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| Section | Objectives |
|---|---|
| Hashing and Digital Signatures | - Message Authentication Codes (MAC) - Digital Signature Standards - Hash Functions (MD5, SHA-1, SHA-256) |
| Applied Cryptography | - PGP and Email Encryption - VPN Security - SSL/TLS Protocols - Cryptographic Best Practices |
| Symmetric Cryptography | - Key Management - Stream Ciphers - Block Ciphers (AES, DES, 3DES) - Initialization Vectors (IV) |
| Cryptography Fundamentals | - Symmetric vs Asymmetric Encryption - Cryptographic Terminology - History and Evolution of Cryptography |
| Cryptanalysis and Attacks | - Social Engineering Prevention - Common Attack Vectors - Brute Force and Dictionary Attacks |
| Asymmetric Cryptography | - Diffie-Hellman Key Exchange - RSA Algorithm - Public Key Infrastructure (PKI) - Elliptic Curve Cryptography (ECC) |
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NEW QUESTION # 35
(What is the correlation between the number of rounds and the key length used in the AES algorithm?)
Answer: A
Explanation:
In AES, the number of rounds is explicitly tied to the key length. AES-128 uses 10 rounds, AES-192 uses 12 rounds, and AES-256 uses 14 rounds. The purpose of additional rounds is to increase diffusion and confusion, strengthening resistance against cryptanalysis as the key schedule and state transformations iterate more times. Although key length primarily affects brute-force resistance, AES's designers and standardization parameters link longer keys with more rounds to maintain security margins across variants, especially considering differences in the key schedule structure. Thus, as key length increases from 128 to 192 to 256 bits, the number of rounds increases correspondingly from 10 to
12 to 14. This relationship is fixed by the AES specification and does not vary dynamically at runtime.
Therefore, the correct correlation is that the number of rounds increases as the key length increases.
NEW QUESTION # 36
(A security analyst uses a polyalphabetic substitution cipher with a keyword of YELLOW to encrypt a message. Which cipher should be used to encrypt the message?)
Answer: C
Explanation:
A polyalphabetic substitution cipher uses multiple substitution alphabets rather than a single fixed mapping. The classic cipher that uses a keyword to select shifting alphabets across the message is the Vigenere cipher. In Vigenere, each plaintext letter is shifted by an amount determined by the corresponding key letter (repeating the keyword as needed). For example, a keyword like "YELLOW" is aligned under the plaintext; each key character defines a Caesar shift (A=0, B=1, ...) applied to the plaintext character, producing ciphertext. This rotation of alphabets across positions makes Vigenere more resistant to simple frequency analysis than monoalphabetic substitution, because the same plaintext letter may encrypt to different ciphertext letters depending on its position relative to the key.
The Pigpen cipher is a symbol substitution cipher, Caesar is monoalphabetic with a single shift, and Playfair is a digraph substitution cipher using a 5×5 key square, not the repeating-key polyalphabetic method described. Therefore, the correct cipher is Vigenere.
NEW QUESTION # 37
(Which symmetric encryption technique uses a 256-bit key size and a 128-bit block size?)
Answer: C
Explanation:
AES (Advanced Encryption Standard) is a symmetric block cipher standardized to operate on a fixed 128-bit block size and supports key sizes of 128, 192, and 256 bits. When the key size is 256 bits, the cipher is commonly referred to as AES-256, but the block size remains 128 bits regardless of key length. This combination (256-bit key, 128-bit block) matches the question precisely. By comparison, DES uses a 64-bit block size with a 56-bit effective key. 3DES also uses a 64-bit block size and effectively applies DES three times, yielding an effective key length typically cited as 112 bits (two-key 3DES) or 168 bits (three-key
3DES), depending on how keys are configured. IDEA uses a 64-bit block size with a 128-bit key. Therefore, the only listed algorithm that supports a 256-bit key while maintaining a 128-bit block size is AES. This is one reason AES is widely adopted for modern symmetric encryption: strong key sizes with efficient implementation and broad standardization.
NEW QUESTION # 38
(Which attack may take the longest amount of time to achieve success?)
Answer: D
Explanation:
A brute-force attack exhaustively tries every possible key or password candidate until the correct one is found. Because it explores the full search space (or a very large portion of it), brute force is often the slowest method, especially when strong keys, long passwords, rate limits, and slow password hashing (bcrypt
/Argon2) are used. By contrast, a dictionary attack reduces work by trying only common or likely passwords, often succeeding quickly against weak human-chosen secrets. Rainbow table attacks shift work into precomputation; once a table exists, lookup can be faster than brute-force-though salt and modern hashing defeat them. Birthday attacks are about finding collisions, not necessarily recovering a specific secret, and their expected work is about 2
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