真實的Applied-Probability-and-Statistics考試資訊|高通過率的考試材料|高效的Applied-Probability-and-Statistics：Applied Probability and Statistics (FZO1 C955)

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WGU Applied-Probability-and-Statistics Exam Syllabus Topics:

SectionObjectives
Probability Theory- Fundamental Probability Concepts
  • 1. Basic probability rules
    • 2. Conditional probability
      • 3. Independent vs dependent events
        - Probability Distributions
        • 1. Binomial distribution basics
          • 2. Normal distribution
            Descriptive Statistics- Single Variable Data Analysis
            • 1. Measures of central tendency (mean, median, mode)
              • 2. Data visualization (histograms, box plots)
                • 3. Measures of dispersion (variance, standard deviation, range)
                  - Two Variable Data Analysis
                  • 1. Outliers and relationships
                    • 2. Correlation
                      • 3. Scatter plots interpretation
                        Regression and Modeling- Linear Relationships
                        • 1. Slope and intercept interpretation
                          • 2. Simple linear regression
                            Statistical Inference- Hypothesis Testing (Introductory Level)
                            • 1. Null vs alternative hypothesis
                              • 2. p-values interpretation
                                - Estimation and Confidence Intervals
                                • 1. Point estimates
                                  • 2. Confidence interval interpretation

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                                    最新的 Courses and Certificates Applied-Probability-and-Statistics 免費考試真題 (Q55-Q60):

                                    問題 #55
                                    Dataset: 5, 7, 7, 10. Standard deviation?

                                    答案：D

                                    解題說明：
                                    The standard deviation measures the typical distance of data values from the mean. For the dataset 5, 7, 7, 10, the mean is (5 + 7 + 7 + 10) ÷ 4 = 29 ÷ 4 = 7.25. The deviations from the mean are #2.25, #0.25, #0.25, and
                                    2.75. Squaring these deviations gives 5.0625, 0.0625, 0.0625, and 7.5625. The sum of squared deviations is
                                    12.75. If treated as a sample, the variance is 12.75 ÷ 3 = 4.25, and the sample standard deviation is #4.25 #
                                    2.06. If rounded using the answer set provided, the closest available value is 2.16. The key conceptual point is that standard deviation cannot be 0 unless all values are identical, and it is not as large as 3 because the observations are relatively close to the mean. Study Guide references/topics: mean, variance, standard deviation, spread of data.


                                    問題 #56
                                    In a city's public transportation system, the distribution of commuters by mode of transport is as follows: 40% use buses, 25% use trains, 20% use bicycles, 10% walk, and 5% use other means of transportation.
                                    What is the probability that a randomly selected commuter uses either a bus or a train?

                                    答案：B

                                    解題說明：
                                    The event is that a randomly selected commuter uses either a bus or a train. These categories are mutually exclusive because one commuter is classified under one primary transportation mode in the given distribution.
                                    For mutually exclusive events, the probability of "A or B" is found by adding the individual probabilities. The probability of using a bus is 40%, and the probability of using a train is 25%. Therefore, P(bus or train) = 40%
                                    + 25% = 65%. The bicycle, walking, and other transportation categories are not included because the question restricts the event to bus or train only. Option B, 45%, would incorrectly combine bus with the 5% "other" category or otherwise omit part of the train group. Option C is too low, and option A is unrelated to the stated categories. References/topics from the Study Guide: probability, mutually exclusive events, addition rule, percentage distributions.


                                    問題 #57
                                    Probability of heads on 3 coin flips exactly twice?

                                    答案：C

                                    解題說明：
                                    This is a binomial probability problem because there is a fixed number of independent trials, each trial has two outcomes, and the probability of success is constant. Let success be flipping heads. There are 3 coin flips, and the probability of heads on each flip is 1/2. The event "exactly two heads" can occur in three ordered ways: HHT, HTH, and THH. Each sequence has probability (1/2)(1/2)(1/2) = 1/8. Since there are three favorable sequences, the total probability is 3 × 1/8 = 3/8. Equivalently, use the binomial formula: C(3,2)(1/2)