Applied-Algebra試験のShikenPASS教材は専門家によって編集され、経験豊富な専門家によって承認されています。これらは、合格試験の論文と業界で人気の傾向に従って改訂および更新されます。 Applied-Algebra試験トレントの言語は理解しやすいものであり、Applied-Algebra試験問題はどの学習者にも適しています。 Applied-Algebra学習教材の内容は習得しやすく、重要な情報を簡素化しました。 Applied-Algebraテストの質問は、最新かつ有効な質問と回答を伝えるため、WGU Applied Algebra FXO2 PFXP C957学習がリラックスして効率的になります。
| Section | Objectives |
|---|---|
| Functions and Algebra of Functions | - Derive conclusions based on graphs - Derive conclusions based on notation - Derive conclusions based on data |
| Validity of Models | - Determine validity - Examine utility - Determine fit |
| Graphical Depictions | - Interpret maximum and minimum for situations - Interpret asymptotes for situations - Interpret rates of change for situations - Interpret inputs and outputs for situations - Interpret concavity for situations |
| Logistic Functions | - Interpret rates of change for logistic functions - Interpret asymptotes for logistic functions - Interpret inputs and outputs for logistic functions |
| Polynomial Functions | - Interpret inputs and outputs for polynomial functions - Interpret rates of change for polynomial functions - Interpret concavity for polynomial functions |
| Exponential Functions | - Interpret concavity for exponential functions - Interpret inputs and outputs for exponential functions - Interpret rates of change for exponential functions |
| Linear Functions | - Interpret inputs and outputs of linear functions - Interpret rates of change for linear functions |
人々はそれぞれ自分の人生計画があります。違った選択をしたら違った結果を取得しますから、選択は非常に重要なことです。ShikenPASSのWGUのApplied-Algebra試験トレーニング資料はIT職員が自分の高い目標を達成することを助けます。この資料は問題と解答に含まれていて、実際の試験問題と殆ど同じで、最高のトレーニング資料とみなすことができます。
質問 # 72
As sacks are unloaded off a wagon, the total weight of the wagon and sacks changes. Each sack has the same weight. After 3 sacks are removed, the total weight of the cart and remaining sacks is 116 pounds. After 6 sacks are removed, the total weight is 101 pounds.
What is the weight of each sack?
正解：C
解説：
This situation can be modeled using a linear relationship because each sack has the same weight.
We are given:
After 3sacks are removed, the total weight is 116pounds.
After 6sacks are removed, the total weight is 101pounds.
From 3 sacks removed to 6 sacks removed, the number of removed sacks increases by:
6-3=3
During that time, the total weight decreases from 116pounds to 101pounds:
116-101=15
So removing 3 additional sacks decreases the total weight by 15 pounds.
Now divide to find the weight of one sack:
15/3=5
So each sack weighs:
5 " pounds "
Check:
If 3 more sacks are removed and each sack weighs 5 pounds, the total weight should decrease by:
3(5)=15
116-15=101
This matches the given information.
質問 # 73
The value of a collectible coin can be modeled by F(t), where t represents years since the number of years since the coin was found, and the vertical axis represents the value, in thousands of dollars.
How is the value of the coin changing over time based on the graph?
正解：C
解説：
The graph shows the value of the coin increasing over time. Since the curve rises from left to right, the value is not decreasing. The graph also becomes steeper as time increases, which means the rate of increase is getting larger. In Applied Algebra, when a graph is increasing and its slope is increasing, the quantity is described as increasing faster and faster. This is typical of exponential growth, where values grow by a repeated percent or factor rather than by a constant amount. The choices involving decreasing are incorrect because the graph moves upward. The choice "increasing slower and slower" would require the graph to flatten, which it does not. Therefore, the correct answer is B.
質問 # 74
The figure displays the graphs of two functions representing the heights, h_1and h_2, in feet, of two balls tseconds after being launched.
Which ball was lower 0.9seconds after being launched?
正解：A
解説：
This question asks us to compare the heights of two balls at a specific time:
t=0.9
The graph shows:
Ball 1 as the solid blue curve.
Ball 2 as the dashed blue curve.
To determine which ball was lower at t=0.9, we look at the vertical positions of both curves when the time is
0.9seconds.
At approximately t=0.9:
" height of Ball 1 " < " height of Ball 2 "
This means Ball 1 is lower than Ball 2 at that time.
The correct reasoning must say both:
Ball 1 was lower, and
Ball 1's height was less than Ball 2's height at t=0.9.
That matches option A.
質問 # 75
The graph shows the value, O, in dollars, of an investment account over time.
What represents the value of the account after 8 years?
正解：D
解説：
The graph shows the total value of an investment account as time increases.
The horizontal axis represents:
" Time in years "
The vertical axis represents:
" Total value in dollars "
We need to find the value of the account after:
8 " years "
From the graph, when t=8, the curve is slightly above $2,200. The closest answer choice is:
$2,221.12
So the value of the account after 8 years is approximately:
$2,221.12
Therefore, the correct answer is:
# ( " D " )
質問 # 76
A researcher collected data on the number of annual bear sightings in a region over time. The results are shown in the scatterplot. A regression function is graphed with r