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| Section | Objectives |
|---|---|
| Topic 1: Testing of Software Quality Characteristics | - Functional suitability testing
|
| Topic 2: Reviews and Defect Management | - Static testing and review process
|
| Topic 3: Test Tools and Test Automation Support | - Tool support for test analysis and execution
|
| Topic 4: Testing Process in the Test Analyst Role | - Test planning, monitoring, and control in advanced testing contexts
|
| Topic 5: Testing Techniques for Test Analysis | - Experience-based techniques
|
>> Question CTAL-TA_V4.0 Explanations <<
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NEW QUESTION # 30
A savings bank rewards its customers with a £100 bonus when they reach the age of 21, if they have held a savings account for more than 3 years and have at least £2,000 in the account at that time.
Assume that Age is measured in whole years, Account term in whole years, and Account balance to two decimal places, i.e., pounds and pence.
The intended rule is:
IF Age = 21 AND Account term > 3 years AND Account balance > = £2000.00 THEN Pay £100 bonus You have a suite of test cases with the following values:
* TC1 Age = 21, Account term = 3 years, Account balance = £2000.00
* TC2 Age = 20, Account term = 6 years, Account balance = £500.00
* TC3 Age = 20, Account term = 2 years, Account balance = £3000.00
Which of the following test cases should you add to the suite to achieve 100% Reliable domain coverage?
Answer: D
Explanation:
The correct answer is B . Reliable domain coverage requires stronger boundary evidence than simplified domain coverage. CTAL-TA v4.0 defines ON, OFF, IN, and OUT points and states that for borders defined by < , #, > , or #, reliable domain coverage requires one ON, one OFF, one IN, and one OUT point . For an equality operator, it requires one ON point and two OFF points located on different sides of the border .
The existing tests already cover several required items. For Age = 21 , TC1 gives the ON point and TC2/TC3 give the lower-side OFF point at age 20; the missing equality-side point is age 22. For Account term > 3 , TC1 gives OFF at 3, TC2 gives IN at 6, TC3 gives OUT at 2; the missing ON point is 4. For Account balance > = £2000.00 , TC1 gives ON at £2000.00, TC3 gives IN at £3000.00, and TC2 gives OUT at
£500.00; the missing closest OFF point is £1999.99. Option B supplies all three missing items in a single test case: age 22, term 4, and balance £1999.99. Reference: CTAL-TA v4.0, Section 3.1.1 Domain Testing , Reliable domain coverage.
NEW QUESTION # 31
You are developing test cases for an application which performs complex calculations and have decided to model these calculations on a spreadsheet, to determine expected results from inputs.
Which solution to the test oracle problem BEST describes the approach you are using?
Answer: A
Explanation:
The correct answer is D . A spreadsheet model used to calculate expected results is best classified as a pseudo- oracle when it has been developed independently from the test object and is used to produce expected outcomes for comparison with the system under test. CTAL-TA v4.0 explains that a test oracle is needed to determine expected results in dynamic testing, and that the test oracle problem occurs when a cost-effective oracle is not readily available because of factors such as data-related complexity, non-determinism, probabilistic behavior, or ambiguous requirements. The syllabus identifies pseudo-oracles as independently developed systems that fulfill the same specification as the test object, including simplified versions of the test object.
Here, the application performs complex calculations, and the spreadsheet is being used as an independent calculation model to determine expected results from the same inputs. That is the classic pseudo-oracle pattern. Option A is wrong because property-based testing verifies general input/output properties rather than exact expected calculation results. Option B is wrong because metamorphic testing checks relations between source and follow-up test cases, not a full expected result from a spreadsheet. Option C is not the named CTAL-TA oracle solution being used here. Reference: CTAL-TA v4.0, Section 1.3.4 Determining Test Oracles .
NEW QUESTION # 32
The following minimized decision table shows the rules for rewarding members of a hotel's loyalty scheme who have booked a room, according to the type of room (luxury or not) and/or whether they have prepaid for breakfast (yes or no). The loyalty scheme has tiers Bronze, Silver and Gold. All combinations are feasible.
Using the checksum procedure, what do you notice about the structure of the minimized table?
Answer: C
Explanation:
The correct answer is B . In CTAL-TA v4.0 decision table testing, the checksum procedure is used to detect structural problems in a minimized decision table. A rule without any "-" condition represents one full-table combination. Each "-" multiplies that rule's checksum by the number of possible values for that condition. If the minimized-table checksum is higher than the original-table checksum, some rules overlap or additional rules exist; if it is lower, the table is incomplete; if equal, the minimization may be structurally correct.
