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Oracle 1z0-830 Exam Syllabus Topics:

SectionObjectives
Database Connectivity (JDBC)- Database interaction
  • 1. JDBC API usage
    • 2. SQL execution and result handling
      Exception Handling and Debugging- Error handling mechanisms
      • 1. Checked vs unchecked exceptions
        • 2. Try-with-resources
          Advanced Java Features (Java SE 21)- Modern language features
          • 1. Pattern matching for switch
            • 2. Virtual threads (Project Loom)
              • 3. Sealed classes
                • 4. Records and record patterns
                  Input/Output and File Handling- NIO and file operations
                  • 1. File, Path, and Streams APIs
                    • 2. Serialization basics
                      Java Language Fundamentals- Java syntax and language structure
                      • 1. Data types, variables, and operators
                        • 2. Control flow statements
                          Object-Oriented Programming- Core OOP principles
                          • 1. Encapsulation, inheritance, polymorphism
                            • 2. Abstract classes and interfaces
                              Core APIs- Java standard library usage
                              • 1. Streams and functional programming
                                • 2. Date and Time API
                                  • 3. Collections Framework
                                    Concurrency and Multithreading- Thread management
                                    • 1. Thread lifecycle and synchronization
                                      • 2. Virtual threads and structured concurrency concepts

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                                        Oracle Java SE 21 Developer Professional Sample Questions (Q72-Q77):

                                        NEW QUESTION # 72
                                        Given:
                                        java
                                        List<String> frenchAuthors = new ArrayList<>();
                                        frenchAuthors.add("Victor Hugo");
                                        frenchAuthors.add("Gustave Flaubert");
                                        Which compiles?

                                        Answer: A,D,E

                                        Explanation:
                                        * Option A (Map<String, ArrayList<String>> authorsMap1 = new HashMap<>();)
                                        * #Compilation Fails
                                        * frenchAuthors is declared as List<String>,notArrayList<String>.
                                        * The correct way to declare a Map that allows storing List<String> is to use List<String> as the generic type,notArrayList<String>.
                                        * Fix:
                                        java
                                        Map<String, List<String>> authorsMap1 = new HashMap<>();
                                        authorsMap1.put("FR", frenchAuthors);
                                        * Reason:The type ArrayList<String> is more specific than List<String>, and this would cause a type mismatcherror.
                                        * Option B (Map<String, ? extends List<String>> authorsMap2 = new HashMap<String, ArrayList<String>>();)
                                        * #Compilation Fails
                                        * ? extends List<String>makes the map read-onlyfor adding new elements.
                                        * The line authorsMap2.put("FR", frenchAuthors); causes acompilation errorbecause wildcard (?
                                        extends List<String>) prevents modifying the map.
                                        * Fix:Remove the wildcard:
                                        java
                                        Map<String, List<String>> authorsMap2 = new HashMap<>();
                                        authorsMap2.put("FR", frenchAuthors);
                                        * Option C (var authorsMap3 = new HashMap<>();)
                                        * Compiles Successfully
                                        * The var keyword allows the compiler to infer the type.
                                        * However,the inferred type is HashMap<Object, Object>, which may cause issues when retrieving values.
                                        * Option D (Map<String, List<String>> authorsMap4 = new HashMap<String, ArrayList<String>
                                        >();)
                                        * Compiles Successfully
                                        * Valid declaration:HashMap<K, V> can be assigned to Map<K, V>.
                                        * Using new HashMap<String, ArrayList<String>>() with Map<String, List<String>> isallowed due to polymorphism.
                                        * Correct syntax:
                                        java
                                        Map<String, List<String>> authorsMap4 = new HashMap<String, ArrayList<String>>(); authorsMap4.put("FR", frenchAuthors);
                                        * Option E (Map<String, List<String>> authorsMap5 = new HashMap<String, List<String>>();)
                                        * Compiles Successfully
                                        * HashMap<String, List<String>> isa valid instantiation.
                                        * Correct usage:
                                        java
                                        Map<String, List<String>> authorsMap5 = new HashMap<>();
                                        authorsMap5.put("FR", frenchAuthors);
                                        Thus, the correct answers are:C, D, E
                                        References:
                                        * Java SE 21 - Generics and Type Inference
                                        * Java SE 21 - var Keyword


                                        NEW QUESTION # 73
                                        Given:
                                        java
                                        public class ExceptionPropagation {
                                        public static void main(String[] args) {
                                        try {
                                        thrower();
                                        System.out.print("Dom Perignon, ");
                                        } catch (Exception e) {
                                        System.out.print("Chablis, ");
                                        } finally {
                                        System.out.print("Saint-Emilion");
                                        }
                                        }
                                        static int thrower() {
                                        try {
                                        int i = 0;
                                        return i / i;
                                        } catch (NumberFormatException e) {
                                        System.out.print("Rose");
                                        return -1;
                                        } finally {
                                        System.out.print("Beaujolais Nouveau, ");
                                        }
                                        }
                                        }
                                        What is printed?

