Exam Applied-Algebra Vce Format, Applied-Algebra Valid Test Forum

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WGU Applied-Algebra Exam Syllabus Topics:

Section	Objectives
Topic 1: Polynomial and Rational Expressions	- Polynomials 1. Factoring techniques 2. Operations with polynomials - Rational Expressions 1. Restrictions on variables 2. Simplification
Topic 2: Functions and Graphs	- Function Concepts 1. Function notation 2. Domain and range - Graphing Functions 1. Transformations of graphs 2. Coordinate plane interpretation
Topic 3: Linear Functions and Systems	- Linear Equations 1. Point-slope form 2. Slope-intercept form - Systems of Equations 1. Substitution method 2. Elimination method
Topic 4: Exponential and Logarithmic Concepts	- Exponential Functions 1. Growth and decay models 2. Exponential equations - Logarithmic Basics 1. Conversion between exponential and logarithmic form 2. Logarithm properties
Topic 5: Foundations of Algebra	- Equations and Inequalities 1. Inequalities and interval notation 2. Linear equations in one variable - Algebraic Expressions 1. Evaluating expressions 2. Simplifying expressions 3. Order of operations

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q24-Q29):

NEW QUESTION # 24
A contractor charges a flat rate plus a fixed rate per hour to come and make repairs. For a job that takes 3 hours, the contractor charges $220. For a job that takes 5 hours, the contractor charges $340.
Which function correctly represents the total charge Cfor a job that takes thours?

A. C(t)=60t
B. C(t)=60t+40
C. C(t)=40t
D. C(t)=40t+60

Answer: B

Explanation:
The contractor charges a flat rate plus a fixed rate per hour, so this situation is modeled by a linear function:
C(t)=mt+b
where:
m= " hourly rate "
and
b= " flat rate "
We are given two points:
(3#220)
and
(5#340)
These mean:
A 3-hour job costs $220.
A 5-hour job costs $340.
First, find the hourly rate using slope:
m=(340-220)/(5-3)
m=120/2
m=60
So the contractor charges:
$60 " per hour "
Now the function has the form:
C(t)=60t+b
Use the point (3#220)to find the flat rate:
220=60(3)+b
220=180+b
b=40
So the function is:
C(t)=60t+40
Check with t=5:
C(5)=60(5)+40
C(5)=300+40
C(5)=340
This matches the given information.

NEW QUESTION # 25
The weight of a radioactive sample is given by the function
W(x)=740× # 0.87 #

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