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| Section | Objectives |
|---|---|
| Key Management and PKI | - Key exchange and lifecycle management - Certificates, certificate authorities, and PKI structure |
| Foundations of Cryptography | - Core concepts of confidentiality, integrity, authentication, non-repudiation - Historical and modern cryptography principles |
| Symmetric Encryption | - AES and legacy algorithms (e.g., DES conceptually) - Block and stream ciphers |
| Hash Functions and Message Authentication | - Cryptographic hash functions (e.g., SHA family concepts) - MAC and HMAC mechanisms |
| Asymmetric Encryption | - Public key cryptography principles - RSA and ECC fundamentals |
| Cryptographic Protocols and Applications | - TLS/SSL conceptual overview - Secure communication design principles |
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26. Frage
(What describes how Counter (CTR) mode encryption functions?)
Antwort: A
Begründung:
CTR mode turns a block cipher (like AES) into a stream-like construction by generating a keystream from successive encryptions of a changing input block. Specifically, CTR forms input blocks using a nonce (unique per message) combined with an increasing counter. Each nonce||counter block is encrypted with the block cipher under the shared key, producing a pseudorandom output block. That output is then XORed with plaintext to yield ciphertext (and XORed with ciphertext to recover plaintext). This design enables parallelization (blocks can be generated independently), efficient random access decryption, and avoids chaining dependencies seen in modes like CBC. Option B describes CFB-like behavior; option C describes ECB; option D describes CBC. CTR's security critically depends on never reusing the same nonce/counter sequence with the same key, because reuse would repeat keystream blocks and expose plaintext relationships. Therefore, the correct description is that CTR converts the block cipher into a stream cipher using a counter value and a nonce.
27. Frage
(What type of encryption uses different keys to encrypt and decrypt the message?)
Antwort: C
Begründung:
Asymmetric encryption (also called public key cryptography) uses a pair of mathematically related keys: a public key and a private key. One key is used to encrypt, and the other is used to decrypt, which is the defining "different keys" property asked in the question. In the common confidentiality use case, a sender encrypts a message using the recipient's public key, and only the recipient can decrypt it using their private key. This solves the key distribution problem inherent in symmetric encryption, where both parties must securely share the same secret key in advance. Asymmetric systems also enable digital signatures: the private key signs (creates a signature) and the public key verifies it, providing authenticity and integrity. Symmetric encryption, by contrast, uses the same shared key for both encryption and decryption (even though internal round keys may exist, it is still one shared secret). "Private key" alone is not a full encryption type, and
"secure" is a generic description rather than a cryptographic category. Therefore, the correct answer is D.
Asymmetric.
28. Frage
(What is an example of a block cipher mode of operation?)
Antwort: D
Begründung:
A block cipher mode of operation defines how a block cipher (such as AES) is applied to data longer than a single block, and how blocks are linked (or not linked) to provide certain security properties. ECB (Electronic Codebook) is one of the canonical block cipher modes: it encrypts each plaintext block independently using the same key. While ECB is generally discouraged because it leaks patterns (identical plaintext blocks produce identical ciphertext blocks), it is still a valid and historically important mode of operation and is often used as a teaching example of what not to do for structured data. In contrast, SHA-256 is a hash function (one- way digest) and not a mode for block ciphers. DSA is a digital signature algorithm and provides authenticity
/integrity, not encryption mode behavior. RSA is an asymmetric cryptosystem, not a block cipher mode.
Therefore, among the options, ECB is the correct example of a block cipher mode of operation.
29. Frage
(Which encryption algorithm encrypts with one key, decrypts with another key, and then encrypts with the first key?)
Antwort: C
Begründung:
3DES (Triple DES) commonly uses an Encrypt-Decrypt-Encrypt (EDE) sequence. In the two-key form, it encrypts with key K1, decrypts with key K2, then encrypts again with K1. In the three-key form, it encrypts with K1, decrypts with K2, then encrypts with K3. The EDE construction was chosen partly for backward compatibility: if K1=K2=K3, the scheme reduces to single DES, allowing older systems to interoperate in constrained ways. AES and IDEA do not use an EDE triple-stage process as their defining structure; they are single-pass block ciphers with internal rounds. DES is a single-pass algorithm (one key) rather than a triple application with multiple keys. Therefore, the algorithm described-encrypt with one key, decrypt with another, encrypt with the first-is 3DES. Although now considered legacy, it remains a classic example of increasing effective security by applying a block cipher multiple times with independent keys.
30. Frage
(Which attack may take the longest amount of time to achieve success?)
Antwort: C
Begründung:
A brute-force attack exhaustively tries every possible key or password candidate until the correct one is found. Because it explores the full search space (or a very large portion of it), brute force is often the slowest method, especially when strong keys, long passwords, rate limits, and slow password hashing (bcrypt/Argon2) are used. By contrast, a dictionary attack reduces work by trying only common or likely passwords, often succeeding quickly against weak human-chosen secrets. Rainbow table attacks shift work into precomputation; once a table exists, lookup can be faster than brute-force-though salt and modern hashing defeat them. Birthday attacks are about finding collisions, not necessarily recovering a specific secret, and their expected work is about 2
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