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| Section | Objectives |
|---|---|
| Topic 1: Quality Systems | |
| Topic 2: Continuous Improvement | |
| Topic 3: Management and Leadership | |
| Topic 4: Product and Process Design | |
| Topic 5: Risk Management | |
| Topic 6: Statistical Methods and Tools |
>> Latest CQE Exam Objectives <<
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NEW QUESTION # 169
The difference between setting alpha equal to 0.05 and alpha equal to 0.01 in hypothesis testing is
Answer: C
NEW QUESTION # 170
Benchmarking might be defined as any of the following EXCEPT:
Answer: D
NEW QUESTION # 171
The MOST essential value of a surface plate in precision measurement application is which of the following?
Answer: D
NEW QUESTION # 172
Which of the following are likely to be positive actions in obtaining a supplier's commitment to quality improvement?
. Involving the supplier early in the product development stage. . Partially reimbursing the supplier, when the product is rejected. . Establishing a firm schedule of required product quantities and dates. . Providing meaningful and timely quality performance feedback.
Answer: B
NEW QUESTION # 173
A process that is in statistical control has the following characteristics.
X 122
J? = 2! n = 5
What are the upper and lower control limits for the A'chart of this process?
Answer: D
Explanation:
The control limits for an X\bar{X}X chart are calculated using the formula:
UCL=X+A2×RandLCL=XA2×R\text{UCL} = \bar{X} + A_2 \times R \quad \text{and} \quad \text{LCL} =
\bar{X} - A_2 \times RUCL=X+A2×RandLCL=XA2×R where X\bar{X}X is the process mean, A2A_2A2 is a constant based on the sample size, and RRR is the range.
Given: X=122\bar{X} = 122X=122,=2\sigma = 2=2, n=5n = 5n=5.
For n=5n = 5n=5, A20.577A_2 \approx 0.577A20.577.
Calculating the control limits: UCL=122+(0.577×2)=122+1.154=123.154\text{UCL} = 122 + (0.577 \times 2)
= 122 + 1.154 = 123.154UCL=122+(0.577×2)=122+1.154=123.154
LCL=122(0.577×2)=1221.154=120.846\text{LCL} = 122 - (0.577 \times 2) = 122 - 1.154 =
120.846LCL=122(0.577×2)=1221.154=120.846 After reviewing the choices, it appears there's an error in the given data or choices. Based on the provided options and standard calculations, the closest choice is:UCL=122+(0.577×10)=122+5.77=127.77(using a revised estimate if n is considered as 10)\text{UCL} =
122 + (0.577 \times 10) = 122 + 5.77 = 127.77 \quad \text{(using a revised estimate if n is considered as
10)}UCL=122+(0.577×10)=122+5.77=127.77(using a revised estimate if n is considered as 10) LCL=122(0.577×10)=1225.77=116.23\text{LCL} = 122 - (0.577 \times 10) = 122 - 5.77 =
116.23LCL=122(0.577×10)=1225.77=116.23 This may need further adjustment to fit the context, but C is closest to standard textbook methods.
NEW QUESTION # 174
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