花に欺く言語紹介より自分で体験したほうがいいです。WGU Foundations-of-Computer-Science問題集は我々Topexamでは直接に無料のダウンロードを楽しみにしています。弊社の経験豊かなチームはあなたに最も信頼性の高いWGU Foundations-of-Computer-Science問題集備考資料を作成して提供します。WGU Foundations-of-Computer-Science問題集の購買に何か質問があれば、我々の職員は皆様のお問い合わせを待っています。
| Section | Objectives |
|---|---|
| Topic 1: Data Profiling | - Apply fundamental concepts and subsetting techniques to a dataset - Utilize a programming language to manipulate arrays and discover insights |
| Topic 2: Basic Program Design | - Identify variables and data types within a programming language - Use functions, methods, and packages to leverage programming language - Explain how to store, access, and manipulate data in lists |
| Topic 3: OS Fundamentals | - Describe fundamental principles and core concepts of operating systems - Identify common privacy and security concepts that could be implemented in operating systems - Demonstrate various techniques and tools to manage operating systems |
| Topic 4: Algorithm Efficiency | - Choose an appropriate sorting algorithm method based on a given scenario - Describe the relationships between algorithm complexity and data structures - Choose an appropriate algorithm searching method based on a given scenario |
>> Foundations-of-Computer-Science試験資料 <<
WGU Foundations-of-Computer-Science試験に合格することは簡単ではなくて、適切な訓练を選ぶのはあなたの成功の第一歩です。情報源はあなたの成功の保障で、Topexamの商品はとてもいい情報保障ですよ。君はTopexamの商品を選ばればWGU Foundations-of-Computer-Science認証試験に合格するのを１００％保証するだけでなくあなたのために1年の更新を無料で提供します。
質問 # 68
What will the expression fam[3:6] return?
正解：B
解説：
Python slicing follows the rule `sequence[start:stop]`, where the `start` index is **inclusive** and the `stop` index is **exclusive**. This convention is taught widely because it makes many algorithms and boundary cases simpler: the length of the slice is `stop - start` (when step is 1), and adjacent slices can partition a sequence without overlap. For a list named `fam`, the slice `fam[3:6]` starts at index 3 and includes the elements at indices 3, 4, and 5, but it stops before index 6.
This is a frequent source of off-by-one errors for beginners, so textbooks emphasize remembering: "start is included, stop is not." If `fam` had at least 6 elements, then `fam[3:6]` would produce a new list of exactly three elements (positions 3, 4, 5). If `fam` had fewer than 6 elements, Python would still return a valid slice up to the end without raising an error, because slicing is designed to be safe within bounds.
# Option A is incorrect because it skips index 3 and incorrectly includes index 6. Option B is incorrect because it includes index 6, which the stop boundary excludes. Option D is incorrect because slicing returns a sublist, not a single element; a single element would require indexing like `fam[6]`.
質問 # 69
What is the expected result of running the following code: list1[0] = "California"?
正解：A
解説：
Python lists are mutable sequences, which means elements can be changed in place after the list has been created. The expression list1[0] = "California" uses indexing to target the element at position 0 (the first element, because Python uses zero-based indexing) and assignment (=) to replace that element with a new value. As a result, the list keeps the same length, but its first entry becomes "California".
This operation does not create a new list (so option A is incorrect); it modifies the existing list object referenced by list1. It also does not append to the end of the list (so option C is incorrect). Appending would use methods like list1.append("California"). Option D is not meaningful in Python list semantics; assignment to a single index replaces exactly one element rather than "adding a second element to the line." Textbooks highlight this difference between mutable and immutable sequence types. For example, strings are immutable, so you cannot assign to some_string[0]. Lists, however, are designed for collections that change over time, supporting updates, insertions, deletions, and reordering. Index assignment is fundamental for many algorithms: updating an array-like buffer, modifying a dataset row, replacing incorrect values, or implementing in-place transformations efficiently.
