Applied-Algebra Der beste Partner bei Ihrer Vorbereitung der WGU Applied Algebra FXO2 PFXP C957

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WGU Applied-Algebra Exam Syllabus Topics:

SectionObjectives
Polynomial Functions- Interpret inputs and outputs for polynomial functions
- Interpret rates of change for polynomial functions
- Interpret concavity for polynomial functions
Validity of Models- Examine utility
- Determine fit
- Determine validity
Logistic Functions- Interpret rates of change for logistic functions
- Interpret asymptotes for logistic functions
- Interpret inputs and outputs for logistic functions
Graphical Depictions- Interpret asymptotes for situations
- Interpret rates of change for situations
- Interpret concavity for situations
- Interpret maximum and minimum for situations
- Interpret inputs and outputs for situations
Linear Functions- Interpret rates of change for linear functions
- Interpret inputs and outputs of linear functions
Functions and Algebra of Functions- Derive conclusions based on data
- Derive conclusions based on notation
- Derive conclusions based on graphs
Exponential Functions- Interpret inputs and outputs for exponential functions
- Interpret concavity for exponential functions
- Interpret rates of change for exponential functions

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Applied-Algebra PDF Demo & Applied-Algebra Antworten

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WGU Applied Algebra FXO2 PFXP C957 Applied-Algebra Prüfungsfragen mit Lösungen (Q51-Q56):

51. Frage
The given function represents the price of a commodity, p, in dollars, based on the number of months, m, since the beginning of 2020.
p(m)=5m+5
What is the average rate of change of the price over the interval m=1to m=10?

Antwort: D

Begründung:
The function is:
p(m)=5m+5
This is a linear function in the form:
p(m)=mx+b
For a linear function, the average rate of change over any interval is the same as the slope.
The slope is the coefficient of m:
5
So the price increases at a constant rate of:
$5 " per month "
We can also verify using the average rate of change formula:
(p(10)-p(1))/(10-1)
Find p(10):
p(10)=5(10)+5=55
Find p(1):
p(1)=5(1)+5=10
Now calculate:
(55-10)/(10-1)
=45/9
=5


52. Frage
The logistic function f(x), whose graph is shown, models the number of registrants for an academic conference, where xrepresents the number of weeks since registration opened and f(x)represents the number of registrants.

How does the number of registrants change as time progresses from week 1 to week 7?

Antwort: D

Begründung:
From week 1 to week 7, the graph is increasing and becoming steeper.
In Applied Algebra, when a graph is increasing and its slope is getting larger, the quantity is said to be:
" increasing faster and faster "
This interval is on the early increasing part of the logistic curve, before the graph begins to level off.
Therefore, the correct answer is:
# ( " B " )


53. Frage
The function P(t) represents the yearly profit, in millions of dollars, for a clothing store since opening. The graph of P(t) is shown.

How should the maximum value be interpreted?

Antwort: C

Begründung:
The maximum value of a polynomial graph is found at the highest point of the curve. In this problem, P(t) represents yearly profit in millions of dollars, and t represents years since opening. The graph reaches its highest point at approximately t=10.5, so the maximum yearly profit occurs about 10.5 years after opening.
The vertical value at that point is about 2.25, but because the profit is measured in millions of dollars, this means 2.25 million dollars. Converting gives 2.25×1,000,000=2,250,000. Therefore, the correct interpretation must include both the correct time and the correct dollar amount. The correct answer is C.


54. Frage
The weekly number of players, P, in hundreds, on a gaming website is modeled by the graph. The horizontal axis shows the number of years since the website was launched.

When did the website reach the minimum weekly number of players?

Antwort: B

Begründung:
The graph shows the weekly number of players on a gaming website.
The horizontal axis represents:
" years since launching "
The vertical axis represents:
" players in hundreds "
The graph is an upward-opening curve, so the minimum value occurs at the lowest point of the graph.
From the graph, the lowest point occurs at approximately:
t=4
This means the website reached its minimum weekly number of players approximately:
4 " years after it was launched "
Therefore, the correct answer is:
# ( " B " )


55. Frage
The population of fish in a lake is changing according to the function
P(t)=462-35t
where tis the number of months since the beginning of the year and P(t)is the fish population at time t.
Which interpretation of the rate of change is correct?

Antwort: C

Begründung:
The function is:
P(t)=462-35t
This is a linear function in the form:
P(t)=mt+b
where:
m= " rate of change "
and
b= " initial value "
In this function:
m=-35
The negative sign means the fish population is decreasing.
The number 35tells us the amount of decrease per month.
So the fish population is decreasing by:
35 " fish per month "
The value 462is not the rate of change. It represents the starting fish population at the beginning of the year, when t=0:
P(0)=462
Therefore, the correct interpretation is:
" The number of fish in the lake is decreasing at a constant rate of 35 fish per month. " So the correct answer is:
# ( " D " )


56. Frage
......

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