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Oracle Database SQL Sample Questions (Q72-Q77):

NEW QUESTION # 72
View the Exhibit and examine the structure in the DEPARTMENTS tables. (Choose two.)

Examine this SQL statement:
SELECT department_id "DEPT_ID", department_name, 'b' FROM
departments
WHERE departments_id=90
UNION
SELECT department_id, department_name DEPT_NAME, 'a' FROM
departments
WHERE department_id=10
Which two ORDER BY clauses can be used to sort the output?

A. ORDER BY DEPT_NAME;
B. ORDER BY DEPT_ID;
C. ORDER BY 3;
D. ORDER BY 'b';

Answer: B,C

NEW QUESTION # 73
You need to produce a report where each customer's credit limit has been incremented by
$1000. In the output, the customer's last name should have the heading Name and the incremented credit limit should be labeled New Credit Limit. The column headings should have only the first letter of each word in uppercase.
Which statement would accomplish this requirement?

A. SELECT cust_last_name AS "Name", cust_credit_limit + 1000AS "New Credit Limit"FROM customers;
B. SELECT cust_last_name AS Name, cust_credit_limit + 1000"New Credit Limit"FROM customers;
C. SELECT cust_last_name AS Name, cust_credit_limit + 1000AS New Credit LimitFROM customers;
D. SELECT INITCAP (cust_last_name) "Name", cust_credit_limit + 1000INITCAP ("NEW CREDIT LIMIT")FROM customers;

Answer: A

NEW QUESTION # 74
View the exhibit and examine the ORDERS table.
ORDERS
Name
Null?
Type
ORDER ID
NOT NULL
NUMBER(4)
ORDATE DATE
DATE
CUSTOMER ID
NUMBER(3)
ORDER TOTAL
NUMBER(7,2)
The ORDERS table contains data and all orders have been assigned a customer ID. Which statement would add a NOT NULL constraint to the CUSTOMER_ID column?

A. ALTER TABLE ordersMODIFY CONSTRAINT orders_cust_id_nn NOT NULL
(customer_id);
B. ALTER TABLE ordersMODIFY customer_id CONSTRAINT orders_cust_nn NOT NULL (customer_id);
C. ALTER TABLE ordersADD customer_id NUMBER(6)CONSTRAINT orders_cust_id_nn NOT NULL;
D. ALTER TABLE ordersADD CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);

Answer: B

NEW QUESTION # 75
Examine the description of the PRODUCT_INFORMATION table:

Which query retrieves the number of products with a null list price?

A. SELECT COUNT (list_price) FROM product_information WHERE list_price = NULL;
B. SELECT COUNT(NVL(list_price, 0)) FROM product_information WHERE list_price IS NULL;
C. SELECT COUNT (list_price) FROM product_information WHERE list_price IS NULL;
D. SELECT COUNT (DISTINCT list_price) FROM product_information WHERE list_price IS NULL;

Answer: B

Explanation:
https://www.oracletutorial.com/oracle-aggregate-functions/oracle-avg/

NEW QUESTION # 76
Which two are true about virtual columns?

A. They can be indexed.
B. They can be referenced in the set clause of an update statement as the name of the column To be updated.
C. They cannot have a data type explicitly specified.
D. They can be referenced In the where clause of an update or debete statement.
E. They can be referenced in the column expression of another virtxial column.

Answer: A,D

NEW QUESTION # 77
......

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