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| Section | Objectives |
|---|---|
| Topic 1: Functions and Graphs | - Function Concepts
|
| Topic 2: Exponential and Logarithmic Concepts | - Exponential Functions
|
| Topic 3: Foundations of Algebra | - Algebraic Expressions
|
| Topic 4: Linear Functions and Systems | - Systems of Equations
|
| Topic 5: Polynomial and Rational Expressions | - Polynomials
|
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NEW QUESTION # 86
The graph shows the daily practice duration for a musician, where the number of days since the beginning of the month is along the horizontal axis and the number of minutes practiced per day is along the vertical axis.
What was the practice duration for day 9, based on the graph?
Answer: D
Explanation:
This question asks us to read and interpret a value from a graph.
The horizontal axis represents:
" Days since the beginning of the month "
The vertical axis represents:
" Practice duration in minutes "
We need to find the practice duration for:
" day " 9
To do this, locate 9on the horizontal axis, move upward to the blue graph, and then read the corresponding value on the vertical axis.
From the graph, the point at day 9is approximately:
127
So the musician practiced for:
127 " minutes "
NEW QUESTION # 87
The function d(x)=14+65xrepresents the distance, in meters, from a tower to an object at time x, in seconds.
What is the value of d(1.5)?
Answer: C
Explanation:
We are given the function:
d(x)=14+65x
This is a linear function because it has the form:
d(x)=mx+b
where 65is the rate of change and 14is the starting value.
We need to find:
d(1.5)
That means substitute x=1.5into the function:
d(1.5)=14+65(1.5)
Now multiply:
65(1.5)=97.5
Then add:
d(1.5)=14+97.5
d(1.5)=111.5
So the distance from the tower to the object at 1.5seconds is:
111.5 " meters "
NEW QUESTION # 88
The weight of a radioactive sample is given by the function
W(x)=740× # 0.87 #