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WGU Applied-Algebra Exam Syllabus Topics:

SectionWeightObjectives
Topic 1: Algebraic Expressions and Operations20%- Simplifying and evaluating expressions
- Order of operations
- Operations with polynomials
- Variables, constants, and coefficients
Topic 2: Exponents, Radicals, and Quadratic Relationships15%- Solving quadratic equations
- Basic quadratic graphs
- Simplifying radical expressions
- Properties of exponents
Topic 3: Linear Equations and Inequalities25%- Real-world applications
- Solving single-variable equations
- Solving and graphing inequalities
Topic 4: Systems of Equations and Inequalities15%- Graphical solutions
- Applications of systems
- Solving by substitution and elimination
Topic 5: Graphing and Functions25%- Coordinate plane and plotting points
- Slope and equations of lines
- Function notation and evaluation
- Linear functions and their graphs

>> Applied-Algebra Exam Topic <<

Applied-Algebra Exam Topic | Valid Applied-Algebra: WGU Applied Algebra FXO2 PFXP C957

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q26-Q31):

NEW QUESTION # 26
As sacks are unloaded off a wagon, the total weight of the wagon and sacks changes. Each sack has the same weight. After 3 sacks are removed, the total weight of the cart and remaining sacks is 116 pounds. After 6 sacks are removed, the total weight is 101 pounds.
What is the weight of each sack?

Answer: A

Explanation:
This situation can be modeled using a linear relationship because each sack has the same weight.
We are given:
After 3sacks are removed, the total weight is 116pounds.
After 6sacks are removed, the total weight is 101pounds.
From 3 sacks removed to 6 sacks removed, the number of removed sacks increases by:
6-3=3
During that time, the total weight decreases from 116pounds to 101pounds:
116-101=15
So removing 3 additional sacks decreases the total weight by 15 pounds.
Now divide to find the weight of one sack:
15/3=5
So each sack weighs:
5 " pounds "
Check:
If 3 more sacks are removed and each sack weighs 5 pounds, the total weight should decrease by:
3(5)=15
116-15=101
This matches the given information.


NEW QUESTION # 27
A cart is being loaded with boxes, and each box has the same weight. After 4 boxes are loaded, the total weight of the boxes and cart is 116 pounds. After 9 boxes are loaded, the total weight is 161 pounds.
What is the weight of each box?

Answer: D

Explanation:
This situation can be modeled with a linear relationship because each box has the same weight.
We are given:
4 " boxes " #116 " pounds "
and
9 " boxes " #161 " pounds "
The weight increases because more boxes are added.
First, find the change in total weight:
161-116=45
Then find the change in the number of boxes:
9-4=5
Since 5 additional boxes increased the total weight by 45 pounds, the weight of each box is:
45/5=9
So each box weighs:
9 " pounds "
Check:
If each box weighs 9 pounds, then adding 5 more boxes adds:
5(9)=45
116+45=161
This matches the given information.


NEW QUESTION # 28
The scatterplot shows data on the number of shirts sold at a gift shop per week over time. The graphed regression function has an r
2
value of 0.09.

Which range of x-values is appropriate for extrapolation?

Answer: A

Explanation:
The r
2
value tells how closely the regression model fits the scatterplot data. In this problem, r
2
=0.09, which is extremely low. This means the regression model explains only a very small portion of the variation in the shirt-sales data. When r
2
is this weak, the model is not reliable for predictions outside the data range. Extrapolation is already less certain than interpolation because it predicts beyond the observed data. With such a poor fit, extending the model beyond the data would not be appropriate. Since 0.09 < 0.3, the best justification is that extrapolation is not appropriate because r
2
< 0.3. Therefore, the correct answer is C.


NEW QUESTION # 29
The scatterplot shows data on the number of visitors to a resort each week since opening. A regression function is graphed with r