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| Section | Objectives |
|---|---|
| Xcode Developer Tools | - Identify and use the features of the Xcode interface
|
| View Building with SwiftUI | - Create a multi-view app with navigation Stacks, Links, and/or Sheets - Use List Views to iterate through collections - Create multiple Views to implement app logic - Use @State, @Binding, @Environment, and/or Observable to share data between Views - Position and/or layout a single SwiftUI View with standard Views and modifiers - Extract Subviews to simplify the structure of an overlarge View |
| Swift Programming Language | - Use functions
- Declare and use basic Swift types
|
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問題 #40
You have created a view which includes some formatted text:
You decide to extract this formatted text into a subview so that you can reuse the formatting for other texts.
You highlight the Text and choose Extract subview.
You refactor ExtractedView to BigGreenTextView.
You add the line let text: String to the extracted view above the body.
You replace " That ' s all folks " with a reference to text
How should you call this extracted View from the original View?
答案：B
解題說明：
This question belongs to View Building with SwiftUI , specifically the domain on extracting subviews to simplify the structure of an overlarge View .
When you create a custom SwiftUI view and add a stored property like:
let text: String
that property becomes part of the view's initializer. Since the property name is text, Swift expects you to pass the value using the parameter label text: when creating the view. So the correct call is:
BigGreenTextView(text: " That ' s all folks " )
That makes B the correct answer.
Why the others are wrong:
* A is incorrect because this is not using the expected parameter label.
* C would only be correct if there were already another variable named text in the calling scope and you wanted to pass that variable instead of the literal string shown in the question.
* D is incorrect because it omits the parameter label.
This is a standard SwiftUI pattern: extract reusable formatting into a separate custom View, give it an input property, and then pass the needed value through the initializer using the property label.
問題 #41
Complete the code that will add the BlueView to the NavigationStack and present the RedView modally.
|Complete the code by typing in the boxes.
答案：
解題說明：
NavigationLink, .sheet
Explanation:
This question falls under View Building with SwiftUI , specifically the domain covering multi-view apps with navigation stacks, links, and sheets . The first blank must be NavigationLink because SwiftUI uses a navigation link inside a NavigationStack to push or present a destination view as part of the navigation hierarchy. Apple's documentation states that people tap or click a NavigationLink to present a view inside a NavigationStack or NavigationSplitView. That matches the first code section, where tapping " Show Blue View " should navigate to BlueView().
The second blank must be .sheet because the code uses isPresented: $showRedView, which is the standard SwiftUI sheet modifier for modal presentation controlled by a Boolean binding. Apple documents sheet (isPresented:onDismiss:content:) as the modifier to use when you want to present a modal view when a Boolean becomes true. Since the button toggles showRedView, SwiftUI presents RedView() modally as a sheet.
So the completed structure is effectively:
NavigationLink( " Show Blue View " ) {
BlueView()
}
sheet(isPresented: $showRedView) {
RedView()
}
This directly aligns with SwiftUI navigation and modal presentation patterns in the App Development with Swift objective domains.
問題 #42
Complete the code by selecting the correct option from each drop-down list to create the following screen.
Note: You will receive partial credit for each correct answer.
答案：
解題說明：
問題 #43
Which two statements about building an app are true? (Choose 2.)
答案：A,E
解題說明：
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to Xcode Developer Tools , especially the objectives about using the Xcode interface, building and running an app, and debugging. A is true because Xcode supports SwiftUI previews in the canvas, allowing you to see a view's interface directly in Xcode without fully launching the entire app in the normal run workflow. Apple's documentation states that Xcode can display a preview of a custom SwiftUI view in the preview canvas and keep it updated as you make code changes.
D is also true because when you run an app from Xcode on a device, Xcode opens a debugging session in the debug area. Apple explicitly documents that after a successful build, Xcode runs the app and opens a debugging session, which means you can view debug information while the app is running on the phone.
The other options are false. B is false because a phone does not have to be physically attached at all times; modern Xcode workflows support device pairing and wireless development after setup. C is false because Generic iOS Device is not an actual simulator run target for launching the app like a specific simulator device. E is false because you do not need a paid Apple Developer Program membership merely to run an app on your own device for development; Apple provides support for development testing on devices with the required setup such as pairing and Developer Mode.
問題 #44
Review the code snippet and identify what happens when the program is executed.
答案：D
解題說明：
This question belongs to Swift Programming Language , specifically the objectives covering arrays , loops
, and range operators . The array has 6 elements, so menuItems.count is 6. The loop uses the half-open range operator:
for index in 1.. < (menuItems.count - 1)
That becomes:
for index in 1.. < 5
In Swift, the half-open range operator a.. < b includes the lower bound but does not include the upper bound.
So this loop runs with index values 1, 2, 3, 4, not 0 and not 5.
Array subscripting uses those indexes to print:
* menuItems[1] # " Burger "
* menuItems[2] # " Chicken "
* menuItems[3] # " Pasta "
* menuItems[4] # " Salad "
That means " Pizza " at index 0 is skipped, and " Steak " at index 5 is also skipped. Swift arrays use zero- based indexing, and count returns the number of elements in the array.
Therefore, the program prints only " Burger " , " Chicken " , " Pasta " , and " Salad " , so the correct answer is A .
問題 #45
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