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ISC CISSP Exam Syllabus Topics:

Section	Weight	Objectives
Software Development Security	11%	- Assess software security effectiveness 1. Security metrics 2. Application testing - Understand software development lifecycle security 1. DevSecOps 2. Secure SDLC - Identify and mitigate vulnerabilities 1. Static and dynamic testing 2. Code review
Asset Security	10%	- Identify and classify information and assets 1. Data classification 2. Asset ownership - Establish information handling requirements 1. Secure disposal 2. Data retention - Manage data lifecycle 1. Data sharing 2. Data storage - Provision resources securely 1. Media handling 2. Asset lifecycle management
Communication and Network Security	13%	- Secure network components 1. Firewalls 2. Routers and switches - Implement secure communication channels 1. VPN 2. Secure protocols - Implement secure design principles in networks 1. Segmentation 2. Network architecture
Security Operations	13%	- Conduct logging and monitoring activities 1. SIEM 2. Continuous monitoring - Operate and maintain preventive measures 1. Patch management 2. Backup operations - Implement incident management 1. Recovery procedures 2. Incident response - Understand and support investigations 1. Digital forensics 2. Evidence handling - Implement disaster recovery processes 1. Recovery testing 2. Business continuity
Security and Risk Management	15%	- Evaluate and apply security governance principles 1. Roles and responsibilities 2. Security policies and procedures 3. Organizational processes - Understand and apply threat modeling concepts 1. Attack surfaces 2. Threat actors - Apply risk management concepts 1. Risk treatment 2. Risk monitoring 3. Risk assessment - Establish and manage security awareness training 1. Training effectiveness 2. Awareness programs - Identify and analyze threats and vulnerabilities 1. Risk analysis methodologies 2. Threat modeling - Understand requirements for investigation types 1. Criminal investigations 2. Administrative investigations - Determine compliance requirements 1. Legal and regulatory requirements 2. Privacy requirements - Develop and manage security policies 1. Policy lifecycle 2. Standards and guidelines - Understand legal and regulatory issues 1. Cyber crimes and data breaches 2. Licensing and intellectual property - Understand and apply security concepts 1. Due care and due diligence 2. Confidentiality, integrity and availability 3. Security governance principles - Apply supply chain risk management concepts 1. Third-party governance 2. Vendor assessments
Security Assessment and Testing	12%	- Design and validate assessment strategies 1. Security testing 2. Audit strategies - Collect and analyze test outputs 1. Log reviews 2. Reporting - Conduct security control testing 1. Penetration testing 2. Vulnerability assessments
Security Architecture and Engineering	13%	- Apply cryptography 1. PKI 2. Encryption methods - Select controls based on security requirements 1. Preventive controls 2. Detective controls - Understand security capabilities of systems 1. Virtualization 2. Hardware security - Research and implement security models 1. Trusted computing base 2. Security frameworks - Assess vulnerabilities of architectures 1. Cloud-based systems 2. Embedded systems
Identity and Access Management	13%	- Integrate identity as a service 1. Cloud identity 2. SSO - Control physical and logical access 1. Identity lifecycle 2. Access provisioning - Manage identification and authentication 1. Federated identity 2. MFA

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ISC Certified Information Systems Security Professional (CISSP) 認定 CISSP 試験問題 (Q16-Q21):

質問 # 16
A database view is the results of which of the following operations?

A. Join, Project, and Select.
B. Join and Select.
C. Join, Project, and Create.
D. Join, Insert, and Project.

正解：A

解説：
Explanation/Reference:
Explanation:
SQL offers three classes of operators for creating views: select, project, and join.
The select operator serves to shrink the table vertically by eliminating unwanted rows (tuples).

The project operator serves to shrink the table horizontally by removing unwanted columns (attributes).

Most commercial implementations of SQL do not support a project operation, instead projections are achieved by specifying the columns desired in the output.
The join operator allows the dynamic linking of two tables that share a common column value.

Incorrect Answers:
A: SQL offers three classes of operators for creating views: select, project, and join. However, modern implementations of SQL do not support a project operation, instead projections are achieved by specifying the columns desired in the output. Nevertheless, project is a SQL operator.
B: Insert is a SQL command used to insert data into a table. It is not used to output a view.
C: Create is a SQL command used to create a new database, table, view, or index. However, the data or output of the view requires a select statement to shrink the table vertically by not showing unwanted rows, a project operation that shrinks the table horizontally by not showing unwanted columns, and a join statement when data from more than one table is required.
References:
http://db.grussell.org/section010.html
http://databasemanagement.wikia.com/wiki/Relational_Database_Model

質問 # 17
A large organization's human resources and security teams are planning on implementing technology to eliminate manual user access reviews and improve compliance. Which of the following options is MOST likely to resolve the issues associated with user access?

