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CWNP CWNA-109 Exam Syllabus Topics:

TopicDetails
Topic 1
  • RF Validation and WLAN remediation: This topic covers RF interference, WLAN performance, the basic features of validation tools, and common wireless issues.
Topic 2
  • Radio Frequency (RF) Technologies: This topic explains the basic features and behavior of RF. It also discusses applying the basic concepts of RF mathematics and measurement. Lastly, the topic covers RF signal characteristics and the functionality of RF antennas.
Topic 3
  • WLAN Network Architecture and Design Concepts: This topic deals with describing and implementing Power over Ethernet (PoE). Furthermore, the topic covers different wireless LAN architectures, coverage requirements, roaming considerations, and common proprietary features in wireless networks.
Topic 4
  • WLAN Network Security: It addresses the concepts of weak security options, security mechanisms for enterprise WLANs, and security options and tools used in wireless networks.

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CWNP Wireless Network Administrator (CWNA) Sample Questions (Q93-Q98):

NEW QUESTION # 93
Which antenna type radiates RF energy equally in all directions in a spherical pattern and is used primarily as a theoretical reference for calculating antenna gain?

Answer: B

Explanation:
An isotropic radiator is a theoretical, hypothetical antenna that radiates RF energy equally in all directions, forming a perfect sphere. It does not exist in reality but is used as a baseline reference point for measuring antenna gain, expressed in dBi (decibels relative to an isotropic radiator). All real-world antennas focus energy in some directions more than others, and their gain is calculated by comparing their radiation pattern to that of the isotropic radiator.


NEW QUESTION # 94
An 802.11 WLAN transmitter that emits a 50 mW signal is connected to a cable with 3 dB of loss. The cable is connected to an antenna with 16 dBi of gain. What is the power level at the Intentional Radiator?

Answer: B

Explanation:
The power level at the Intentional Radiator (IR) is 250 mW. The IR is the point where the RF signal leaves the transmitter and enters the antenna system. To calculate the power level at the IR, we need to consider the output power level of the transmitter, the loss of the cable, and the gain of the antenna. The formula is:
Power level at IR (dBm) = Output power level (dBm) - Cable loss (dB) + Antenna gain (dBi) We can convert the output power level of 50 mW to dBm by using the formula:
Power level (dBm) = 10 * log10(Power level (mW))
Therefore, 50 mW = 10 * log10(50) = 16.99 dBm
We can plug in the values into the formula:
Power level at IR (dBm) = 16.99 - 3 + 16 = 29.99 dBm
We can convert the power level at IR from dBm to mW by using the inverse formula:
Power level (mW) = 10

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