Applied-Algebra Prüfungsfragen - Applied-Algebra Musterprüfungsfragen

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WGU Applied-Algebra Exam Syllabus Topics:

SectionObjectives
Graphical Depictions- Interpret asymptotes for situations
- Interpret maximum and minimum for situations
- Interpret inputs and outputs for situations
- Interpret rates of change for situations
- Interpret concavity for situations
Functions and Algebra of Functions- Derive conclusions based on notation
- Derive conclusions based on graphs
- Derive conclusions based on data
Validity of Models- Determine fit
- Determine validity
- Examine utility
Logistic Functions- Interpret inputs and outputs for logistic functions
- Interpret rates of change for logistic functions
- Interpret asymptotes for logistic functions
Polynomial Functions- Interpret rates of change for polynomial functions
- Interpret concavity for polynomial functions
- Interpret inputs and outputs for polynomial functions
Linear Functions- Interpret rates of change for linear functions
- Interpret inputs and outputs of linear functions
Exponential Functions- Interpret inputs and outputs for exponential functions
- Interpret concavity for exponential functions
- Interpret rates of change for exponential functions

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Applied-Algebra Musterprüfungsfragen & Applied-Algebra Tests

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WGU Applied Algebra FXO2 PFXP C957 Applied-Algebra Prüfungsfragen mit Lösungen (Q102-Q107):

102. Frage
In the graph showing the number of new customer accounts, the horizontal axis shows the number of weeks since the beginning of winter and the vertical axis shows the number of new customer accounts. More customer accounts are opened during snowy weeks than during weeks without snow.

When was it likely snowy?

Antwort: A

Begründung:
This question asks us to interpret unusually high values on a graph. The problem states that more customer accounts are opened during snowy weeks than during weeks without snow. Therefore, the likely snowy weeks correspond to the peaks on the graph, where the number of new customer accounts is noticeably higher than surrounding weeks. The graph shows clear spikes at approximately week 7 and week 14. These weeks have higher account openings compared with nearby weeks, making them the best evidence of snowy conditions.
Week 1 and week 5 do not match the main peaks shown in the graph. Since the snowy weeks should correspond to the highest customer-account values, the correct answer is D.


103. Frage
A new company just launched and is using the function M(t)to predict its market share after tyears. The graph of M(t)is shown.

When should the company expect to have a market share of 60%?

Antwort: C

Begründung:
The function M(t)represents the company's predicted market share after tyears.
The horizontal axis represents:
t= " time in years "
The vertical axis represents:
M(t)= " market share percentage "
We need to find when the company's market share reaches:
60%
To answer this from the graph:
Locate 60on the vertical axis.
Move horizontally until reaching the blue curve.
Move downward to the horizontal axis to read the corresponding time.
From the graph, the blue curve reaches 60%a little after 6years, approximately at:
t=6.6
So the company should expect to have a market share of 60%after about:
6.6 " years "


104. Frage
The graphed function n(t)represents the number of animals, n, at a feeding station thours after 5:00 a.m. The plotted points Aand Bhave coordinates (1#10.6)and (8#6.59).

Which statement gives the correct interpretation of the average rate of change of the number of animals over the interval from point Ato point B?

Antwort: A

Begründung:
The average rate of change tells how much the output changes per one unit of input.
Here:
t= " hours after 5:00 a.m. "
and
n(t)= " number of animals "
The two given points are:
A=(1,10.6)
and
B=(8,6.59)
Use the average rate of change formula:
(y_2-y_1)/(x_2-x_1 )
Substitute the coordinates:
(6.59-10.6)/(8-1)
=(-4.01)/7
#-0.573
The negative sign means the number of animals is decreasing.
So the correct interpretation is:
" The number of animals at the station decreases at an average rate of " 0.573 " animals per hour. " Therefore, the correct answer is:
# ( " B " )


105. Frage
The scatterplot shows data on the popularity of a blog post over time. The graphed regression function has an r2value of 0.42.

Is it appropriate to make a prediction for the number of daily blog post views after 12.4 days?

Antwort: D

Begründung:
Explanation:The regression model has r2=0.42, which indicates a moderate fit. This means the model captures some of the pattern in the data, but it is not strong enough to support distant predictions. The proposed prediction is for x=12.4 days, which lies beyond the largest observed x-value in the scatterplot. Since the model is only moderate, acceptable extrapolation must remain close to the original data range. The value x=12.4 is more than 25% of the range beyond the maximum observed value, so it is too far outside the data for a reliable prediction. Therefore, the prediction is not appropriate. The correct answer is B.


106. Frage
The function F(n) represents the relationship between the number of animals in two enclosures, where n is the number of animals in enclosure A and F is the number of animals in enclosure B. The number of animals in enclosure B is 20 more than the number of animals in enclosure A.
Which function represents this situation?

Antwort: B

Begründung:
The function F(n) gives the number of animals in enclosure B.
The input n represents the number of animals in enclosure A.
The problem says enclosure B has 20 more animals than enclosure A. The phrase "20 more than" means we add 20:
F(n)=n+20
For example, if enclosure A had 30 animals, then enclosure B would have:
F(30)=30+20=50
So the function that represents the situation is:
F(n)=n+20


107. Frage
......

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