CWNP CWNA-109: CWNP Wireless Network Administrator (CWNA) braindumps PDF & Testking echter Test

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CWNP Wireless Network Administrator (CWNA) CWNA-109 Prüfungsfragen mit Lösungen (Q95-Q100):

95. Frage
Return Loss is the decrease of forward energy in a system when some of the power is being reflected back toward the transmitter. What will cause high return loss in an RF transmission system, including the radio, cables, connectors and antenna?

• A. High output power at the transmitter and use of a low-gain antenna
• B. The use of 50 ohm cables longer than one meter in the RF system
• C. A Voltage Standing Wave Ratio (VSWR) of 1:1
• D. A significant impedance mismatch between components in the RF system

Antwort: D

Begründung:
Return loss is a measure of how well the components of an RF system are matched in terms of their impedance. Impedance is the opposition to the flow of alternating current in a circuit, and it depends on the frequency, resistance, capacitance, and inductance of the components. When the impedance of the source, the transmission line, and the load are not equal, some of the power is reflected back to the source, causing a loss of forward power. This loss is expressed in decibels (dB) as return loss. The higher the return loss, the lower the reflection and the better the impedance matching. Conversely, the lower the return loss, the higher the reflection and the worse the impedance matching.
VSWR (Voltage Standing Wave Ratio) is another way of expressing the same concept. It is the ratio of the maximum voltage to the minimum voltage along a transmission line due to the interference of the incident and reflected waves. A VSWR of 1:1 means that there is no reflection and perfect impedance matching. A VSWR higher than 1:1 means that there is some reflection and impedance mismatch. The higher the VSWR, the higher the reflection and the lower the return loss. Therefore, a significant impedance mismatch between components in an RF system will cause high reflection, high VSWR, and low return loss.

96. Frage
You administer a WLAN that offers a guest SSID of GUESTNWORK. Users connect to the GUESTNWORK SSID, but report that they cannot browse the Internet. The devices simply report no Internet connection. What common problem causes this scenario?

• A. IP routing issues
• B. NTP issues
• C. Hardware issues
• D. Captive portal issues

Antwort: D

Begründung:
A common problem that causes this scenario is captive portal issues. A captive portal is a web page that requires users to authenticate or accept terms and conditions before accessing the Internet through a WLAN. A captive portal is often used for guest networks to provide security and control over the network access. A captive portal works by intercepting the user's web requests and redirecting them to the portal page until the user completes the required action.
However, sometimes the captive portal may not work properly due to various reasons, such as browser settings, firewall rules, DNS configuration, or network errors. This can prevent the user from browsing the Internet or seeing the portal page. To troubleshoot captive portal issues, you can try to use a different browser, clear the browser cache and cookies, disable any VPN or proxy settings, manually enter the portal URL, or contact the network administrator. NTP issues, hardware issues, or IP routing issues are not common problems that cause this scenario.

97. Frage
What statement about the IEEE 802.11-2016 QoS facility is true?

• A. 802.11 QoS is achieved by giving high priority queues a statistical advantage at winning contention.
• B. When the Voice queue has frames awaiting transmission, no data will be transmitted from the Best Effort queue.
• C. 802.11 control frames are assigned to the 802.11 EF priority queue.
• D. Four 802.1p user priorities are mapped to eight 802.11 transmit queues.

Antwort: A

Begründung:
802.11 QoS is achieved by giving high priority queues a statistical advantage at winning contention. 802.11 QoS is based on the Enhanced Distributed Channel Access (EDCA) mechanism, which defines four access categories (ACs) for different types of traffic: Voice, Video, Best Effort, and Background. Each AC has its own transmit queue and contention parameters, such as Arbitration Interframe Space (AIFS), Contention Window (CW), and Transmission Opportunity (TXOP). These parameters determine how long a station has to wait before transmitting a frame and how long it can occupy the channel. Higher priority ACs have shorter AIFS, smaller CW, and longer TXOP, which means they have more chances to access the channel and send more data than lower priority ACs. However, this does not guarantee that higher priority ACs will always win the contention, as there is still a random backoff process involved. Therefore, 802.11 QoS is a statistical service that provides different levels of service quality based on traffic categories.

98. Frage
An 802.11 WLAN transmitter that emits a 50 mW signal is connected to a cable with 3 dB of loss.
The cable is connected to an antenna with 16 dBi of gain. What is the power level at the Intentional Radiator?

• A. 500 mW
• B. 250 mW
• C. 1000 mW
• D. 25 mW

Antwort: C

Begründung:
The power level at the Intentional Radiator (IR) is 250 mW. The IR is the point where the RF signal leaves the transmitter and enters the antenna system. To calculate the power level at the IR, we need to consider the output power level of the transmitter, the loss of the cable, and the gain of the antenna. The formula is:
Power level at IR (dBm) = Output power level (dBm) - Cable loss (dB) + Antenna gain (dBi) We can convert the output power level of 50 mW to dBm by using the formula:
Power level (dBm) = 10 * log10(Power level (mW))
Therefore, 50 mW = 10 * log10(50) = 16.99 dBm
We can plug in the values into the formula:
Power level at IR (dBm) = 16.99 - 3 + 16 = 29.99 dBm
We can convert the power level at IR from dBm to mW by using the inverse formula:
Power level (mW) = 10

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