Free PDF Quiz 1z0-071 - High Pass-Rate Valid Oracle Database SQL Test Sample

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Oracle 1z0-071 Exam Syllabus Topics:

Section	Weight	Objectives
Relational Database Concepts	10%	- Relationship between database and SQL - Theoretical and physical aspects of relational databases - ERD and SQL statement mapping
Using Subqueries to Solve Queries		- Correlated subqueries for update/delete - Single-row and multi-row subqueries
Controlling User Access		- Roles, granting and revoking privileges - System and object privileges
Working with Time Zones and Date/Time Data		- Time zone conversion functions - TIMESTAMP, INTERVAL data types
Managing Indexes, Synonyms and Sequences		- Create and use synonyms - Create and maintain indexes - Create and use sequences
Restricting and Sorting Data	15%	- Substitution variables, DEFINE and VERIFY commands - WHERE clause and filtering conditions - Operator precedence - ORDER BY clause and sorting rules
Managing Views		- Updatable and read-only views - Create, modify and drop views
Using Single-Row Functions to Customize Output	20%	- Character, number, and date functions - Nested functions usage
Manipulating Data and Managing Transactions		- Multi-table inserts - INSERT, UPDATE, DELETE, MERGE statements - Transaction control: COMMIT, ROLLBACK, SAVEPOINT
Retrieving Data Using SQL SELECT Statement	20%	- Column aliases, concatenation, literals and DISTINCT - SELECT statement syntax and usage - Arithmetic operations and NULL handling
Using SET Operators		- Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators
Using Data Dictionary Views		- Retrieve metadata and object information
Aggregating Data Using Group Functions	10%	- SUM, AVG, COUNT, MAX, MIN functions - GROUP BY and HAVING clauses - Handling NULLs in group functions
Managing Tables and Constraints		- Constraints: primary key, foreign key, unique, check, not null - Data types, creating/altering/dropping tables - Temporary and external tables
Displaying Data from Multiple Tables	15%	- Cartesian products - Self-joins and outer joins - Equijoins and non-equijoins
Conversion Functions and Conditional Expressions	10%	- Implicit and explicit data type conversion - TO_CHAR, TO_NUMBER, TO_DATE functions - NVL, NULLIF, COALESCE and CASE expressions

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Oracle Database SQL Sample Questions (Q173-Q178):

NEW QUESTION # 173
Examine these statements:

Which two are true? (Choose two.)

A. The MGR column in the DEPT table will not be able to contain NULL values.
B. All three statements execute successfully in the order shown.
C. The CREATE TABLE EMP statement must precede the CREATE TABLE DEPT statement for all three statements to execute successfully.
D. The DEPTNO column in the EMP table will be able to contain NULL values.
E. Both foreign key constraint definitions must be removed from the CREATE TABLE statements, and be added with ALTER TABLE statements once both tables are created, for the two CREATE TABLE statements to execute successfully in the order shown.
F. The DEPT_FKEY constraint definition must be removed from the CREATE TABLE DEPT statement, and be added with an ALTER TABLE statement once both tables are created, for the two CREATE statements to execute successfully in the order shown.
TABLE

Answer: D,E

NEW QUESTION # 174
Examine the business rule:
Each student can work on multiple projects and each project can have multiple students.
You need to design an Entity Relationship Model (ERD) for optimal data storage and allow for generating reports in this format:
STUDENT_ID FIRST_NAME LAST_NAME PROJECT_ID PROJECT_NAME PROJECT_TASK
Which two statements are true in this scenario? (Choose two.)

A. PROJECT_IDmust be the primary key in the PROJECTSentity and foreign key in the STUDENTSentity.
B. STUDENT_IDmust be the primary key in the STUDENTSentity and foreign key in the PROJECTSentity.
C. The ERD must have a 1:M relationship between the STUDENTSand PROJECTSentities.
D. The ERD must have a M:M relationship between the STUDENTSand PROJECTSentities that must be resolved into 1:M relationships.
E. An associative table must be created with a composite key of STUDENT_ID and PROJECT_ID, which is the foreign key linked to the STUDENTS and PROJECTS entities.

Answer: D,E

Explanation:
Explanation/Reference:
References:
http://www.oracle.com/technetwork/issue-archive/2011/11-nov/o61sql-512018.html

NEW QUESTION # 175
View the Exhibit and examine the structure of the ORDER_ITEMS and ORDERS tables.

You are asked to retrieve the ORDER_ID, product_ID, and total price (UNIT_PRICE multiplied by QUANTITY), where the total price is greater than 50,000.
You executed the following SQL statement:
SELECT prder_id, product_id, unit_price*quantity "Total Price"
FROM order_items
WHERE unit_price*quantity > 50000
NATURAL JOIN orders;
Which statement is true regarding the execution of the statement?

A. The statement would execute and provide the desired result.
B. The statement would not execute because the ON keyword is missing in the NATURAL JOIN clause.
C. The statement would not execute because the WHERE clause is before the NATURAL JOIN clause.
D. The statement would not execute because the USING keyword is missing in the NATURAL JOIN clause.

Answer: C

NEW QUESTION # 176
The BOOKS_TRANSACTIONS table exists in your schema in this database.
You execute this SQL statement when connected to your schema in your database instance.
SQL> SELECT * FROM books_transactions ORDER BY 3;
What is the result?

A. Only the three rows with the lowest values in the key column are displayed in the order that they are stored.
B. The first three rows in the table are displayed in the order that they are stored.
C. The execution fails unless the numeral 3 in the ORDER BY clause is replaced by a column name.
D. All table rows are displayed sorted in ascending order of the values in the third column.

Answer: D

NEW QUESTION # 177
Examine the description or the BOOKS_TRANSACTIONS table:

FOR customers whose income level has a value, you want to display the first name and due amount as 5% of their credit limit. Customers whose due amount is null should not be displayed.
Which query should be used?

A. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level <> NULL
AND due_amount <> NULL;
B. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level IS NOT NULL
AND due_amount IS NOT NULL;
C. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level !=NULL
AND due_amount !=NULL;
D. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level !=NULL
AND cust credit_level !=NULL;
E. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust_income_level IS NOT NULL
AND cust_credit_limit IS NOT NULL;

Answer: E

NEW QUESTION # 178
......

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