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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Creating Other Schema Objects | 10% | - Create synonyms for database objects - Create, maintain, and use sequences - Create and maintain indexes - Create, modify, and retrieve data from a view |
| Topic 2: Manipulating Data | 14% | - Control transactions - Describe each data manipulation language (DML) statement - Insert rows into a table - Update rows in a table - Delete rows from a table |
| Topic 3: Retrieving Data Using the SQL SELECT Statement | 5% | - List the capabilities of SQL SELECT statements - Execute a basic SELECT statement - Differentiate between SQL statements and SQL*Plus commands |
| Topic 4: Restricting and Sorting Data | 6% | - Use ampersand substitution to restrict and sort output at runtime - Limit the rows that are retrieved by a query - Sort the rows that are retrieved by a query - Use DEFINE and UNDEFINE commands |
| Topic 5: Using Subqueries to Solve Queries | 15% | - Write single-row and multi-row subqueries - Define subqueries - Describe the types of problems that subqueries can solve - List the types of subqueries |
| Topic 6: Using Conversion Functions and Conditional Expressions | 10% | - Apply the NVL, NULLIF, and COALESCE functions to data - Use the TO_CHAR, TO_NUMBER, and TO_DATE conversion functions - Describe implicit and explicit data type conversion - Use conditional IF THEN ELSE logic in a SELECT statement |
| Topic 7: Controlling User Access | 5% | - Distinguish between granting privileges and roles - Differentiate system privileges from object privileges - Grant privileges on tables and on a view |
| Topic 8: Working with Oracle Database SQL | 8% | - Create a container database - Start up and shut down a database - Explain the installation of Oracle Database software - Describe the Oracle Database architecture |
| Topic 9: Reporting Aggregated Data Using Group Functions | 15% | - Include or exclude grouped rows by using the HAVING clause - Describe the use of group functions - Group data by using the GROUP BY clause - Identify the available group functions |
| Topic 10: Using Set Operators | 5% | - Describe set operators - Describe the order of precedence when the set operators are used - Use a set operator to combine multiple queries into a single query |
| Topic 11: Using Single-Row Functions to Customize Output | 10% | - Manipulate numbers with the ROUND, TRUNC, and MOD functions - Describe the differences between single-row and multiple-row functions - Manipulate dates with the date functions - Manipulate strings with character function in the SELECT and WHERE clauses - Perform arithmetic with date data |
| Topic 12: Displaying Data from Multiple Tables Using Joins | 15% | - Cross join tables - View data that does not meet a join condition by using outer joins - Join a table to itself by using a self-join - Write SELECT statements to access data from more than one table using equijoins and non-equijoins |
| Topic 13: Using DDL Statements to Create and Manage Tables | 14% | - Drop, rename, and truncate tables - Describe the data types that are available for columns - Categorize the main database objects - Alter table definitions - Create a simple table - Review the table structure |
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NEW QUESTION # 103
which is true about the round,truncate and mod functions>?
Answer: A
Explanation:
Both ROUND and TRUNC functions can be applied to numbers, and MOD is a function that returns the remainder of a division. The ROUND function rounds a number to a specified number of decimal places, which can be positive, zero, or negative. The TRUNC function truncates a number to a specified number of decimal places.
ROUND(MOD(25,3),-1) rounds the result of MOD(25,3), which is 1, to tens place, which results in 0. TRUNC(MOD(25,3),-1) truncates the result of MOD(25,3), which is 1, to tens place, which also results in 0.
Both are valid, but in this specific case, they give the same result because the remainder (1) when rounded or truncated to tens place (-1) will be 0.
NEW QUESTION # 104
Examine the description of the CUSTONERS table:
CUSTNO is the PRIMARY KEY.
You must determine if any customers' details have been entered more than once using a different CUSTNO, by listing all duplicate names.
Which two methods can you use to get the required result?
Answer: C,D
Explanation:
To find duplicate customer details entered under different CUSTNO values, one would typically use methods that compare records within the same table:
C . Subquery: A subquery can be used to compare customer details in the CUSTOMERS table and identify duplicates. This subquery can look for matches in the customer details while having different CUSTNO.
E . Self Join: A self join can also be used for this purpose. This involves joining the CUSTOMERS table to itself on the columns containing customer details to identify rows that have the same information but different CUSTNO.
Reference:
Oracle Database SQL Language Reference 12c, particularly the sections on self joins and subqueries, as these can be utilized to find duplicate rows based on specified criteria.
NEW QUESTION # 105
Examine the structure of the PROGRAMStable:
Which two SQL statements would execute successfully?
SELECT NVL(ADD_MONTHS(END_DATE,1)SYSDATE)
Answer: B,C
NEW QUESTION # 106
Which two are SQL features?
Answer: B,E
NEW QUESTION # 107
You must create a table for a banking application. (Choose the best answer.) One of the columns in the table has these requirements:
1: A column to store the duration of a short team loan
2: The data should be stored in a format supporting DATE arithmetic with DATE datatypes without using conversion functions.
3: The maximum loan period is 30 days.
4: Interest must be calculated based on the number of days for which the loan remains unpaid.
Which data type would you use?
Answer: D
NEW QUESTION # 108
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