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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I |
| Exam Number: | JS-Dev-101 |
| Available Languages: | English |
| Related Certifications: | Salesforce Certified JavaScript Developer I Lightning Web Components Specialist Superbadge |
| Exam Duration: | 105 minutes |
| Passing Score: | 65% |
| Real Exam Qty: | 60 (plus up to 5 unscored pilot questions) |
| Exam Format: | Multiple Select, Multiple Choice |
| Certificate Validity Period: | Lifetime (No renewal required) |
| Exam Price: | $200 USD |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online (Proctored) |
| Pre Condition: | Completion of the Lightning Web Components Specialist Superbadge is required to earn the full credential, though it can be completed before or after the exam. |
| Official Syllabus URL: | https://trailhead.salesforce.com/en/credentials/javascriptdeveloperi |
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The web-based JS-Dev-101 practice exam can be taken via the internet from any browser like Firefox, Safari, Opera, MS Edge, Internet Explorer, and Chrome. You donโt need to install any excessive plugins and software to take this Salesforce JS-Dev-101 Practice Test. Windows, Mac, iOS, Android, and Linux support this Salesforce Certified JavaScript Developer - Multiple Choice (JS-Dev-101) practice exam.
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NEW QUESTION # 131
Given the code below:
01 function Person() {
02 this.firstName = 'John';
03 }
04
05 Person.proto = {
06 job: x => 'Developer'
07 });
08
09 const myFather = new Person();
10 const result = myFather.firstName + ' ' + myFather.job();
What is the value of result when line 10 executes?
Answer: C
Explanation:
Person.proto is being set, but JavaScript uses Person.prototype for the prototype chain, not Person.proto.
Therefore, job is not on Person.prototype, and instances of Person do not have job via prototype.
myFather is created with new Person(), so:
myFather.firstName is 'John'.
myFather.job is undefined.
Attempting to call myFather.job() results in:
TypeError: myFather.job is not a function
So option A is correct.
NEW QUESTION # 132
A developer wants to use a module named universalContainerslib and then call functions from it. How should a developer import every function from the module and then call the functions foo and bar?
Answer: D
Explanation:
import * as lib from '...' imports all named exports from the module into the namespace object lib.
You then call:
lib.foo();
lib.bar();
Option D correctly imports only foo and bar, not every function. The question explicitly says "import every function... and then call foo and bar", so A best matches.
Options B and C are invalid syntax or reference the wrong identifier.
________________________________________
NEW QUESTION # 133
Which statement accurately describes an aspect of promises?
Answer: B
Explanation:
Evaluate each option:
A . Arguments for .then() are optional.
This is correct.
.then() has the signature:
promise.then(onFulfilled?, onRejected?)
Both arguments (onFulfilled and onRejected) are optional.
If a callback is not supplied, JavaScript provides a default pass-through handler.
B . .then() cannot be added after a catch.
Incorrect.
Promises support chaining in any order:
promise
.catch(...)
.then(...);
After a catch, the chain continues normally.
C . .then() manipulates and returns the original promise.
Incorrect.
.then() always returns a new promise, not the original one.
This is fundamental to promise chaining behavior.
D . Returning values in .then() is not necessary.
Incorrect.
If you want the next .then() in the chain to receive a value, the current .then() must explicitly return it:
.then(value => {
return value * 2; // passes to next .then()
})
If nothing is returned, the next .then() receives undefined.
Why A is correct
It is the only statement that accurately describes built-in Promise behavior:
.then() accepts optional arguments.
JavaScript Knowledge Reference (text-only)
.then(onFulfilled?, onRejected?) accepts optional handlers.
Promise chaining creates new promises for each .then().
catch() can be followed by additional .then() calls.
Returning inside .then() passes values to the next step in the chain.
NEW QUESTION # 134
Refer to the code below:
01 const objBook = {
02 title: 'JavaScript',
03 };
04 Object.preventExtensions(objBook);
05 const newObjBook = objBook;
06 newObjBook.author = 'Robert';
What are the values of objBook and newObjBook respectively?
Answer: B
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Object.preventExtensions(obj) This built-in JavaScript method marks an object so that no new properties can be added to it.
Existing properties can still be read and updated, but adding new ones is disallowed.
const newObjBook = objBook;
Both variables reference the same object in memory. JavaScript objects are assigned by reference, not copied.
newObjBook.author = "Robert";
Because the object has been marked as non-extensible, JavaScript will not allow new properties to be added.
The behavior depends on mode:
In non-strict mode: the assignment silently fails and does nothing.
In strict mode: this would throw a TypeError.
Since nothing indicates strict mode, this is non-strict behavior, making the assignment fail silently.
Therefore, the object remains:
{ title: "JavaScript" }
Both objBook and newObjBook point to the same unchanged object.
This matches option A.
________________________________________
JavaScript knowledge references (text-only)
Object.preventExtensions() prevents adding new properties.
Assigning an object to another variable copies the reference, not the object.
Adding a property to a non-extensible object silently fails in non-strict mode.
NEW QUESTION # 135
Universal Containers (UC) just launched a new landing page, but users complain that the website is slow. A developer found some functions that might cause this problem. To verify this, the developer decides to execute everything and log the time each of these three suspicious functions consumes.
01 console.time('Performance');
02
03 maybeAHeavyFunction();
04
05 thisCouldTakeTooLong();
06
07 orMaybeThisOne();
08
09 console.endTime('Performance');
Which function can the developer use to obtain the time spent by every one of the three functions?
Answer: C
Explanation:
JavaScript consoles (browsers and Node) provide timing utilities:
console.time(label) - starts a timer with the given label.
console.timeEnd(label) - stops the timer and logs the total elapsed time.
console.timeLog(label) - logs the current elapsed time without stopping the timer.
To measure the time taken by each function separately while still using a single overall timer, you can log intermediate times:
console.time('Performance');
maybeAHeavyFunction();
console.timeLog('Performance', 'after maybeAHeavyFunction');
thisCouldTakeTooLong();
console.timeLog('Performance', 'after thisCouldTakeTooLong');
orMaybeThisOne();
console.timeLog('Performance', 'after orMaybeThisOne');
console.timeEnd('Performance');
Each console.timeLog('Performance') call prints the elapsed time since console.time('Performance') was started, so you can infer how long each function took.
Note: console.endTime in the original snippet is incorrect; the real method is console.timeEnd.
Why other options are incorrect:
B . console.trace()
Prints a stack trace, not timing information.
C . console.timeStamp()
Used with browser performance tools; it does not directly show elapsed times like timeLog or timeEnd.
D . console.getTime()
Not a standard console method.
Thus, the function that can be used to obtain timing between calls is:
Answe r: A
Study Guide Concepts:
console.time, console.timeLog, console.timeEnd
Measuring performance and intermediate timings
Standard console debugging API methods
NEW QUESTION # 136
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