The original full table has 3 loyalty tiers × 2 luxury-room values × 2 breakfast values = 12 feasible combinations . The minimized rules score as follows: Rule 1 G/Y/- = 2 , Rule 2 G/N/- = 2 , Rule 3 S/Y/- = 2
, Rule 4 S/-/- = 4 , Rule 5 B/-/Y = 2 , Rule 6 B/-/N = 2 . Total checksum = 2 + 2 + 2 + 4 + 2 + 2 = 14 . Since
14 > 12 , the minimized table cannot be structurally clean. The overlap is visible: Rule 3 covers Silver + Luxury + either breakfast value , while Rule 4 covers Silver + any room type + any breakfast value , so the Silver/Luxury combinations are covered twice. Option C is wrong because all condition values are represented. Option D alone is weaker than B , because the actual symptom here is overlap. Reference: CTAL- TA v4.0, Section 3.3.1 Decision Table Testing .
NEW QUESTION # 33
A simple drinks machine is described in the following state transition diagram:
How many test cases will be needed for Chow's 1-switch coverage?
Answer: D
Explanation:
The correct answer is C , because Chow's 1-switch coverage requires every valid sequence of two consecutive transitions to be covered. CTAL-TA v4.0 states that N-switch coverage applies to valid sequences of N+1 consecutive transitions , and specifically defines a 1-switch as a pair of incoming and outgoing transitions at a state.
Count the possible incoming-transition/outgoing-transition pairs at each state:
* S1 has 2 incoming transitions: clear, take drink, and 2 outgoing transitions: coffee, tea.
So, 2 × 2 = 4 1-switches.
* S2 has 4 incoming transitions: coffee, tea, dispensed from sugar, dispensed from milk, and 4 outgoing transitions: clear, sugar, milk, vend.
So, 4 × 4 = 16 1-switches.
* S3 has 1 incoming transition and 1 outgoing transition: 1 × 1 = 1 .
* S4 has 1 incoming transition and 1 outgoing transition: 1 × 1 = 1 .
* S5 has 1 incoming transition and 1 outgoing transition: 1 × 1 = 1 .
Total = 4 + 16 + 1 + 1 + 1 = 23 .
Therefore, the minimum quantity needed for full Chow's 1-switch coverage is 23 . Reference: CTAL-TA v4.
0, Section 3.2.2 State Transition Testing , N-switch coverage.
NEW QUESTION # 34
You are testing the functional correctness of an application which generates quotes for motor insurance. The amount of the quote is governed by a combination of the following factors:
* Type of Cover, can be: comprehensive, third party damage only, or third party damage + fire and theft
* Vehicle Engine Size, can be: < 1500cc, < 2000cc, < 2500cc, > =2500cc
* Driving Licence Type, can be: fully qualified, or student driver
* Vehicle Storage Type, can be: locked garage, or unlocked private place, or public place
* Time Since Last Claim, can be: < 1year, < 2yrs, < 3yrs, > =3yrs
In order to achieve full PAIRWISE coverage, how many combinations must be tested?
Answer: C
Explanation:
The correct answer is C . Pairwise coverage means that every possible pair of parameter-value pairs across any two parameters must appear in at least one test case. CTAL-TA v4.0 defines pairwise coverage as coverage where the coverage items are pairs of parameter-value pairs for any two parameters, and notes that tools are commonly used because finding a minimal set can be difficult.
Here the parameter value counts are: Type of Cover = 3 , Vehicle Engine Size = 4 , Driving Licence Type = 2
, Vehicle Storage Type = 3 , and Time Since Last Claim = 4 . The largest two-parameter interaction is between the two 4-value parameters: Vehicle Engine Size × Time Since Last Claim = 4 × 4 = 16 required pairs. Therefore, no pairwise suite can have fewer than 16 tests, because each test can cover only one specific pair between those two parameters.
A 16-test pairwise suite is achievable because the remaining 3-value, 2-value, and 3-value parameters can be distributed across those 16 rows while preserving all required two-way interactions. Option D , 288, is the full exhaustive combination count: 3 × 4 × 2 × 3 × 4 = 288 , not pairwise coverage. Option A and B are insufficient or unsupported by the pairwise lower bound. Reference: CTAL-TA v4.0, Section 3.1.2 Combinatorial Testing .
NEW QUESTION # 35
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