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81. Frage
A developer has a fizzbuzz function that, when passed in a number, returns the following:
'fizz' if the number is divisible by 3.
'buzz' if the number is divisible by 5.
'fizzbuzz' if the number is divisible by both 3 and 5.
Empty string '' if the number is divisible by neither 3 nor 5.
Which two test cases properly test scenarios for the fizzbuzz function?
Antwort: A,D
Begründung:
:
First, recall the fizzbuzz rules:
If n divisible by 3 and not by 5 → return 'fizz'.
If n divisible by 5 and not by 3 → return 'buzz'.
If n divisible by both 3 and 5 → return 'fizzbuzz'.
Otherwise → return '' (empty string).
Evaluate each test:
Option A:
let res = fizzbuzz(true);
console.assert(res === '');
In JavaScript, when using arithmetic operations with true, it is coerced to the number 1. A typical implementation of fizzbuzz would treat the argument as a number and compute:
true % 3 → 1 % 3 → 1
true % 5 → 1 % 5 → 1
So true is effectively treated as 1, which is divisible by neither 3 nor 5. The function should return ''. The assertion res === '' will pass.
This test covers the scenario "neither divisible by 3 nor 5".
Option B:
let res = fizzbuzz(3);
console.assert(res === '');
3 is divisible by 3 but not by 5.
According to fizzbuzz rules, fizzbuzz(3) should return 'fizz'.
This test expects '', so it is incorrect; the assertion would fail in a correct implementation.
Option C:
let res = fizzbuzz(5);
console.assert(res === 'fizz');
5 is divisible by 5 but not by 3.
According to fizzbuzz rules, fizzbuzz(5) should return 'buzz'.
This test expects 'fizz', so it is incorrect.
Option D:
let res = fizzbuzz(15);
console.assert(res === 'fizzbuzz');
15 is divisible by both 3 and 5.
According to fizzbuzz rules, fizzbuzz(15) should return 'fizzbuzz'.
This assertion correctly matches the expected result, so it is a proper test case.
Thus, the two test cases that correctly test valid fizzbuzz behavior are:
Answe r: A, D
Study Guide / Concept Reference (no links):
Modulo operator (%) for divisibility checks
Truthy/number coercion of boolean true in arithmetic (Number(true) === 1) Designing unit tests with console.assert Typical fizzbuzz logic structure and expected outputs
82. Frage
Corrected code:
function Person() {
this.firstName = "John";
}
Person.prototype = {
job: x => "Developer"
};
const myFather = new Person();
const result = myFather.firstName + " " + myFather.job();
What is the value of result after line 10 executes?
Antwort: B
Begründung:
The verified answer is A.
This constructor function runs when new Person() is called:
function Person() {
this.firstName = "John";
}
So this line:
const myFather = new Person();
creates an object like this:
{
firstName: "John"
}
Then the prototype is assigned a method named job:
Person.prototype = {
job: x => "Developer"
};
Because myFather is created from Person, it can access properties and methods from Person.prototype.
So:
myFather.firstName
returns:
"John"
And:
myFather.job()
returns:
"Developer"
Therefore:
const result = myFather.firstName + " " + myFather.job();
becomes:
const result = "John" + " " + "Developer";
Final value:
"John Developer"
Option B is incorrect because job() returns "Developer", not undefined.
Option C is incorrect because job exists on Person.prototype, so it is callable.
Option D is incorrect because firstName is assigned inside the constructor.
Therefore, the verified answer is A.
83. Frage
A developer needs to debug a Node.js web server because a runtime error keeps occurring at one of the endpoints.
The developer wants to test the endpoint on a local machine and make the request against a local server to look at the behavior. In the source code, the server.js file will start the server. The developer wants to debug the Node.js server only using the terminal.
Which command can the developer use to open the CLI debugger in their current terminal window?
(With corrected typing errors: node_inspect → node inspect, node_start_inspect → node start inspect.)
Antwort: A
Begründung:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
Node.js includes a built-in command-line (CLI) debugger. To use it directly in the terminal, the standard command is:
node inspect server.js
This:
Starts server.js under the Node.js inspector.
Opens the CLI debugger right in the terminal window where you ran the command.
Lets you interactively:
Step through code
Set breakpoints
Inspect variables
Continue execution, etc.
Why B is correct:
Option B (corrected to node inspect server.js) is exactly the standard Node.js command to run a script under the CLI debugger in the current terminal.
It does not rely on any external GUI tools.
You stay entirely in the terminal to debug.
Why the other options are incorrect:
A . node start inspect server.js
There is no start subcommand like this in standard Node.js CLI.
This is not a valid Node.js debugging command.
C . node server.js --inspect
This starts Node.js with the Inspector protocol enabled and is typically used to connect external tools like Chrome DevTools or VS Code.
It does not open the CLI debugger in the current terminal. Instead, it opens a debugging port that other tools attach to.
The question specifically says "only using the terminal" and "open the CLI debugger in their current terminal window", which points to node inspect, not --inspect.
D . node -i server.js
-i starts Node in interactive REPL mode, optionally after running a script.
This is for an interactive shell, not the Node debugger.
It does not provide breakpoint/step/next/continue debugging features like the CLI debugger.
Therefore, the only option that opens the Node.js CLI debugger in the current terminal is:
JavaScript / Node.js knowledge / Study Guide references (concept names only, no links):
Node.js CLI debugger: node inspect <script>
Node.js inspector protocol: node --inspect
Difference between CLI debugger and DevTools-based debugging
Node.js command-line options and subcommands
________________________________________
84. Frage
Universal Containers (UC) just launched a new landing page, but users complain that the website is slow. A developer found some functions that might cause this problem. To verify this, the developer decides to execute everything and log the time each of these three suspicious functions consumes.
01 console.time('Performance');
02
03 maybeAHeavyFunction();
04
05 thisCouldTakeTooLong();
06
07 orMaybeThisOne();
08
09 console.endTime('Performance');
Which function can the developer use to obtain the time spent by every one of the three functions?
Antwort: D
Begründung:
JavaScript consoles (browsers and Node) provide timing utilities:
console.time(label) - starts a timer with the given label.
console.timeEnd(label) - stops the timer and logs the total elapsed time.
console.timeLog(label) - logs the current elapsed time without stopping the timer.
To measure the time taken by each function separately while still using a single overall timer, you can log intermediate times:
console.time('Performance');
maybeAHeavyFunction();
console.timeLog('Performance', 'after maybeAHeavyFunction');
thisCouldTakeTooLong();
console.timeLog('Performance', 'after thisCouldTakeTooLong');
orMaybeThisOne();
console.timeLog('Performance', 'after orMaybeThisOne');
console.timeEnd('Performance');
Each console.timeLog('Performance') call prints the elapsed time since console.time('Performance') was started, so you can infer how long each function took.
Note: console.endTime in the original snippet is incorrect; the real method is console.timeEnd.
Why other options are incorrect:
B . console.trace()
Prints a stack trace, not timing information.
C . console.timeStamp()
Used with browser performance tools; it does not directly show elapsed times like timeLog or timeEnd.
D . console.getTime()
Not a standard console method.
Thus, the function that can be used to obtain timing between calls is:
Answe r: A
Study Guide Concepts:
console.time, console.timeLog, console.timeEnd
Measuring performance and intermediate timings
Standard console debugging API methods
85. Frage
Given the JavaScript below:
Which code should replace the placeholder comment on line 06 to hide accounts that do not match the search string?
Antwort: D
86. Frage
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