WGUのApplied-Algebra試験問題には3つの異なるバージョン（PDF、ソフトウェア、APPオンライン）があるため、Applied-Algebra学習ガイドのバージョンには複数の選択肢があり、興味や習慣に応じて選択できます。 WGUソフトウェアまたはAPPオンラインバージョンのApplied-Algebra準備資料は、コンピューターまたは電話で練習できます。 それらは、エレクトロニクス製品が私たちの生活や仕事のスタイルに広く適用されているという理由で開発された新しいものです。 Applied-Algebraの実際のWGU Applied Algebra FXO2 PFXP C957試験のPDFバージョンは印刷をサポートしており、論文で練習してメモを取ることができます。
| Section | Objectives |
|---|---|
| Topic 1: Exponential and Logarithmic Concepts | - Exponential Functions
|
| Topic 2: Functions and Graphs | - Function Concepts
|
| Topic 3: Foundations of Algebra | - Equations and Inequalities
|
| Topic 4: Linear Functions and Systems | - Linear Equations
|
| Topic 5: Polynomial and Rational Expressions | - Rational Expressions
|
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質問 # 75
The spread of two viruses within a single population is modeled using the functions in the graph.
What is a correct conclusion based on the graph?
正解：B
解説：
The graph compares the spread of two viruses over time.
The horizontal axis represents:
t= " time in months "
The vertical axis represents:
" percentage of the population affected "
The graph shows:
Virus A as the solid blue curve.
Virus B as the dashed blue curve.
To determine which statement is correct, we compare when each virus reaches the same population percentage.
At 20%:
Virus B reaches 20%earlier, around t#5months.
Virus A reaches 20%later, around t#6.5months.
So Virus B affects 20%of the population before Virus A does.
For higher percentages such as 60%, 70%, and 80%, Virus A rises more quickly after about 50%, so Virus A reaches those percentages before Virus B.
Therefore, the correct conclusion is:
" Virus B affects " 20% " of the population before virus A does. "
質問 # 76
Consider the graph of h(t) shown. The function represents the height, h, in feet, of a ball t seconds after being launched.
What is the point, if any, at which the concavity changes from concave down to concave up?
正解：A
解説：
The graph represents the height of a launched ball over time. Such height functions are typically quadratic because gravity causes the ball to rise, slow down, reach a maximum height, and then fall. The graph shown is a downward-opening parabola. A downward-opening parabola is concave down for its entire domain.
Concavity changes only if the curve switches from bending downward to bending upward, or from bending upward to bending downward. Since this graph bends downward the entire time, there is no point where the concavity changes from concave down to concave up. The vertex is a maximum point, but it is not a change in concavity. Therefore, the correct statement is that the graph is always concave down.
質問 # 77
As sacks are unloaded off a wagon, the total weight of the wagon and sacks changes. Each sack has the same weight. After 3 sacks are removed, the total weight of the cart and remaining sacks is 116 pounds. After 6 sacks are removed, the total weight is 101 pounds.
What is the weight of each sack?
正解：B
解説：
This situation can be modeled using a linear relationship because each sack has the same weight.
We are given:
After 3sacks are removed, the total weight is 116pounds.
After 6sacks are removed, the total weight is 101pounds.
From 3 sacks removed to 6 sacks removed, the number of removed sacks increases by:
6-3=3
During that time, the total weight decreases from 116pounds to 101pounds:
116-101=15
So removing 3 additional sacks decreases the total weight by 15 pounds.
Now divide to find the weight of one sack:
15/3=5
So each sack weighs:
5 " pounds "
Check:
If 3 more sacks are removed and each sack weighs 5 pounds, the total weight should decrease by:
3(5)=15
116-15=101
This matches the given information.
質問 # 78
Consider the function I(m)=41m²#490m+30, which represents the daily income, I, in dollars, of a store based on the number of months, m, since the beginning of the year. What is the difference between I(7) and I(9)?
正解：D
解説：
This is a polynomial function evaluation problem. Since I(m) represents daily income in dollars, the difference between I(7) and I(9) must also be in dollars. First evaluate I(7)=41(49)#490(7)
+30=2009#3430+30=#1391. Then evaluate I(9)=41(81)#490(9)+30=3321#4410+30=#1059. The difference is
|#1059#(#1391)|=332. Because the question asks for the difference between the two outputs, the correct unit is dollars, not months. So the difference between I(7) and I(9) is approximately $332. Therefore, the correct answer is C.
質問 # 79
The function
c(t)=-0.01t