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The Platform Salesforce Certified JavaScript Developer - Multiple Choice JS-Dev-101 Exam credential makes it simple to renew your skills and knowledge to keep up with the latest trends. The Platform Salesforce Certified JavaScript Developer - Multiple Choice JS-Dev-101 exam certification is a worthwhile, internationally accepted industry credential. You can become a recognized specialist in addition to learning new technological needs and honing your abilities.
| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101) |
| Exam Number: | JS-Dev-101 |
| Exam Duration: | 105 minutes |
| Related Certifications: | Salesforce Platform Developer II Salesforce Platform Developer I |
| Passing Score: | 65% |
| Available Languages: | English |
| Exam Price: | $200 USD |
| Exam Format: | Multiple Choice Questions, Multiple Select Questions |
| Certificate Validity Period: | 1 year (maintenance required annually in Salesforce certification program) |
| Real Exam Qty: | 60 (multiple choice) |
| Recommended Training: | Salesforce Trailhead - JavaScript Developer I MDN Web Docs - JavaScript Guide |
| Exam Registration: | Salesforce Certification Registration Kryterion Webassessor (Exam Delivery) |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor) |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and web development is recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper |
>> Latest JS-Dev-101 Test Notes <<
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NEW QUESTION # 147
Refer to the code below:
What is the output of this function when called with an empty array?
Answer: B
NEW QUESTION # 148
let sampleText = "The quick brown fox jumps";
Which three expressions return true for a substring?
Answer: B,C,E
Explanation:
The correct answers are A, B, and C.
The original variable name appears to contain a typing error. The variable should be used consistently as sampleText:
let sampleText = "The quick brown fox jumps";
A is correct because includes() checks whether a string contains a specific substring and returns a Boolean value:
sampleText.includes('fox');
Since "fox" exists inside "The quick brown fox jumps", this returns:
true
B is correct after correcting the typing error. The correct expression is:
sampleText.indexOf('quick') > -1;
indexOf() returns the index position where the substring is found. If the substring is not found, it returns -1.
Since "quick" exists in the string, sampleText.indexOf('quick') returns a value greater than -1, so the expression returns:
true
C is correct after correcting the missing quotation marks and adding a Boolean comparison:
sampleText.indexOf('fox') !== -1;
The substring "fox" exists in the string, so indexOf('fox') does not return -1. Therefore, the expression returns:
true
D is incorrect because the method name is typed incorrectly. JavaScript string has includes(), not include().
Incorrect:
sampleText.include('fox')
Correct:
sampleText.includes('fox')
E is incorrect because JavaScript string matching is case-sensitive:
sampleText.indexOf('Quick') !== -1;
The string contains "quick" with a lowercase q, not "Quick" with an uppercase Q, so this returns:
false
Therefore, the verified answers are A, B, and C.
NEW QUESTION # 149
Why does second have access to variable a?
Answer: A
Explanation:
The answer is B because JavaScript uses lexical scope.
When a function is created inside another function, the inner function can access variables from the outer function where it was defined.
For example:
function first() {
let a = 10;
function second() {
console.log(a);
}
second();
}
Here, a belongs to the outer function first(). The inner function second() can access it because JavaScript looks for variables through the scope chain.
The lookup works like this:
1. Look inside second()
2. If not found, look inside first()
3. If not found, look in the global scope
Since a is found in the outer function's scope, second() can use it.
This is also the basis of a closure. A closure allows an inner function to remember and access variables from its outer lexical environment.
Why the other options are incorrect:
A is not the best answer because a is not declared inside second() itself.
C is incorrect because the prototype chain is used for object property lookup, not local variable scope lookup.
D is incorrect because hoisting explains how declarations are moved during compilation, but it does not explain why an inner function can access an outer function's variable.
Therefore, the verified answer is B.
NEW QUESTION # 150
Refer to the following code:
Let sampleText = 'The quick brown fox jumps';
A developer needs to determine if a certainsubstring is part of a string.
Which three expressions return true for the given substring ?
Choose 3 answers
Answer: B,C,D
NEW QUESTION # 151
A developer wants to use a module called DatePrettyPrint.
This module exports one default function called printDate().
How can the developer import and use printDate()?
Answer: B
Explanation:
ES Modules follow these rules:
Default exports are imported using:
import anyName from 'module'
The name chosen in the import does NOT need to match the exported name.
If a module exports:
export default function printDate() {}
then consuming code should import the function directly:
import printDate from '/path/DatePrettyPrint.js';
To execute it:
printDate();
Option analysis:
A incorrect:
import DatePrettyPrint() is invalid syntax.
Also calling printDate() without importing it is incorrect.
B incorrect:
A default export imported as DatePrettyPrint gives the function itself, not an object containing methods.
You cannot call DatePrettyPrint.printDate().
C incorrect:
Imports printDate but then calls DatePrettyPrint.printDate(), which does not exist.
D correct:
Correct import of a default-exported function.
Correct direct invocation.
JavaScript Knowledge Reference (text-only)
Default export β imported without braces.
Importing default functions gives a callable function, not an object.
Correct syntax: import identifier from "module".
NEW QUESTION # 152
......
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