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Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q97-Q102):

NEW QUESTION # 97
What are two unique features of functions defined with a fat arrow as compared to normal function definition?
Choose 2 answers

Answer: A,C


NEW QUESTION # 98
A developer has a fizzbuzz function that, when passed in a number, returns the following:
* ' fizz ' if the number is divisible by 3.
* ' buzz ' if the number is divisible by 5.
* ' fizzbuzz ' if the number is divisible by both 3 and 5.
* Empty string ' ' if the number is divisible by neither 3 nor 5.
Which two test cases properly test scenarios for the fizzbuzz function?

Answer: A,C

Explanation:
First, recall the fizzbuzz rules:
* If n divisible by 3 and not by 5 # return ' fizz ' .
* If n divisible by 5 and not by 3 # return ' buzz ' .
* If n divisible by both 3 and 5 # return ' fizzbuzz ' .
* Otherwise # return ' ' (empty string).
Evaluate each test:
Option A:
let res = fizzbuzz(true);
console.assert(res === ' ' );
In JavaScript, when using arithmetic operations with true, it is coerced to the number 1. A typical implementation of fizzbuzz would treat the argument as a number and compute:
* true % 3 # 1 % 3 # 1
* true % 5 # 1 % 5 # 1
So true is effectively treated as 1, which is divisible by neither 3 nor 5. The function should return ' ' . The assertion res === ' ' will pass.
This test covers the scenario "neither divisible by 3 nor 5".
Option B:
let res = fizzbuzz(3);
console.assert(res === ' ' );
* 3 is divisible by 3 but not by 5.
* According to fizzbuzz rules, fizzbuzz(3) should return ' fizz ' .
* This test expects ' ' , so it is incorrect; the assertion would fail in a correct implementation.
Option C:
let res = fizzbuzz(5);
console.assert(res === ' fizz ' );
* 5 is divisible by 5 but not by 3.
* According to fizzbuzz rules, fizzbuzz(5) should return ' buzz ' .
* This test expects ' fizz ' , so it is incorrect.
Option D:
let res = fizzbuzz(15);
console.assert(res === ' fizzbuzz ' );
* 15 is divisible by both 3 and 5.
* According to fizzbuzz rules, fizzbuzz(15) should return ' fizzbuzz ' .
* This assertion correctly matches the expected result, so it is a proper test case.
Thus, the two test cases that correctly test valid fizzbuzz behavior are:
The answer: A, D
Study Guide / Concept References (no links):
* Modulo operator (%) for divisibility checks
* Truthy/number coercion of boolean true in arithmetic (Number(true) === 1)
* Designing unit tests with console.assert
* Typical fizzbuzz logic structure and expected outputs


NEW QUESTION # 99
Refer to the following code that imports a module named utils:
import (foo, bar) from '/path/Utils.js';
foo() ;
bar() ;
Which two implementations of Utils.js export foo and bar such that the code above runs without
error?
Choose 2 answers

Answer: A,C


NEW QUESTION # 100
A developer wrote the following code to test a sum3 function that takes in an array of numbers and returns the sum of the first three numbers in the array, and the test passes.
A different developer made changes to the behavior of sum3 to instead sum only the first two numbers present in the array.

Which two results occur when running this test on the updated sum3 function?
Choose 2 answers

Answer: A,C


NEW QUESTION # 101
01 function changeValue(obj) {
02 obj.value = obj.value / 2;
03 }
04 const objA = {value: 10};
05 const objB = objA;
06
07 changeValue(objB);
08 const result = objA.value;
What is the value of result after the code executes?

Answer: D

Explanation:
* objA is { value: 10 }.
* objB = objA; # both variables reference the same object .
* changeValue(objB);:
obj.value = obj.value / 2; // modifies the shared object
So:
* objA.value becomes 10 / 2 = 5.
Thus result is 5.


NEW QUESTION # 102
......

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