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Oracle 1z1-071 exam, also known as the Oracle Database SQL exam, is a certification test that validates the knowledge and skills of individuals in using SQL to interact with Oracle Database. Passing 1z0-071 Exam demonstrates that an individual has a strong foundation in SQL and is capable of performing basic database operations.

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1z0-071 Test Review | 1z0-071 Examcollection Questions Answers

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To prepare for this certification exam, candidates should have a good understanding of SQL programming concepts, such as data types, operators, functions, and control structures. They should also be familiar with basic database concepts, such as normalization, indexing, and transaction management. 1z0-071 exam consists of 73 multiple-choice questions, which need to be completed within 100 minutes. The passing score for 1z0-071 Exam is 63%. Upon successful completion of the exam, candidates will be awarded the Oracle Database SQL certification, which is a valuable credential for anyone seeking to advance their career in database management.

Oracle Database SQL Sample Questions (Q380-Q385):

NEW QUESTION # 380
View the Exhibit and examine the structure of the PRODUCT_INFORMATIONand INVENTORIEStables.

You have a requirement from the supplies department to give a list containing PRODUCT_ID, SUPPLIER_ID,and QUANTITY_ON_HANDfor all the products wherein QUANTITY_ON_HANDis less than five.
Which two SQL statements can accomplish the task? (Choose two.)
SELECT i.product_id, i.quantity_on_hand, pi.supplier_id

A. FROM product_information
NATURAL JOIN inventories AND quantity_on_hand < 5;
SELECT i.product_id, i.quantity_on_hand, pi.supplier_id
B. FROM product_information pi JOIN inventories i
ON (pi.product_id=i.product_id) AND quantity_on_hand < 5;
SELECT i.product_id, i.quantity_on_hand, pi.supplier_id
C. FROM product_information pi JOIN inventories i
ON (pi.product_id=i.product_id)
USING (product_id) AND quantity_on_hand < 5;
D. FROM product_information pi JOIN inventories i
ON (pi.product_id=i.product_id)
WHERE quantity_on_hand < 5;
SELECT product_id, quantity_on_hand, supplier_id

Answer: B,D

NEW QUESTION # 381
You are designing the structure of a table in which two columns have the specifications:
COMPONENT_ID- must be able to contain a maximum of 12 alphanumeric characters and uniquely identify the row EXECUTION_DATETIME- contains Century, Year, Month, Day, Hour, Minute, Second to the maximum precision and is used for calculations and comparisons between components.
Which two options define the data types that satisfy these requirements most efficiently?

A. The EXECUTION_DATETIME must be of DATE data type.
B. The COMPONENT_IDcolumn must be of CHAR data type.
C. The COMPONENT_IDmust be of VARCHAR2 data type.
D. The EXECUTION_DATETIME must be of TIMESTAMP data type.
E. The COMPONENT_IDmust be of ROWID data type.
F. The EXECUTION_DATETIME must be of INTERVAL DAY TO SECOND data type.

Answer: A,B

NEW QUESTION # 382
Which two are true about self joins?

A. They are always equijoins.
B. They require the NOT EXISTS operator in the join condition.
C. They require the EXISTS opnrator in the join condition.
D. They require table aliases.
E. They can use INNER JOIN and LEFT JOIN.
F. They have no join condition.

Answer: D,E

NEW QUESTION # 383
You want to display the date for the first Monday of the next month and issue the following command:
SQL>SELECT TO_CHAR(NEXT_DAY(LAST_DAY(SYSDATE),'MON'), 'dd "is the first Monday for"fmmonth rrrr') FROM DUAL;
What is the outcome?

A. It generates an error because fm and double quotation marks should not be used in the format string.
B. It executes successfully and returns the correct result.
C. It generates an error because rrrr should be replaced by rr in the format string.
D. It executes successfully but does not return the correct result.
E. It generates an error because TO_CHAR should be replaced with TO_DATE.

Answer: B

Explanation:
NEXT_DAY(date, 'char'): Finds the date of the next specified day of the week ('char') following date. The value of char may be a number representing a day or a character string.
LAST_DAY(date): Finds the date of the last day of the month that contains date The second innermost function is evaluated next. TO_CHAR('28-OCT-2009', 'fmMonth') converts the given date based on the Month format mask and returns the character string October. The fm modifier trims trailing blank spaces from the name of the month.

NEW QUESTION # 384
View the Exhibit and examine the description of the EMPLOYEEStable.

You want to calculate the total remuneration for each employee. Total remuneration is the sum of the annual salary and the percentage commission earned for a year. Only a few employees earn commission.
Which SQL statement would you execute to get the desired output?
SELECT first_name, salary, salary*12+(salary*NVL2 (commission_pct,

A. FROM EMPLOYEES;
B. FROM EMPLOYEES;
SELECT first_name, salary, salary*12 + NVL(salary,0)*commission_pct, "Total"
C. FROM EMPLOYEES;
SELECT first_name, salary (salary + NVL (commission_pct, 0)*salary)*12 "Total"
D. salary,salary+commission_pct))"Total"
FROM EMPLOYEES;
SELECT first_name, salary, salary*12+salary*commission_pct "Total"

Answer: D

NEW QUESTION # 385
......

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