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Oracle 1z0-071 (Oracle Database SQL) Exam is an essential certification exam for IT professionals who want to demonstrate their expertise in SQL programming and Oracle database management. Passing 1z0-071 exam validates the candidate's skills and knowledge in database management, database design, and application development. It is a valuable asset for IT professionals who want to advance their careers in database management and administration.

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Oracle 1z0-071 exam is intended for SQL developers, database administrators, and IT professionals who work with Oracle databases. 1z0-071 exam consists of 73 multiple-choice questions that need to be completed within two hours. 1z0-071 Exam is available in several languages, including English, Japanese, and Chinese. 1z0-071 exam can be taken either in-person at a Pearson VUE testing center or online from your home or office.

Oracle Database SQL Sample Questions (Q274-Q279):

NEW QUESTION # 274
In your session, the NLS._DAE_FORMAT is DD- MM- YYYY.There are 86400 seconds in a day.Examine this result:
DATE
02-JAN-2020
Which statement returns this?

A. SELECT-TO_CHAR(TO _DATE('29-10-2019'+ INTERVAL '2' MONTH+INTERVAL '4' DAYINTERVAL
'120' SECOND, 'DD-MON-YY') AS "daTe"
FROM DUAL;
B. SELECT TO_ CHAR(TO_ DATE('29-10-2019') + INTERVAL '3' MONTH + INTERVAL '7' DAY - INTERVAL '360' SECOND, ' DD-MON-YYYY') AS "date" FROM DUAL;
C. SELECT-TO_CHAR(TO _DATE('29-10-2019'+ INTERVAL '2' MONTH+INTERVAL '6' DAYINTERVAL
'120' SECOND, 'DD-MON-YY') AS "daTe"
FROM DUAL;
D. SELECT TO_ CHAR(TO_ DATE('29-10-2019') +INTERVAL '2'; MONTH + INTERVAL '5'; DAY
-
INTERVAL '86410' SECOND, ' DD-MON-YYYY') AS "date"
FROM DUAL;
E. SELECT To CHAR(TO _DATE('29-10-2019') + INTERVAL '2' NONTH + INTERVAL '5' DAY INEERVAL '120' SECOND, ' DD-MON-YYY) AS "date" FROM DUAL;

Answer: B

Explanation:
To calculate the date from a given base date with intervals, Oracle allows you to add or subtract intervals from dates. Since the NLS_DATE_FORMAT is set to DD-MM-YYYY, the output is expected to be in that format.
Option B seems to calculate a date that is 3 months and 7 days ahead of October 29, 2019, and then subtracts
360 seconds (which is 6 minutes), resulting in a time that is still within the same day.
Here's how the calculation in option B would work out:
* Start date: 29-10-2019
* Add 3 months: 29-01-2020
* Add 7 days: 05-02-2020
* Subtract 360 seconds: Since it's only a few minutes, the date remains 05-02-2020.
However, this does not match the provided result of 02-JAN-2020. We would need to consider the exact amount of time being subtracted or added to find the correct answer.
But upon reviewing the options, they all have various syntax errors such as a missing TO_CHAR function, incorrect quotes, and date formats not matching the session's NLS_DATE_FORMAT. Therefore, we would need to correct these issues to find the right answer.

NEW QUESTION # 275
Examine the data in the ORD_ITEMS table:

Evaluate this query:

Which statement is true regarding the result?

A. It returns an error because the HAVING clause should be specified after the GROUP BY clause.
B. It displays the item nos with their average quantity where the average quantity is more than double the minimum quantity of that item in the table.
C. It returns an error because all the aggregate functions used in the HAVING clause must be specified in the SELECT list.
D. It displays the item nos with their average quantity where the average quantity is more than double the overall minimum quantity of all the items in the table.

Answer: B

NEW QUESTION # 276
View the Exhibit and examine the details of PRODUCT_INFORMATIONtable.
PRODUCT_NAME
CATEGORY_ID SUPPLIER_ID
Inkjet C/8/HQ 12 102094
Inkjet C/4 12 102090
LaserPro 600/6/BW 12 102087
LaserPro 1200/8/BW 12 102099
Inkjet B/6 12 102096
Industrial 700/ID 12 102086
Industrial 600/DQ 12 102088
Compact 400/LQ 12 102087
Compact 400/DQ 12 102088
HD 12GB /R 13 102090
HD 10GB /I 13 102071
HD 12GB @7200 /SE 13 102057
HD 18.2GB @10000 /E 13 102078
HD 18.2GB @10000 /I 13 102050
HD 18GB /SE 13 102083
HD 6GB /I 13 102072
HD 8.2GB@5400 13 102093
You have the requirement to display PRODUCT_NAMEfrom the table where the CATEGORY_IDcolumn has values 12or 13, and the SUPPLIER_IDcolumn has the value 102088. You executed the following SQL statement:
SELECT product_name
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088; Which statement is true regarding the execution of the query?

A. It would execute and the output would display the desired result.
B. It would not execute because the entire WHEREclause condition is not enclosed within the parentheses.
C. It would not execute because the same column has been used in both sides of the ANDlogical operator to form the condition.
D. It would execute but the output would return no rows.

Answer: D

NEW QUESTION # 277
Evaluate the following SQL statement:
SQL> select cust_id, cust_last_name "Last name"
FROM customers
WHERE country_id = 10
UNION
SELECT cust_id CUST_NO, cust_last_name
FROM customers
WHERE country_id = 30
Identify three ORDER BY clauses either one of which can complete the query.

A. ORDER BY "CUST_NO"
B. ORDER BY 2, cust_id
C. ORDER BY "Last name"
D. ORDER BY 2, 1
E. ORDER BY CUST_NO

Answer: B,C,D

Explanation:
Using the ORDER BY Clause in Set Operations
-The ORDER BY clause can appear only once at the end of the compound query.
-Component queries cannot have individual ORDER BY clauses.
-The ORDER BY clause recognizes only the columns of the first SELECT query.
-By default, the first column of the first SELECT query is used to sort the output in an ascending order.

NEW QUESTION # 278
View the exhibit and examine the description of the DEPARTMENTSand EMPLOYEEStables.

You wrote this SQL statement to retrieve EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT NAME, for all employees:
SELECT employee_id, first_name, department_name
FROM employees
NATURAL JOIN departments;
The desired output is not obtained after executing the above SQL statement. What could be the reason for this?

A. The NATURAL JOINclause is missing the USINGclause.
B. The DEPARTMENTStable is not used before the EMPLOYEEStable in the FROMclause.
C. The EMPLOYEESand DEPARTMENTStables have more than one column with the same column name and data type.
D. The table prefix is missing for the column names in the SELECTclause.

Answer: C

Explanation:
Natural join needs only one column to be the same in each table. The EMPLOYEESand DEPARTMENTStables have two columns that are the same (Department_ID and Manager_ID)

NEW QUESTION # 279
......

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