Valid Applied-Algebra Exam Format - 100% Pass Applied-Algebra: WGU Applied Algebra FXO2 PFXP C957 First-grade Latest Braindumps Sheet

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WGU Applied-Algebra Exam Syllabus Topics:

SectionWeightObjectives
Topic 1: Graphing and Functions25%- Slope and equations of lines
- Function notation and evaluation
- Coordinate plane and plotting points
- Linear functions and their graphs
Topic 2: Linear Equations and Inequalities25%- Solving and graphing inequalities
- Real-world applications
- Solving single-variable equations
Topic 3: Systems of Equations and Inequalities15%- Graphical solutions
- Solving by substitution and elimination
- Applications of systems
Topic 4: Algebraic Expressions and Operations20%- Simplifying and evaluating expressions
- Variables, constants, and coefficients
- Order of operations
- Operations with polynomials
Topic 5: Exponents, Radicals, and Quadratic Relationships15%- Properties of exponents
- Basic quadratic graphs
- Solving quadratic equations
- Simplifying radical expressions

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q130-Q135):

NEW QUESTION # 130
The weekly number of players, P, in hundreds, on a gaming website is modeled by the graph. The horizontal axis shows the number of years since the website was launched.

When did the website reach the minimum weekly number of players?

Answer: D

Explanation:
The graph shows the weekly number of players on a gaming website.
The horizontal axis represents:
" years since launching "
The vertical axis represents:
" players in hundreds "
The graph is an upward-opening curve, so the minimum value occurs at the lowest point of the graph.
From the graph, the lowest point occurs at approximately:
t=4
This means the website reached its minimum weekly number of players approximately:
4 " years after it was launched "
Therefore, the correct answer is:
# ( " B " )


NEW QUESTION # 131
Consider the graph of h(t) shown. The function represents the height, h, in feet, of a ball t seconds after being launched.

What is the point, if any, at which the concavity changes from concave down to concave up?

Answer: A

Explanation:
The graph represents the height of a launched ball over time. Such height functions are typically quadratic because gravity causes the ball to rise, slow down, reach a maximum height, and then fall. The graph shown is a downward-opening parabola. A downward-opening parabola is concave down for its entire domain.
Concavity changes only if the curve switches from bending downward to bending upward, or from bending upward to bending downward. Since this graph bends downward the entire time, there is no point where the concavity changes from concave down to concave up. The vertex is a maximum point, but it is not a change in concavity. Therefore, the correct statement is that the graph is always concave down.


NEW QUESTION # 132
Consider the graph of x(t) shown. The function represents the number of users, x, watching a live video t hours after 9:00 a.m.

Which interval represents a range of values for which the number of users is decreasing slower and slower?

Answer: B

Explanation:
To describe "decreasing slower and slower," the graph must be moving downward while becoming less steep.
This means the function values are decreasing, but the rate of decrease is becoming smaller in magnitude. On the graph of x(t), the number of users first increases, then decreases after reaching a local maximum. The interval from t=6.8 to t=7.4 lies on a decreasing part of the curve where the graph is beginning to flatten compared with the steeper earlier decrease. That behavior means the number of users is still going down, but not as quickly as before. The other intervals either occur while the graph is increasing or include behavior that does not consistently match decreasing slower and slower. Therefore, the correct answer is C.


NEW QUESTION # 133
The function V(t)represents the number of travelers, V, in a travel depot thours after 7:00 a.m. The graph of V (t)is shown.

What does V(2)represent?

Answer: C

Explanation:
The function V(t)represents the number of travelers in the travel depot.
The input trepresents:
" hours after 7:00 a.m. "
The output V(t)represents:
" number of travelers "
So V(2)means the number of travelers in the depot:
2 " hours after 7:00 a.m. "
From the graph, when:
t=2
the value of V(t)is approximately:
79.2
Since V(t)measures travelers, not hours, V(2)represents:
79.2 " travelers "
Therefore, the correct answer is:
# ( " D " )


NEW QUESTION # 134
As sacks are unloaded off a wagon, the total weight of the wagon and sacks changes. Each sack has the same weight. After 3 sacks are removed, the total weight of the cart and remaining sacks is 116 pounds. After 6 sacks are removed, the total weight is 101 pounds.
What is the weight of each sack?

Answer: B

Explanation:
This situation can be modeled using a linear relationship because each sack has the same weight.
We are given:
After 3sacks are removed, the total weight is 116pounds.
After 6sacks are removed, the total weight is 101pounds.
From 3 sacks removed to 6 sacks removed, the number of removed sacks increases by:
6-3=3
During that time, the total weight decreases from 116pounds to 101pounds:
116-101=15
So removing 3 additional sacks decreases the total weight by 15 pounds.
Now divide to find the weight of one sack:
15/3=5
So each sack weighs:
5 " pounds "
Check:
If 3 more sacks are removed and each sack weighs 5 pounds, the total weight should decrease by:
3(5)=15
116-15=101
This matches the given information.


NEW QUESTION # 135
......

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