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| Certification Vendor: | Juniper Networks |
|---|---|
| Exam Name: | Service Provider Routing and Switching, Professional (JNCIP-SP) |
| Exam Number: | JN0-664 |
| Exam Duration: | 90 minutes |
| Certificate Validity Period: | 3 years |
| Exam Price: | $400 USD |
| Related Certifications: | JNCIE-SP JNCIA-Junos JNCIS-SP |
| Real Exam Qty: | 65 |
| Exam Format: | Multiple choice (single answer, multiple answers) |
| Available Languages: | English |
| Passing Score: | 70% (approximate, pass/fail result) |
| Recommended Training: | Advanced Junos Service Provider Routing (AJSPR) Junos Layer 2 VPNs (JL2V) Junos Layer 3 VPNs (JL3V) |
| Exam Registration: | Pearson VUE Registration |
| Sample Questions: | Juniper JN0-664 Sample Questions |
| Exam Way: | Online proctored or onsite at Pearson VUE test centers |
| Pre Condition: | Juniper Networks Certified Specialist, Service Provider (JNCIS-SP) certification |
| Official Syllabus URL: | https://www.juniper.net/us/en/training/certification/tracks/service-provider-routing-switching/jncip-sp.html |
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Juniper JN0-664 exam is an important certification for network engineers working in the service provider industry. Passing JN0-664 exam validates the candidate's expertise in configuring, troubleshooting, and maintaining Juniper Networks' service provider routing and switching platforms. The JN0-664 Exam is a comprehensive test that covers a wide range of topics related to service provider routing and switching and is designed for network engineers with three to five years of experience.
NEW QUESTION # 11
Refer to the exhibit.
Click the Exhibit button.
You are troubleshooting an issue for a customer site that uses 10.10.0.0/24 in AS 65224, but you see another AS in the AS path.
Referring to the exhibit, what is the cause of the problem?
Answer: D
NEW QUESTION # 12
Exhibit
user@Rl show configuration interpolated-profile { interpolate {
fill-level [ 50 75 drop-probability [ > }
class-of-service drop-profiles
];
20 60 ];
Which two statements are correct about the class-of-service configuration shown in the exhibit? (Choose two.)
Answer: A,D
Explanation:
class-of-service (CoS) is a feature that allows you to prioritize and manage network traffic based on various criteria, such as application type, user group, or packet loss priority. CoS uses different components to classify, mark, queue, schedule, shape, and drop traffic according to the configured policies.
One of the components of CoS is drop profiles, which define how packets are dropped when a queue is congested. Drop profiles use random early detection (RED) algorithm to drop packets randomly before the queue is full, which helps to avoid global synchronization and improve network performance. Drop profiles can be discrete or interpolated. A discrete drop profile maps a specific fill level of a queue to a specific drop probability. An interpolated drop profile maps a range of fill levels of a queue to a range of drop probabilities and interpolates the values in between.
In the exhibit, we can see that the class-of-service configuration shows an interpolated drop profile with two fill levels (50 and 75) and two drop probabilities (20 and 60). Based on this configuration, we can infer the following statements:
* The drop probability jumps immediately from 20% to 60% when the queue level reaches 75% full. This is not correct because the drop profile is interpolated, not discrete. This means that the drop probability gradually increases from 20% to 60% as the queue level increases from 50% full to 75% full. The drop probability for any fill level between 50% and 75% can be calculated by using linear interpolation formula.
* The drop probability gradually increases from 20% to 60% as the queue level increases from 50% full to
75% full. This is correct because the drop profile is interpolated and uses linear interpolation formula to calculate the drop probability for any fill level between 50% and 75%. For example, if the fill level is
60%, the drop probability is 28%, which is calculated by using the formula: (60 - 50) / (75 - 50) * (60 -
20) + 20 = 28.
* To use this drop profile, you reference it in a scheduler. This is correct because a scheduler is a
* component of CoS that determines how packets are dequeued from different queues and transmitted on an interface. A scheduler can reference a drop profile by using the random-detect statement under the
[edit class-of-service schedulers] hierarchy level. For example: scheduler test { transmit-rate percent 10; buffer-size percent 10; random-detect test-profile; }
* To use this drop profile, you apply it directly to an interface. This is not correct because a drop profile cannot be applied directly to an interface. A drop profile can only be referenced by a scheduler, which can be applied to an interface by using the scheduler-map statement under the [edit class-of-service interfaces] hierarchy level. For example: interfaces ge-0/0/0 { unit 0 { scheduler-map test-map; } }
NEW QUESTION # 13
Exhibit
You must ensure that the VPN backbone is preferred over the back door intra-area link as long as the VPN is available. Referring to the exhibit, which action will accomplish this task?
Answer: D
Explanation:
A sham link is a logical link between two PE routers that belong to the same OSPF area but are connected through an L3VPN. A sham link makes the PE routers appear as if they are directly connected, and prevents OSPF from preferring an intra-area back door link over the VPN backbone. To create a sham link, you need to configure the local and remote addresses of the PE routers under the [edit protocols ospf area area-id] hierarchy level1.
https://www.juniper.net/documentation/us/en/software/junos/ospf/topics/topic-map/configuring-ospfv2-sham-links.html
NEW QUESTION # 14
You are attempting to summarize routes from the 203.0.113.128/25 IP block on R8 to AS 64500.
You implement the export policy shown in the exhibit and all routes from the routing table stop being advertised.
In this scenario, which two steps would you take to summarize the route in BGP? (Choose two.)
Answer: B,D
NEW QUESTION # 15 
Click the Exhibit button.
Referring to the exhibit, the PE-to-CE protocol being used is OSPF for the L3VPN. Also, there is an OSPF neighborship between CE-1 and CE-2.
Which statement is correct in this situation?
Answer: A
Explanation:
In the exhibit, the PE-to-CE protocol used is OSPF, and there is an OSPF neighborship between CE-1 and CE-2 within the same Area 0. Let's analyze the default OSPF routing behavior in this setup to determine the correct statement.
1. **OSPF Neighborship**:
- CE-1 and CE-2 have an OSPF neighborship directly within Area 0.
- OSPF prefers intra-area routes over inter-area and external routes.
2. **Default Routing Behavior**:
- Since CE-1 and CE-2 are directly connected through an OSPF link within the same area, OSPF will prefer this direct intra-area path over any other paths learned via the PE routers and the L3VPN.
- This is because intra-area routes have a lower metric compared to inter-area or external routes.
3. **Metric Considerations**:
- By default, OSPF will route traffic between Site-1 and Site-2 through the direct link between CE-1 and CE-2, unless the link's metric is artificially increased to make it less preferable.
- There is no need to adjust metrics for the CE-1 to PE-1 link to prefer the CE-1 to CE-2 path, as OSPF already prefers direct intra-area paths.
**Conclusion**:
Given the default behavior of OSPF and the topology shown in the exhibit, the correct statement is:
**B. Hosts at Site-1 will reach hosts at Site-2 through the CE-1 and CE-2 link by default.**
**References**:
- OSPF Design Guide: [Juniper Networks OSPF Design
Guide](https://www.juniper.net/documentation/en_US/junos/topics/concept/ospf-design-overview.html)
- Juniper Networks Technical Documentation on OSPF: [Junos OS OSPF Configuration Guide](https://www.juniper.net/documentation/en_US/junos/topics/concept/ospf-routing-overview.html)
NEW QUESTION # 16
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