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Oracle 1z1-071 Exam Syllabus Topics:

Section	Weight	Objectives
Working with Time Zones and Date/Time Data		- Time zone conversion functions - TIMESTAMP, INTERVAL data types
Managing Indexes, Synonyms and Sequences		- Create and use sequences - Create and maintain indexes - Create and use synonyms
Aggregating Data Using Group Functions	10%	- SUM, AVG, COUNT, MAX, MIN functions - Handling NULLs in group functions - GROUP BY and HAVING clauses
Conversion Functions and Conditional Expressions	10%	- NVL, NULLIF, COALESCE and CASE expressions - Implicit and explicit data type conversion - TO_CHAR, TO_NUMBER, TO_DATE functions
Managing Tables and Constraints		- Data types, creating/altering/dropping tables - Temporary and external tables - Constraints: primary key, foreign key, unique, check, not null
Displaying Data from Multiple Tables	15%	- Self-joins and outer joins - Cartesian products - Equijoins and non-equijoins
Relational Database Concepts	10%	- Relationship between database and SQL - Theoretical and physical aspects of relational databases - ERD and SQL statement mapping
Manipulating Data and Managing Transactions		- Multi-table inserts - INSERT, UPDATE, DELETE, MERGE statements - Transaction control: COMMIT, ROLLBACK, SAVEPOINT
Using SET Operators		- UNION, UNION ALL, INTERSECT, MINUS operators - Ordering results with set operations
Using Data Dictionary Views		- Retrieve metadata and object information
Retrieving Data Using SQL SELECT Statement	20%	- SELECT statement syntax and usage - Arithmetic operations and NULL handling - Column aliases, concatenation, literals and DISTINCT
Controlling User Access		- Roles, granting and revoking privileges - System and object privileges
Restricting and Sorting Data	15%	- WHERE clause and filtering conditions - ORDER BY clause and sorting rules - Substitution variables, DEFINE and VERIFY commands - Operator precedence
Using Subqueries to Solve Queries		- Correlated subqueries for update/delete - Single-row and multi-row subqueries
Using Single-Row Functions to Customize Output	20%	- Nested functions usage - Character, number, and date functions
Managing Views		- Create, modify and drop views - Updatable and read-only views

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Oracle Database SQL 1z1-071 Prüfungsfragen mit Lösungen (Q211-Q216):

211. Frage
Evaluate the following SELECT statement and view the exhibit to examine its output:
SELECT constraint_name, constraint_type, search_condition, r_constraint_name, delete_rule, status, FROM user_constraints WHERE table_name = 'ORDERS'; CONSTRAINT_NAME CON SEARCH_CONDITION R_CONSTRAINT_NAME DELETE_RULE STATUS
ORDER_DATE_NN
C
"ORDER_DATE" IS NOT NULL
ENABLED
ORDER_CUSTOMER_ID_NN
C
"CUSTOMER_ID" IS NOT NULL
ENABLED
ORDER_MODE_LOV
C
order _mode in ('direct', 'online')
ENABLED
ORDER TOTAL MIN
C
order total >= 0
ENABLED
ORDER PK
P
ENABLED
ORDERS CUSTOMER ID
R
CUSTOMERS ID
SET NULL
ENABLED
ORDERS SALES REP
R
EMP EMP ID
SET NULL
ENABLED
Which two statements are true about the output? (Choose two.)

A. The column DELETE_RULE decides the state of the related rows in the child table when the corresponding row is deleted from the parent table.
B. The STATUS column indicates whether the table is currently in use.
C. In the second column, 'c' indicates a check constraint.
D. The R_CONSTRAINT_NAME column gives the alternative name for the constraint.

Antwort: A,C

212. Frage
Examine the contents of the EMP table:

Examine this query that executes successfully:

What is the result?

A. It will return the six employees earning the lowest salaries, in ascending order.
B. It will return the six employees earning the highest salaries, in descending order.
C. It will return the five employees earning the lowest salaries, in ascending order.
D. It will return the five employees earning the highest salaries, in descending order.

Antwort: C

Begründung:
CREATE TABLE EMP
(
ID NUMBER(10),
NAME VARCHAR2(10),
SALARY NUMBER(10)
)
INSERT INTO EMP VALUES (101, 'JOHN', 26000);
INSERT INTO EMP VALUES (102, 'NEENA', 24000);
INSERT INTO EMP VALUES (103, 'DEHAAN', 12000);
INSERT INTO EMP VALUES (104, 'LEX', 17000);
INSERT INTO EMP VALUES (105, 'BILL', 18000);
INSERT INTO EMP VALUES (106, 'DANIEL', 26000);
INSERT INTO EMP VALUES (107, 'BEN', 12000);
INSERT INTO EMP VALUES (108, 'GEORGE', 25000);
SELECT * FROM EMP
ORDER BY SALARY
FETCH FIRST 5 ROWS WITH TIES;

213. Frage
Examine the description of the EMPLOYEEStable:

Which two queries return all the rows for employees whose salary is greater than the average salary in their department? (Choose two.)

Antwort: A,C

214. Frage
Examine the description of the EMPLOYEES table:

You write this failing statement:
SELECT dept_no AS department_id, MAX (salary) As max_sal
FROM employees
WHERE salary >10000
GROUP BY department_id
ORDER BY max_sal;
Which clause causes the error?

A. ORDER BY
B. SELECT
C. GROUP BY
D. WHERE

Antwort: C

Begründung:
In the SQL statement provided, the error is caused by the GROUP BY clause. In Oracle SQL, when using GROUP BY, the expression in the GROUP BY clause must match exactly the expression in the SELECT list. The GROUP BY clause should reference the column name dept_no as mentioned in the SELECT list, not the alias department_id which is defined within the same SELECT statement.
The corrected SQL statement should be:
SELECT dept_no AS department_id, MAX(salary) As max_sal FROM employees WHERE salary > 10000 GROUP BY dept_no -- Changed from 'department_id' to 'dept_no' ORDER BY max_sal; Reference:
Oracle Documentation on GROUP BY clause: GROUP BY Clause

215. Frage
Which two statements are true about the WHERE and HAVING clauses in a SELECT statement?

A. The WHERE clause can be used to exclude rows before dividing them into groups.
B. WHERE and HAVING clauses can be used in the same statement only if applied to different table columns.
C. Aggregating functions and columns used in HAVING clauses must be specified in these SELECT list of a query.
D. The HAVING clause can be used with aggregating functions in subqueries.
E. The WHERE clause can be used to exclude rows after dividing them into groups

Antwort: A,C

Begründung:
In SQL, the WHERE and HAVING clauses are used to filter records; the WHERE clause is applied before grouping the records, while the HAVING clause is used after grouping the records, particularly when using aggregation functions.
Statement D is true because the HAVING clause is used to filter groups based on the result of aggregate functions. Therefore, any column or aggregate function appearing in the HAVING clause must also appear in the SELECT list of the query, unless it is used as part of an aggregate function.
Statement E is true because the WHERE clause is designed to filter rows before they are grouped into aggregate groups in a GROUP BY clause. This is a fundamental aspect of SQL that optimizes query performance by reducing the number of rows to be processed in the aggregate phase.
Statements A, B, and C are incorrect based on the following:
A is incorrect because the WHERE clause does not operate on groups but on individual rows before grouping.
B is misleading; while WHERE and HAVING can be used in the same statement, their usage is not restricted to different columns. They perform different functions (row-level filtering vs. group-level filtering).
C is incorrect because subqueries using aggregate functions typically do not use HAVING clauses; rather, HAVING is used in the outer query to filter the results of aggregates.

216. Frage
......

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