                                        Answer: A

                                        Explanation:
                                        * Analyzing the thrower() Method Execution
                                        java
                                        int i = 0;
                                        return i / i;
                                        * i / i evaluates to 0 / 0, whichthrows ArithmeticException (/ by zero).
                                        * Since catch (NumberFormatException e) doesnot matchArithmeticException, it is skipped.
                                        * The finally block always executes, printing:
                                        nginx
                                        Beaujolais Nouveau,
                                        * The exceptionpropagates backto main().
                                        * Handling the Exception in main()
                                        java
                                        try {
                                        thrower();
                                        System.out.print("Dom Perignon, ");
                                        } catch (Exception e) {
                                        System.out.print("Chablis, ");
                                        } finally {
                                        System.out.print("Saint-Emilion");
                                        }
                                        * Since thrower() throws ArithmeticException, it is caught by catch (Exception e).
                                        * "Chablis, "is printed.
                                        * Thefinally block always executes, printing "Saint-Emilion".
                                        * Final Output
                                        nginx
                                        Beaujolais Nouveau, Chablis, Saint-Emilion
                                        Thus, the correct answer is:Beaujolais Nouveau, Chablis, Saint-Emilion
                                        References:
                                        * Java SE 21 - Exception Handling
                                        * Java SE 21 - finally Block Execution


                                        NEW QUESTION # 74
                                        Given:
                                        java
                                        import java.io.*;
                                        class A implements Serializable {
                                        int number = 1;
                                        }
                                        class B implements Serializable {
                                        int number = 2;
                                        }
                                        public class Test {
                                        public static void main(String[] args) throws Exception {
                                        File file = new File("o.ser");
                                        A a = new A();
                                        var oos = new ObjectOutputStream(new FileOutputStream(file));
                                        oos.writeObject(a);
                                        oos.close();
                                        var ois = new ObjectInputStream(new FileInputStream(file));
                                        B b = (B) ois.readObject();
                                        ois.close();
                                        System.out.println(b.number);
                                        }
                                        }
                                        What is the given program's output?

                                        Answer: C

                                        Explanation:
                                        In this program, we have two classes, A and B, both implementing the Serializable interface, and a Test class with the main method.
                                        Program Flow:
                                        * Serialization:
                                        * An instance of class A is created and assigned to the variable a.
                                        * An ObjectOutputStream is created to write to the file "o.ser".
                                        * The object a is serialized and written to the file.
                                        * The ObjectOutputStream is closed.
                                        * Deserialization:
                                        * An ObjectInputStream is created to read from the file "o.ser".
                                        * The program attempts to read an object from the file and cast it to an instance of class B.
                                        * The ObjectInputStream is closed.
                                        Analysis:
                                        * Serialization Process:
                                        * The object a is an instance of class A and is serialized into the file "o.ser".
                                        * Deserialization Process:
                                        * When deserializing, the program reads the object from the file and attempts to cast it to class B.
                                        * However, the object in the file is of type A, not B.
                                        * Since A and B are distinct classes with no inheritance relationship, casting an A instance to B is invalid.
                                        Exception Details:
                                        * Attempting to cast an object of type A to type B results in a ClassCastException.
                                        * The exception message would be similar to:
                                        pgsql
                                        Exception in thread "main" java.lang.ClassCastException: class A cannot be cast to class B Conclusion:
                                        The program compiles successfully but throws a ClassCastException at runtime when it attempts to cast the deserialized object to class B.


                                        NEW QUESTION # 75
                                        Given:
                                        java
                                        Optional<String> optionalName = Optional.ofNullable(null);
                                        String bread = optionalName.orElse("Baguette");
                                        System.out.print("bread:" + bread);
                                        String dish = optionalName.orElseGet(() -> "Frog legs");
                                        System.out.print(", dish:" + dish);
                                        try {
                                        String cheese = optionalName.orElseThrow(() -> new Exception());
                                        System.out.println(", cheese:" + cheese);
                                        } catch (Exception exc) {
                                        System.out.println(", no cheese.");
                                        }
                                        What is printed?

                                        Answer: C

                                        Explanation:
                                        Understanding Optional.ofNullable(null)
                                        * Optional.ofNullable(null); creates an empty Optional (i.e., it contains no value).
                                        * Optional.of(null); would throw a NullPointerException, but ofNullable(null); safely creates an empty Optional.
                                        Execution of orElse, orElseGet, and orElseThrow
                                        * orElse("Baguette")
                                        * Since optionalName is empty, "Baguette" is returned.
                                        * bread = "Baguette"
                                        * Output:"bread:Baguette"
                                        * orElseGet(() -> "Frog legs")
                                        * Since optionalName is empty, "Frog legs" is returned from the lambda expression.
                                        * dish = "Frog legs"
                                        * Output:", dish:Frog legs"
                                        * orElseThrow(() -> new Exception())
                                        * Since optionalName is empty, an exception is thrown.
                                        * The catch block catches this exception and prints ", no cheese.".
                                        Thus, the final output is:
                                        makefile
                                        bread:Baguette, dish:Frog legs, no cheese.
                                        References:
                                        * Java SE 21 & JDK 21 - Optional
                                        * Java SE 21 - Functional Interfaces


                                        NEW QUESTION # 76
                                        Which of the following isn't a valid option of the jdeps command?

                                        Answer: F

                                        Explanation:
                                        The jdeps tool is a Java class dependency analyzer that can be used to understand the static dependencies of applications and libraries. It provides several command-line options to customize its behavior.
                                        Valid jdeps Options:
                                        * --generate-open-module: Generates a module declaration (module-info.java) with open directives for the given JAR files or classes.
                                        * --list-deps: Lists the immediate dependencies of the specified classes or JAR files.
                                        * --generate-module-info: Generates a module declaration (module-info.java) for the given JAR files or classes.
                                        * --print-module-deps: Prints the module dependencies of the specified modules or JAR files.
                                        * --list-reduced-deps: Lists the reduced dependencies, showing only the packages that are directly depended upon.
                                        Invalid Option:
                                        * --check-deps: There is no --check-deps option in the jdeps tool.
                                        Conclusion:
                                        Option A (--check-deps) is not a valid option of the jdeps command.


                                        NEW QUESTION # 77
                                        ......

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