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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Retrieving Data Using SQL SELECT Statement | 20% | - Arithmetic operations and NULL handling - Column aliases, concatenation, literals and DISTINCT - SELECT statement syntax and usage |
| Topic 2: Aggregating Data Using Group Functions | 10% | - Handling NULLs in group functions - GROUP BY and HAVING clauses - SUM, AVG, COUNT, MAX, MIN functions |
| Topic 3: Displaying Data from Multiple Tables | 15% | - Equijoins and non-equijoins - Self-joins and outer joins - Cartesian products |
| Topic 4: Managing Indexes, Synonyms and Sequences | - Create and use synonyms - Create and maintain indexes - Create and use sequences | |
| Topic 5: Working with Time Zones and Date/Time Data | - Time zone conversion functions - TIMESTAMP, INTERVAL data types | |
| Topic 6: Using SET Operators | - Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators | |
| Topic 7: Restricting and Sorting Data | 15% | - ORDER BY clause and sorting rules - Substitution variables, DEFINE and VERIFY commands - WHERE clause and filtering conditions - Operator precedence |
| Topic 8: Manipulating Data and Managing Transactions | - Multi-table inserts - Transaction control: COMMIT, ROLLBACK, SAVEPOINT - INSERT, UPDATE, DELETE, MERGE statements | |
| Topic 9: Using Subqueries to Solve Queries | - Single-row and multi-row subqueries - Correlated subqueries for update/delete | |
| Topic 10: Managing Tables and Constraints | - Data types, creating/altering/dropping tables - Temporary and external tables - Constraints: primary key, foreign key, unique, check, not null | |
| Topic 11: Using Single-Row Functions to Customize Output | 20% | - Character, number, and date functions - Nested functions usage |
| Topic 12: Using Data Dictionary Views | - Retrieve metadata and object information | |
| Topic 13: Conversion Functions and Conditional Expressions | 10% | - TO_CHAR, TO_NUMBER, TO_DATE functions - NVL, NULLIF, COALESCE and CASE expressions - Implicit and explicit data type conversion |
| Topic 14: Managing Views | - Updatable and read-only views - Create, modify and drop views | |
| Topic 15: Relational Database Concepts | 10% | - Theoretical and physical aspects of relational databases - Relationship between database and SQL - ERD and SQL statement mapping |
| Topic 16: Controlling User Access | - Roles, granting and revoking privileges - System and object privileges |
>> Standard 1z1-071 Answers <<
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NEW QUESTION # 238
View the Exhibit and examine the structure of the CUSTOMERS table.
Using the CUSTOMERS table, you must generate a report that displays a credit limit increase of 15% for all customers.
Customers with no credit limit should have "Not Available" displayed.
Which SQL statement would produce the required result?
Answer: C
NEW QUESTION # 239
Which two statements are true regarding savepoints? (Choose two.)
Answer: C,D
Explanation:
References:
NEW QUESTION # 240
View the Exhibit and examine the structure of the CUSTOMERS table.
Using the CUSTOMERS table, you must generate a report that displays a credit limit increase of 15% for all customers.
Customers with no credit limit should have "Not Available" displayed.
Which SQL statement would produce the required result?
Answer: C
NEW QUESTION # 241
Examine this SQL statement:
Which two are true?
Answer: B,E
NEW QUESTION # 242
Examine these two queries and their output:
SELECT deptno, dname FROM dept;
SELECT ename, job, deptno FROM emp ORDER BY deptno;
Now examine this query:
SELECT ename, dname
FROM emp CROSS JOIN dept WHERE job = 'MANAGER'
AND dept.deptno IN (10, 20) ;
Answer: A
Explanation:
In a CROSS JOIN (also known as a Cartesian join), each row from the first table (emp) is joined to every row of the second table (dept). When we apply the filter for job = 'MANAGER' and dept.deptno IN (10, 20), we are restricting the results to managers in departments 10 and 20.
From the given data:
There are 2 managers in department 10 (CLARK and KING).
There is 1 manager in department 20 (JONES).
With a cross join, each of these emp records will join with each dept record where deptno is 10 or 20. Since there are two departments (10 and 20) in the dept table, each employee will match with two departments.
Therefore, the result set will be:
CLARK with accounting (dept 10) and research (dept 20)
KING with accounting (dept 10) and research (dept 20)
JONES with accounting (dept 10) and research (dept 20)
That gives us a total of 6 rows, which means the correct answer is B: 6.
NEW QUESTION # 243
......
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