1z1-071考古题推薦，1z1-071認證題庫

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Oracle 1z1-071 Exam Syllabus Topics:

Section	Weight	Objectives
Topic 1: Relational Database Concepts	10%	- Theoretical and physical aspects of relational databases - Relationship between database and SQL - ERD and SQL statement mapping
Topic 2: Retrieving Data Using SQL SELECT Statement	20%	- Column aliases, concatenation, literals and DISTINCT - SELECT statement syntax and usage - Arithmetic operations and NULL handling
Topic 3: Restricting and Sorting Data	15%	- Substitution variables, DEFINE and VERIFY commands - Operator precedence - ORDER BY clause and sorting rules - WHERE clause and filtering conditions
Topic 4: Controlling User Access		- Roles, granting and revoking privileges - System and object privileges
Topic 5: Using SET Operators		- Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators
Topic 6: Working with Time Zones and Date/Time Data		- Time zone conversion functions - TIMESTAMP, INTERVAL data types
Topic 7: Managing Tables and Constraints		- Temporary and external tables - Data types, creating/altering/dropping tables - Constraints: primary key, foreign key, unique, check, not null
Topic 8: Managing Indexes, Synonyms and Sequences		- Create and maintain indexes - Create and use sequences - Create and use synonyms
Topic 9: Using Data Dictionary Views		- Retrieve metadata and object information
Topic 10: Managing Views		- Updatable and read-only views - Create, modify and drop views
Topic 11: Displaying Data from Multiple Tables	15%	- Self-joins and outer joins - Cartesian products - Equijoins and non-equijoins
Topic 12: Using Subqueries to Solve Queries		- Correlated subqueries for update/delete - Single-row and multi-row subqueries
Topic 13: Manipulating Data and Managing Transactions		- Transaction control: COMMIT, ROLLBACK, SAVEPOINT - INSERT, UPDATE, DELETE, MERGE statements - Multi-table inserts
Topic 14: Aggregating Data Using Group Functions	10%	- Handling NULLs in group functions - SUM, AVG, COUNT, MAX, MIN functions - GROUP BY and HAVING clauses
Topic 15: Using Single-Row Functions to Customize Output	20%	- Nested functions usage - Character, number, and date functions
Topic 16: Conversion Functions and Conditional Expressions	10%	- Implicit and explicit data type conversion - TO_CHAR, TO_NUMBER, TO_DATE functions - NVL, NULLIF, COALESCE and CASE expressions

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1z1-071認證題庫，1z1-071最新題庫

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最新的 Oracle PL/SQL Developer Certified Associate 1z1-071 免費考試真題 (Q96-Q101):

問題 #96
Which two statements are true regarding constraints?

A. A constraint can be disabled even if the constraint column contains data.
B. All constraints can be defined at the column level and at the table level.
C. A foreign key column cannot contain null values.
D. A column with the UNIQUE constraint can contain null values.
E. A constraint is enforced only for INSERT operation on the table.

答案：A,D

問題 #97
Examine the structure of the MEMBERS table:

Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC;
What would be the result execution? (Choose the best answer.)

A. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.
B. It displays all cities in descending order, within which the last names are further sorted in descending order.
C. It fails because a column alias cannot be used in the ORDER BY clause.
D. It displays all cities in ascending order, within which the last names are further sorted in descending order.

答案：D

問題 #98
View the Exhibit and examine the description of the EMPLOYEES table.

You want to calculate the total remuneration for each employee. Total remuneration is the sum of the annual salary and the percentage commission earned for a year. Only a few employees earn commission.
Which SQL statement would you execute to get the desired output?

A. SELECT first_name, salary, salary*12+(salary*NVL2 (commission_pct,
salary,salary+commission_pct))"Total"FROM EMPLOYEES;
B. SELECT first_name, salary, salary*12 + NVL(salary,0)*commission_pct, "Total"FROM EMPLOYEES;
C. SELECT first_name, salary (salary + NVL (commission_pct, 0)*salary)*12 "Total"FROM EMPLOYEES;
D. SELECT first_name, salary, salary*12+salary*commission_pct "Total"FROM EMPLOYEES;

答案：A

問題 #99
View the exhibit and examine the description of SALES and PROMOTIONS tables.

You want to delete rows from the SALES table, where the PROMO_NAME column in the PROMOTIONS table has either blowout sale or everyday low price as values.
Which three DELETE statements are valid? (Choose three.)

A. DELETEFROM salesWHERE promo_id = (SELECT promo_idFROM promotionsWHERE promo_name = 'blowout sale')OR promo_name = 'everyday low price');
B. DELETEFROM salesWHERE promo_id IN (SELECT promo_idFROM promotionsWHERE promo_name IN = 'blowout sale','everyday low price'));
C. DELETEFROM salesWHERE promo_id = (SELECT promo_idFROM promo_name = 'blowout sale')AND promo_id = (SELECT promo_idFROM promotionsWHERE promo_name = 'everyday low price')FROM promotionsWHERE promo_name = 'everyday low price');
D. DELETEFROM salesWHERE promo_id = (SELECT promo_idFROM promotionsWHERE promo_name = 'blowout sale')OR promo_id = (SELECT promo_idFROM promotionsWHERE promo_name = 'everyday low price')

答案：A,B,D

問題 #100
Examine this partial statement:
SELECT ename, sal,comm FROM emp
Now examine this output:

WHICH ORDER BY clause will generate the displayed output?

A. ORDER BY NVL(comm,0) ASC NULLS FIRST, ename
B. ORDER BY NVL(comm,0) ASC NULLS LAST, ename
C. ORDER BY comm DESC NULLS LAST, ename
D. ORDER BY NVL(enam,0) DESC, ename

答案：A

解題說明：
The ORDER BY clause is used in a SELECT statement to sort the returned rows by one or more columns.
A . This clause would attempt to order by ename as if it were a numeric column, which is not correct since ename is not numeric.
B . This is the correct answer. The NVL function replaces nulls with the specified value, in this case, 0. This clause sorts by comm, with nulls considered as 0 and appearing first, followed by the actual values, and then sorts by ename.
C . This clause is incorrect because it would place null values at the end, but in the output, rows with null comm appear at the beginning.
D . This clause would sort the comm in descending order with the nulls at the end, which is not consistent with the output shown.
Reference:
Oracle Database SQL Language Reference, 12c Release 1 (12.1): "ORDER BY Clause" Oracle Database SQL Language Reference, 12c Release 1 (12.1): "NVL Function" Please note that the correct formatting of SQL statements and clauses is crucial for the successful execution of queries.

問題 #101
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