A. Implement a role-based access control (RBAC) system.
B. Implement identity and access management (IAM) platform.
C. Implement a single sign-on (SSO) platform.
D. Implement a Privileged Access Management (PAM) system.

正解：B

質問 # 18
Which of the following encryption algorithms does not deal with discrete logarithms?

A. RSA
B. Elliptic Curve
C. Diffie-Hellman
D. El Gamal

正解：A

解説：
The security of the RSA system is based on the assumption that factoring the product into two original large prime numbers is difficult
Source:
KRUTZ, Ronald L. & VINES, Russel D., The CISSP Prep Guide: Mastering the Ten
Domains of Computer Security, John Wiley & Sons, 2001, Chapter 4: Cryptography (page
159).
Shon Harris, CISSP All-in-One Examine Guide, Third Edition, McGraw-Hill Companies,
August 2005, Chapter 8: Cryptography, Page 636 - 639

質問 # 19
A database view is the results of which of the following operations?

A. Join, Project, and Select.
B. Join and Select.
C. Join, Project, and Create.
D. Join, Insert, and Project.

正解：A

解説：
What is Relational Algebra:
1.The formal description of how a relational database operates.
2.The mathematics which underpin SQL operations.
A number of operations can be performed in relational algebra to build relations and operate on
the data.
Five operations are primitives (Select, Project, Union, Difference and Product) and the other
operations can be defined in terms of those five. A View is defined from the operations of Join,
Project, and Select.
For the purpose of the exam you must remember the following terms from relational algebra and
their SQL equivalent:
Tuple = Row, Entry
Attribute = Column
Relation or Based relation = Table
See the extract below from the ISC2 book:
Each table, or relation, in the relational model consists of a set of attributes and a set of tuples
(rows) or entries in the table. Attributes correspond to a column in a table. Attributes are unordered
left to right, and thus are referenced by name and not by position. All data values in the relational
model are atomic. Atomic values mean that at every row/column position in every table there is
always exactly one data value and never a set of values. There are no links or pointers connecting
tables; thus, the representation of relationships is contained as data in another table.
A tuple of a table corresponds to a row in the table. Tuples are unordered top to bottom because a
relation is a mathematical set and not a list. Also, because tuples are based on tables that are
mathematical sets, there are no duplicate tuples in a table (sets in mathematics by definition do
not include duplicate elements).
The primary key is an attribute or set of attributes that uniquely identifies a specific instance of an
entity. Each table in a database must have a primary key that is unique to that table. It is a subset
of the candidate key.
Reference used for this question:
Hernandez CISSP, Steven (2012-12-21). Official (ISC)2 Guide to the CISSP CBK, Third Edition
((ISC)2 Press) (Kindle Locations 12262-12269). Auerbach Publications. Kindle Edition.
and
KRUTZ, Ronald L. & VINES, Russel D., The CISSP Prep Guide: Mastering the Ten Domains of
Computer Security, 2001, John Wiley & Sons, Page 46.
and
http://db.grussell.org/slides/rel%20algebra%201.ppt
NOTE:
SQL offers three classes of operators: select, project, and join.
The select operator serves to shrink the table vertically by eliminating unwanted rows (tuples).
The project operator serves to shrink the table horizontally by removing unwanted columns
(attributes).
And the join operator allows the dynamic linking of two tables that share a common column value.
The join operation is achieved by stating the selection criteria for two tables and equating them
with their common columns.
Most commercial implementations of SQL do not support a project operation, instead projections
are achieved by specifying the columns desired in the output. This is why the Project operator is
not well known as it is fading away from most databases.

質問 # 20
You are part of a security staff at a highly profitable bank and each day, all traffic on the network is logged for later review. Every Friday when major deposits are made you're seeing a series of bits placed in the
"Urgent Pointer" field of a TCP packet. This is only 16 bits which isn't much but it concerns you because:

A. This could be a sign of covert channeling in bank network communications and should be investigated.
B. It could be a symptom of malfunctioning network card or drivers and the source system should be checked for the problem.
C. It could be a sign of a damaged network cable causing the issue.
D. It is normal traffic because sometimes the previous fields 16 bit checksum value can over run into the urgent pointer's 16 bit field causing the condition.

正解：A

解説：
Explanation/Reference:
Explanation:
Some Intrusion Detection System (IDS) evasion techniques involve deliberately violating the TCP or IP protocols in a way the target computer will handle differently from the IDS. For example, the TCP Urgent Pointer is handled differently on different operating systems and may not be handled correctly by the IDS.
Incorrect Answers:
B: It is very unlikely that a changed TCP Urgent pointer value is caused by a hardware problem, such as a damaged network cable.
C: It is very unlikely that a changed TCP Urgent pointer value is caused by a hardware problem, such as a damaged network card, or by a corrupt driver.
D: The TCP Urgent pointer field does not contain checksums.
References:
https://en.wikipedia.org/wiki/Intrusion_detection_system_evasion_techniques

質問 # 21
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