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| Certification Vendor: | CWNP |
|---|---|
| Exam Name: | CWNP Certified Wireless Network Administrator (CWNA) |
| Exam Number: | CWNA-109 |
| Exam Format: | Multiple Select, Multiple Choice, Drag-and-Drop |
| Certificate Validity Period: | 3 years |
| Passing Score: | 70% |
| Exam Price: | USD 250 |
| Related Certifications: | Certified Wireless Network Administrator (CWNA) |
| Real Exam Qty: | 60 |
| Available Languages: | English |
| Exam Duration: | 90 minutes |
| Sample Questions: | CWNP CWNA-109 Sample Questions |
| Exam Way: | Online (Proctored) or Authorized Testing Center |
| Pre Condition: | No formal prerequisites, but foundational networking knowledge recommended |
| Official Syllabus URL: | https://www.cwnp.com/certifications/cwna/ |
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NEW QUESTION # 76
What factors will have the most significant impact on the amount of wireless bandwidth available to each station within a BSS? (Choose 2)
Answer: C
Explanation:
The factors that will have the most significant impact on the amount of wireless bandwidth available to each station within a BSS are:
* The number of client stations associated to the BSS
* The presence of co-located (10m away) access points on non-overlapping channels The number of client stations associated to the BSS affects the wireless bandwidth because each station shares the same channel and medium with other stations in the same BSS. The more stations there are, the more contention and collision there will be for the channel access, which reduces thethroughput and efficiency of the wireless communication. The wireless bandwidth available to each station depends on how the access point allocates the channel resources and how the stations use the channel time. For example, if the access point uses a round-robin scheduling algorithm, each station will get an equal share of the channel time regardless of its data rate or traffic demand. However, if the access point uses a proportional fair scheduling algorithm, each station will get a share of the channel time that is proportional to its data rate and traffic demand, which may result in higher or lower bandwidth for different stations.
The presence of co-located (10m away) access points on non-overlapping channels affects the wireless bandwidth because even though they use different channels, they may still cause interference and noise to each other due to channel leakage or imperfect filtering. The interference and noise can degrade the signal quality and SNR of the wireless communication, which reduces the data rate and throughput of the wireless communication. The wireless bandwidth available to each station depends on how well the access point and the station can cope with the interference and noise from other channels. For example, if the access point and the station support dynamic frequency selection (DFS) or adaptive radio management (ARM), they can switch to a less congested channel or adjust their output power or antenna gain to avoid or minimize interference from other channels.
References:1, Chapter 3, page 94;2, Section 3.2
NEW QUESTION # 77
A wireless engineer measures a high VSWR value on an antenna cable run. What does this indicate?
Answer: C
Explanation:
Voltage Standing Wave Ratio (VSWR) is a measurement used to determine how efficiently RF power is transmitted from a source, through a transmission line, to a load such as an antenna. A high VSWR value indicates a significant impedance mismatch somewhere in the RF path, which causes a portion of the signal to be reflected back toward the transmitter instead of being radiated. This reflected energy can reduce range and, in extreme cases, damage the transmitter.
An ideal VSWR value is close to 1:1, indicating minimal reflection.
NEW QUESTION # 78
An 802.11 WLAN transmitter that emits a 50 mW signal is connected to a cable with 3 dB of loss. The cable is connected to an antenna with 16 dBi of gain. What is the power level at the Intentional Radiator?
Answer: A
Explanation:
The power level at the Intentional Radiator (IR) is 250 mW. The IR is the point where the RF signal leaves the transmitter and enters the antenna system. To calculate the power level at the IR, we need to consider the output power level of the transmitter, the loss of the cable, and the gain of the antenna. The formula is:
Power level at IR (dBm) = Output power level (dBm) - Cable loss (dB) + Antenna gain (dBi) We can convert the output power level of 50 mW to dBm by using the formula:
Power level (dBm) = 10 * log10(Power level (mW))
Therefore, 50 mW = 10 * log10(50) = 16.99 dBm
We can plug in the values into the formula:
Power level at IR (dBm) = 16.99 - 3 + 16 = 29.99 dBm
We can convert the power level at IR from dBm to mW by using the inverse formula:
Power level (mW) = 10
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