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Oracle Database SQL Sample Questions (Q206-Q211):

NEW QUESTION # 206
View the Exhibit and examine the structure of the CUSTOMERS table.

CUSTOMER_VU is a view based on CUSTOMERS_BR1 table which has the same structure as CUSTOMERS table.
CUSTOMERS need to be updated to reflect the latest information about the customers.
What is the error in the following MERGE statement?

A. The INTO clause is misplaced in the command.
B. The CUSTOMER_ID column cannot be updated.
C. The WHERE clause cannot be used with INSERT.
D. CUSTOMER_VU cannot be used as a data source.

Answer: B

NEW QUESTION # 207
Which three are true about the MERGE statement?

A. It can use views to produce source rows.
B. It can update, insert, or delete rows conditionally in multiple tables.
C. It can use subqueries to produce source rows.
D. It can combine rows from multiple tables conditionally to insert into a single table.
E. It can update the same row of the target table multiple times.
F. It can merge rows only from tables.

Answer: A,C,D

NEW QUESTION # 208
Examine the structure of the EMPLOYEES table.

You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.
Which query would retrieve the required result?

A. SELECT last_name, hire_date, salary
FROM employees
WHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = 100) UNION ALL (SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE -180 INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE salary > 10000);
B. SELECT last_name, hire_date, salary
FROM employees
WHERE salary > 10000
UNION ALL
SELECT last_name, hire_date, salary
FROM employees
WHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100) INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE- 180;
C. (SELECT last_name, hire_date, salary
FROM employees
WHERE salary > 10000
UNION ALL
SELECT last_name, hire_date, salary
FROM employees
WHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100)) UNION SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE -180;
D. SELECT last_name, hire_date, salary
FROM employees
WHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = '100') UNION SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE -180 INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE salary > 10000;

Answer: D

NEW QUESTION # 209
View the exhibit and examine the structure of the STORES table.
STORES table
NameNull?Type
---------------------- -------------
STORE_IDNUMBER
NAMEVARCHAR2(100)
ADDRESSVARCHAR2(200)
CITYVARCHAR2(100)
COUNTRYVARCHAR2(100)
START_DATEDATE
END_DATEDATE
PROPERTY_PRICENUMBER
You want to display the NAME of the store along with the ADDRESS, START_DATE, PROPERTY_PRICE, and the projected property price, which is 115% of property price.
The stores displayed must have START_DATE in the range of 36 months starting from 01- Jan-2000 and above.
Which SQL statement would get the desired output?

A. SELECT name, address||','||city||','||country AS full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
B. SELECT name, concat (address| | ','| |city| |', ', country) AS
full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, '01-JAN-2000') <=36;
C. SELECT name, concat (address||','| |city| |', ', country) AS
full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
D. SELECT name, concat (address| | ','| |city| |', ', country) AS
full_address,start_date,property_price, property_price*115/100FROM storesWHERE TO_NUMBER(start_date-TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;

Answer: C

NEW QUESTION # 210
View the Exhibit and examine the structure of the ORDERS table. The ORDER_ID column is the PRIMARY KEY in the ORDERS table.

Evaluate the following CREATE TABLE command:
CREATE TABLE new_orders(ord_id, ord_date DEFAULT SYSDATE, cus_id)
AS
SELECT order_id.order_date,customer_id
FROM orders;
Which statement is true regarding the above command?

A. The NEW_ODRDERS table would get created and all the constraints defined on the specified columns in the ORDERS table would be passed to the new table.
B. The NEW_ODRDERS table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
C. The NEW_ODRDERS table would get created and only the NOT NULL constraint defined on the specified columns would be passed to the new table.
D. The NEW_ODRDERS table would not get created because the DEFAULT value cannot be specified in the column definition.

Answer: C

NEW QUESTION # 211
......

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