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WGU Applied-Probability-and-Statistics Exam Syllabus Topics:

SectionWeightObjectives
Descriptive Statistics25%- Measures of spread: range, IQR, variance, standard deviation
- Graphical displays: histograms, boxplots, scatterplots
- Types of data: categorical, discrete, continuous
- Measures of center: mean, median, mode
Correlation & Regression20%- Interpreting slope, intercept, and R-squared
- Simple linear regression models
- Correlation coefficient and interpretation
- Predictions and limitations of regression
Probability Concepts20%- Normal distribution and empirical rule
- Probability rules, independent and dependent events
- Conditional probability and Venn diagrams
- Discrete and continuous probability distributions
Inferential Statistics & Study Design20%- Hypothesis testing framework and interpretation
- Sampling methods and bias
- Observational studies vs experiments
- Confidence intervals for means/proportions
Basic Numeracy & Algebra15%- Arithmetic operations, fractions, decimals, percentages
- Linear equations, inequalities, graphing functions
- Exponents, roots, and basic formulas

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WGU Applied Probability and Statistics (FZO1 C955) Sample Questions (Q152-Q157):

NEW QUESTION # 152
Probability of rolling 1, 2, or 3 on die = ?

Answer: C

Explanation:
A standard six-sided die has six equally likely outcomes: 1, 2, 3, 4, 5, and 6. The event "rolling 1, 2, or 3" has three favorable outcomes: 1, 2, and 3. The probability is therefore favorable outcomes divided by total outcomes: 3/6. This fraction simplifies to 1/2. Option B, 1/3, would correspond to two favorable outcomes out of six. Option C, 1/6, is the probability of rolling one specific number only. Option D, 2/3, would require four favorable outcomes out of six. Since exactly half of the die faces are 1, 2, or 3, the correct probability is one- half. This is a direct application of theoretical probability with equally likely outcomes. Study Guide references/topics: die probability, favorable outcomes, sample space, theoretical probability.


NEW QUESTION # 153
Two independent events: P(A and B) = ?

Answer: D

Explanation:
For independent events, the probability that both events occur is the product of their individual probabilities.
The rule is P(A and B) = P(A) × P(B). Independence means that the occurrence of one event does not change the probability of the other. For example, if a coin is tossed and a die is rolled, the probability of heads and rolling a 4 is 1/2 × 1/6 = 1/12. Option B is an addition expression used in "or" problems, not "and" problems.
Option C applies to mutually exclusive events, not independent events. Option D would mean both events are certain to occur together, which is not generally true. The word "and" signals intersection, and independence allows the intersection to be calculated by multiplication. Study Guide references/topics: independent events, multiplication rule, joint probability, compound probability.


NEW QUESTION # 154
Poisson mean = 4. Probability of exactly 2 events?