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NEW QUESTION # 20
A penetration tester completed a vulnerability scan against a web server and identified a single but severe vulnerability.
Which of the following is the BEST way to ensure this is a true positive?
Answer: D
NEW QUESTION # 21
During a penetration test, the tester gains full access to the application's source code. The application repository includes thousands of code files. Given that the assessment timeline is very short, which of the following approaches would allow the tester to identify hard-coded credentials most effectively?
Answer: C
Explanation:
TruffleHog is a tool specifically designed to search through git repositories for high-entropy strings and secrets, including hard-coded credentials. This automated tool can quickly scan through thousands of code files and identify sensitive information, making it an ideal choice when time is limited.
NEW QUESTION # 22
A penetration tester obtains password dumps associated with the target and identifies strict lockout policies. The tester does not want to lock out accounts when attempting access. Which of the following techniques should the tester use?
Answer: D
Explanation:
Credential stuffing uses known username-password pairs (often from previous breaches) and attempts to log in without guessing, reducing the risk of lockouts by limiting attempts per account.
NEW QUESTION # 23
A penetration tester creates the following Python script that can be used to enumerate information about email accounts on a target mail server:
Which of the following logic constructs would permit the script to continue despite failure?
Answer: D
Explanation:
The correct construct for handling runtime failures (for example, login failures, network timeouts, or server errors) in Python is a try/except block (option C). Wrapping potentially failing operations in a try block and handling exceptions in except allows the script to catch the exception and continue execution (log the error, skip the target, retry, etc.) rather than crashing.
Why C is correct:
* try/except is the Python mechanism to handle exceptions raised during execution. For network/email operations (IMAP login/select), IMAP libraries raise exceptions on failure - try/except catches these and enables recovery logic.
* Example corrected snippet:
import imaplib, sys
def enumerate_inbox(server, port, user, passwd):
try:
mail = imaplib.IMAP4(server, port)
mail.login(user, passwd)
status, messages = mail.select( " inbox " )
print(f " Total Emails: {int(messages[0])} " )
except imaplib.IMAP4.error as e:
print(f " IMAP error for {user}: {e} " )
# continue to next account or retry
except Exception as e:
print(f " Unexpected error for {user}: {e} " )
finally:
try:
mail.logout()
except:
pass
Why the other options are not the best fit:
* A. do/while loop: Python has no native do/while; loops alone won't catch exceptions - they may repeat the crash.
* B. iterator: Iterators control iteration over collections, not exception handling.
* D. if/else conditional: Conditionals can test return values but cannot handle exceptions thrown by library calls; they are not sufficient to prevent the script from aborting when an exception is raised.
CompTIA PT0-003 Mapping:
* Domain 4.0 Tools and Code Analysis - basic defensive programming and error handling when writing or reviewing scripts used in engagements (use exception handling to make enumeration tools robust and predictable).
NEW QUESTION # 24
There is a low-level shell on a system, and a penetration tester has discovered a service with system-level privileges that is available in the following directory structure:
objectpath\imagepath=C:\Program Files\New Folder\bin\cutepanda.exe
Which of the following is the most likely attack the tester should perform on the host?
Answer: A
Explanation:
The service path contains spaces and is not enclosed in quotes, which allows the system to interpret and execute unintended binaries placed in higher-priority paths. This enables privilege escalation by placing a malicious executable in a location that will be executed with system-level privileges.
NEW QUESTION # 25
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