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| Section | Weight | Objectives |
|---|---|---|
| Hash Functions & Data Integrity | 15% | - HMAC construction and application - Uses: integrity checks, password storage, message authentication - Algorithms: SHA-1, SHA-256, SHA-3, MD5 - Properties: collision resistance, one-way function |
| Cryptography Fundamentals | 20% | - Basic terminology: plaintext, ciphertext, algorithm, key - Historical evolution and modern applications - Core goals: confidentiality, integrity, authentication, non-repudiation |
| Key Management & Secure Protocols | 10% | - Cryptographic attacks: brute force, birthday, man-in-the-middle - Key generation, storage, exchange, and destruction - Secure protocols: TLS/SSL, IPsec, SSH, PGP |
| Implementation & Best Practices | 5% | - Common mistakes and vulnerabilities - Selecting appropriate algorithms and key sizes - Standards and compliance |
| Asymmetric Encryption & Public Key Infrastructure | 25% | - Principles: public/private key pairs - Algorithms: RSA, ECC, Diffie-Hellman - Digital signatures: purpose and process - PKI components: certificates, CAs, trust models - Certificate lifecycle: creation, validation, revocation |
| Symmetric Encryption | 25% | - Principles and operation - Block vs stream ciphers, modes of operation (ECB, CBC, OFB, CFB) - Algorithms: AES, DES, 3DES, Blowfish - Key generation, distribution, and management challenges |
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NEW QUESTION # 29
(Which encryption mode is known for supporting parallel processing?)
Answer: A
Explanation:
ECB (Electronic Codebook) mode encrypts each block independently with the same key, which makes it naturally amenable to parallel processing: multiple blocks can be encrypted or decrypted simultaneously because there is no chaining dependency between blocks. This is in contrast to CBC encryption, where each plaintext block is XORed with the previous ciphertext block, creating a dependency that prevents straightforward parallelization of encryption (though CBC decryption can be parallelized because ciphertext blocks are already known). Feedback modes like CFB and OFB generate keystream material sequentially, where each step depends on the previous state, limiting parallelism. While ECB's parallelism is an implementation advantage, it is widely discouraged for most real data because it leaks patterns-identical plaintext blocks produce identical ciphertext blocks. Modern systems prefer parallel-friendly and secure modes such as CTR or GCM, but among the listed options, the mode most known for parallel processing is ECB due to block independence. Therefore, the correct answer is Electronic Codebook (ECB).
NEW QUESTION # 30
(What is used to randomize the initial value when generating Initialization Vectors (IVs)?)
Answer: B
Explanation:
An IV (Initialization Vector) is a value used to ensure that encrypting identical plaintext under the same key produces different ciphertexts, preventing pattern leakage. In many secure designs, the IV must be unique (and often unpredictable) per encryption operation. A common way to ensure uniqueness is to incorporate a nonce-a "number used once." A nonce can be random, pseudo-random, or a counter-based value depending on the mode and security requirements. For example, CTR mode uses a nonce combined with a counter to produce unique input blocks; GCM uses a nonce/IV to ensure unique authentication and encryption behavior. The encryption key should remain stable across many operations and should not be used as the "randomizer" for IV generation; mixing key material into IV creation in an ad hoc way can create reuse or correlation issues. Plaintext and algorithm do not provide the needed uniqueness property. The nonce concept is specifically about ensuring one-time uniqueness of the starting value so that IV reuse does not repeat keystream blocks (stream modes) or reveal plaintext equality (CBC/CTR). Therefore, the correct choice is Nonce.
NEW QUESTION # 31
(Why are large prime numbers important in cryptography?)
Answer: D
Explanation:
Large prime numbers are crucial because they enable cryptosystems where certain operations are easy to perform, but reversing them is computationally hard without secret information. In RSA, security is based on the difficulty of factoring a large composite number that is the product of two large primes; multiplying primes is easy, but factoring the product is believed to be hard at sufficient sizes. In Diffie-Hellman and related systems, primes define finite groups (often modulo a large prime) where exponentiation is efficient but the discrete logarithm problem is hard. Primes also help ensure desirable group properties-such as having a large cyclic subgroup-reducing vulnerabilities from small subgroups or weak structure. The value of "large" is that it makes brute-force and known algorithmic attacks infeasible with current computing resources. Large primes do not primarily make encryption faster, nor do they make decryption easier; they are chosen to maximize security margins. While primes can be involved in encoding steps, their importance is security: they form the mathematical foundation for hardness assumptions used by major public-key algorithms. Therefore, the best answer is that they provide security in encryption algorithms.
NEW QUESTION # 32
(Which default port must be allowed by firewalls for the key exchange of the IPsec handshaking process to be successful?)
Answer: C
Explanation:
IPsec's initial key exchange is commonly performed using IKE (Internet Key Exchange), which negotiates Security Associations (SAs), authenticates peers, and establishes shared keys for ESP/AH protection. The traditional and default transport for IKEv1 and IKEv2 is UDP port 500. During negotiation, peers exchange proposals (crypto suites), perform Diffie-Hellman to derive key material, and authenticate using pre-shared keys, certificates, or EAP methods. If a firewall blocks UDP 500, the IKE negotiation cannot begin, preventing IPsec tunnels from forming. In many real deployments, NAT traversal is also used; in that case, traffic typically shifts to UDP 4500 (NAT-T) after detection of NAT, but UDP 500 is still required for the initial exchange and NAT detection in many configurations. TCP 500 is not standard for IKE. Port 443 is associated with HTTPS/TLS and some SSL VPNs, not IPsec IKE. Therefore, among the options provided, the firewall must allow UDP 500 for IPsec key exchange to succeed.
NEW QUESTION # 33
(Which type of exploit involves looking for different inputs that generate the same hash?)
Answer: B
Explanation:
A birthday attack targets hash functions by exploiting the birthday paradox: collisions (two different inputs producing the same hash output) can be found much faster than brute-forcing a specific preimage. For an n-bit hash, the expected work t o find any collision is on the order of 2