uses 10 rounds, AES-192 uses 12 rounds, and AES-256 uses 14 rounds. The purpose of additional rounds is to increase diffusion and confusion, strengthening resistance against cryptanalysis as the key schedule and state transformations iterate more times. Although key length primarily affects brute-force resistance, AES's designers and standardization parameters link longer keys with more rounds to maintain security margins across variants, especially considering differences in the key schedule structure. Thus, as key length increases from 128 to 192 to 256 bits, the number of rounds increases correspondingly from 10 to
12 to 14. This relationship is fixed by the AES specification and does not vary dynamically at runtime.
Therefore, the correct correlation is that the number of rounds increases as the key length increases.


NEW QUESTION # 49
(What is used to randomize the initial value when generating Initialization Vectors (IVs)?)

Answer: D

Explanation:
An IV (Initialization Vector) is a value used to ensure that encrypting identical plaintext under the same key produces different ciphertexts, preventing pattern leakage. In many secure designs, the IV must be unique (and often unpredictable) per encryption operation. A common way to ensure uniqueness is to incorporate a nonce-a "number used once." A nonce can be random, pseudo-random, or a counter-based value depending on the mode and security requirements. For example, CTR mode uses a nonce combined with a counter to produce unique input blocks; GCM uses a nonce/IV to ensure unique authentication and encryption behavior.
The encryption key should remain stable across many operations and should not be used as the "randomizer" for IV generation; mixing key material into IV creation in an ad hoc way can create reuse or correlation issues. Plaintext and algorithm do not provide the needed uniqueness property. The nonce concept is specifically about ensuring one-time uniqueness of the starting value so that IV reuse does not repeat keystream blocks (stream modes) or reveal plaintext equality (CBC/CTR). Therefore, the correct choice is Nonce.


NEW QUESTION # 50
(Why should a forensic investigator create a hash of a victim's hard drive and of the bitstream copy of the hard drive?)

Answer: C

Explanation:
In digital forensics, investigators must preserve evidence integrity and demonstrate an unbroken chain of custody. Creating a cryptographic hash (such as SHA-256) of the original drive and then hashing the forensic bitstream image provides a strong mathematical assurance that the copy is an exact, bit-for-bit replica. Because secure hash functions are designed so that any tiny change in data produces a dramatically different digest, matching hashes indicate the image contains identical data to the source at the time of acquisition. This is critical in legal and investigative contexts: analysis is performed on the copy, not the original, to avoid altering evidence. If the hashes match, the investigator can testify that the evidence examined is identical to what was collected, supporting admissibility and credibility.
Hashing does not prove who created files, nor does it directly show whether someone "opened the drive"; it specifically validates the integrity and equivalence of the captured image. Therefore, hashing both artifacts is done to verify that the original and the bitstream copy are identical.


NEW QUESTION # 51
(Which attack may take the longest amount of time to achieve success?)

Answer: C

Explanation:
A brute-force attack exhaustively tries every possible key or password candidate until the correct one is found. Because it explores the full search space (or a very large portion of it), brute force is often the slowest method, especially when strong keys, long passwords, rate limits, and slow password hashing (bcrypt
/Argon2) are used. By contrast, a dictionary attack reduces work by trying only common or likely passwords, often succeeding quickly against weak human-chosen secrets. Rainbow table attacks shift work into precomputation; once a table exists, lookup can be faster than brute-force-though salt and modern hashing defeat them. Birthday attacks are about finding collisions, not necessarily recovering a specific secret, and their expected work is about 2

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