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WGU Introduction-to-Cryptography Exam Syllabus Topics:

SectionWeightObjectives
Topic 1: Cryptography Fundamentals20%- Historical evolution and modern applications
- Basic terminology: plaintext, ciphertext, algorithm, key
- Core goals: confidentiality, integrity, authentication, non-repudiation
Topic 2: Symmetric Encryption25%- Block vs stream ciphers, modes of operation (ECB, CBC, OFB, CFB)
- Algorithms: AES, DES, 3DES, Blowfish
- Principles and operation
- Key generation, distribution, and management challenges
Topic 3: Implementation & Best Practices5%- Common mistakes and vulnerabilities
- Standards and compliance
- Selecting appropriate algorithms and key sizes
Topic 4: Key Management & Secure Protocols10%- Secure protocols: TLS/SSL, IPsec, SSH, PGP
- Key generation, storage, exchange, and destruction
- Cryptographic attacks: brute force, birthday, man-in-the-middle
Topic 5: Asymmetric Encryption & Public Key Infrastructure25%- Certificate lifecycle: creation, validation, revocation
- PKI components: certificates, CAs, trust models
- Digital signatures: purpose and process
- Principles: public/private key pairs
- Algorithms: RSA, ECC, Diffie-Hellman
Topic 6: Hash Functions & Data Integrity15%- Properties: collision resistance, one-way function
- Uses: integrity checks, password storage, message authentication
- HMAC construction and application
- Algorithms: SHA-1, SHA-256, SHA-3, MD5

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WGU Introduction to Cryptography HNO1 Sample Questions (Q45-Q50):

NEW QUESTION # 45
(What is an alternative to using a Certificate Revocation List (CRL) with certificates?)

Answer: B

Explanation:
OCSP is the primary online alternative to CRLs for checking whether a certificate has been revoked. With a CRL, a relying party periodically downloads a list of revoked certificate serial numbers published by the issuing CA (or CRL distribution point). That approach can be bandwidth-heavy, introduces latency between revocation and client awareness, and can result in clients using stale revocation data if updates are infrequent.
OCSP improves this by allowing a client (or a server on the client's behalf) to query an OCSP responder in near real time about the status of a specific certificate (good, revoked, or unknown). In practice, many TLS deployments use OCSP stapling, where the server periodically fetches a signed OCSP response from the CA's responder and "staples" it to the TLS handshake, reducing client-side network calls and improving privacy (the CA doesn't learn which site the client is visiting). Thus, OCSP provides a more timely, certificate- specific revocation status mechanism than CRLs while preserving the CA's signed assurance.


NEW QUESTION # 46
(A company wants to use certificates issued by a root CA to demonstrate to customers that it is a legitimate company being hosted by a cloud provider. Who needs to trust the root CA public key?)

Answer: B

Explanation:
In a public key infrastructure, trust in a certificate ultimately depends on the relying party's trust anchor set- typically the root CA certificates preinstalled in a customer's browser/OS trust store. For customers to accept the company's certificate as legitimate, the buyer (customer) must trust the root CA public key (or an intermediate chained to it) so they can validate the certificate chain and signatures. The seller (the company) also must trust and rely on the root CA public key to build and present a valid chain and to make operational decisions based on that CA's issuance and revocation mechanisms; practically, the seller selects a CA whose root is widely trusted by customers. The cloud provider's trust is not what makes the certificate valid to customers; the provider may terminate TLS or pass traffic through, but customer validation is based on the chain to a trusted root. Government agencies like the FTC are not part of the cryptographic trust path for TLS certificate validation. Therefore, among the given options, the correct pairing is the seller and the buyer, reflecting both the issuer selection/usage by the company and the relying-party validation by customers.


NEW QUESTION # 47
(Which mode of encryption uses an Initialization Vector (IV) to encrypt the first block and then uses the result to encrypt the next block?)

Answer: C

Explanation:
CBC mode introduces dependency between blocks to prevent the pattern leakage seen in ECB. It starts with a random (or unpredictable) IV for the first block. Before encrypting block 1, CBC XORs plaintext block 1 with the IV, then encrypts the result. For block 2 and onward, CBC XORs each plaintext block with the previous ciphertext block before encryption. This chaining means that changing one plaintext block affects that block's ciphertext and also influences the next block's computation. The IV ensures that encrypting the same message twice under the same key produces different ciphertexts (assuming a fresh IV). Option A (ECB) has no IV or chaining. OFB and CFB are feedback modes that effectively generate a keystream; they do use an IV, but the "uses the result to encrypt the next block" wording most directly matches CBC's ciphertext-chaining description in standard teaching. CBC still requires integrity protection (e.g., HMAC or an AEAD mode) because it can be malleable without authentication. Therefore, the correct mode is Cipher Block Chaining (CBC).


NEW QUESTION # 48
(Which attack may take the longest amount of time to achieve success?)

Answer: C

Explanation:
A brute-force attack exhaustively tries every possible key or password candidate until the correct one is found. Because it explores the full search space (or a very large portion of it), brute force is often the slowest method, especially when strong keys, long passwords, rate limits, and slow password hashing (bcrypt/Argon2) are used. By contrast, a dictionary attack reduces work by trying only common or likely passwords, often succeeding quickly against weak human-chosen secrets. Rainbow table attacks shift work into precomputation; once a table exists, lookup can be faster than brute-force-though salt and modern hashing defeat them. Birthday attacks are about finding collisions, not necessarily recovering a specific secret, and their expected work is about 2

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