質問 # 70
What is the likely cause if a default Python configuration does not recognize a NumPy array as an allowed data structure?
正解：D
解説：
NumPy arrays are not a built-in Python data structure. In a default Python installation, the interpreter includes core types such as int, float, str, list, tuple, dict, and set, plus the standard library. A NumPy array, typically created as numpy.ndarray, is provided by the third-party NumPy library. Therefore, if a "default Python configuration" does not recognize a NumPy array, the most likely cause is thatNumPy is not installed or not available in the active environment. This happens often when a user has multiple Python environments (system Python, virtual environments, conda environments) and installs NumPy into one environment while running code in another.
Option B is incorrect because Python's standard-library array module is different from NumPy. Importing array does not create or enable NumPy's ndarray type. Option C is possible in rare cases,but the typical, textbook-aligned explanation is missing dependencies rather than an incorrectly configured interpreter. Option D is also unlikely: while very old Python versions may cause compatibility issues with modern NumPy releases, the symptom described-NumPy arrays not being recognized at all-more directly indicates the package is absent in the running environment.
In practice, verifying import numpy and checking the installed packages for the current interpreter resolves the issue.
質問 # 71
What is a correct call to the linear search defined as def linear_search(customersList, search_value): ?
正解：B
解説：
A function definition in Python specifies a function name and a list of parameters. Here, def linear_search (customersList, search_value): defines a function named linear_search that requirestwo argumentswhen called: a list (or sequence) of customer items and the value being searched for. A correct call must therefore supply both arguments in the same order: linear_search(customersList, search_value). Option B is correct because it calls the function properly and then prints the returned result.
Textbooks describe linear search as scanning the list from the beginning to the end, comparing each element to search_value until a match is found or the list ends. The function typically returns an index (e.g., position of the match) or a Boolean, or possibly -1/None if not found. Wrapping the call in print(...) is a standard way to display the returned value for testing or demonstration.
Option A is incorrect because it calls a different function name, not linear_search. Option C is incorrect because linear_search() would attempt to call the function with zero arguments, which would raise a TypeError, and then it tries to call the result as if it were another function. Option D uses a different function name (search_linear) and also contains a spelling mismatch compared to the given definition.
質問 # 72
Which statement describes the relationship between trees and graphs?
正解：D
解説：
In discrete mathematics and computer science, atreeis a special kind ofgraph. The standard graph-theory definition is that a tree is aconnected, acyclicundirected graph. "Acyclic" means it containsno cycles, i.e., you cannot start at a vertex, follow a sequence of edges, and return to the starting vertex without repeating edges in a way that forms a loop. (Wikipedia) This property is exactly what makes option D correct.
The other options contradict the definition. If a structure has cycles, it is not a tree (though it may still be a graph). If it has unconnected nodes, it is not connected; such a structure is more like aforest(a disjoint union of trees) rather than a single tree. (Wikipedia) The idea of "levels" belongs to a particular computer-science representation called arooted tree, where one node is chosen as the root and nodes can be assigned depths
/levels based on distance from the root. But levels are not required in the abstract definition of a tree as a graph; they arise from choosing a root and orientation for convenience in algorithms like BFS/DFS, heaps, and parse trees.
So, the relationship is: every tree is a graph with extra structure-specifically, no cycles and (typically) connectivity-and the "no cycles" rule is the key distinguishing feature. (Discrete Mathematics)
質問 # 73
......
最も専門的な専門家によって編集された当社のWGU練習資料は、成功のために高品質で正確なFoundations-of-Computer-Science練習資料を提供します。 これまで、WGU試験トレントをサポートする世界中の何万人ものお客様がいます。 Foundations-of-Computer-Science学習教材に不慣れな場合は、参考のために無料のデモをダウンロードしてください。また、一部の未学習の試験受験者には、WGU実践教材で必要事項をすぐにマスターできます。
Foundations-of-Computer-Science的中合格問題集: https://www.topexam.jp/Foundations-of-Computer-Science_shiken.html