Actual Salesforce JS-Dev-101 Exam Questions In Different Formats

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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
Topic 2
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 3
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q144-Q149):

NEW QUESTION # 144
Original constructor function:
01 function Vehicle(name, price) {
02 this.name = name;
03 this.price = price;
04 }
05 Vehicle.prototype.priceInfo = function () {
06 return `Cost of the $(this.name) is $(this.price)$`;
07 }
08 var ford = new Vehicle('Ford Fiesta', '20,000');
Which class definition is correct?

Answer: D

Explanation:
A correct conversion from constructor-function syntax to ES6 class syntax must satisfy:
Use a constructor(name, price) method.
Assign instance properties inside the constructor.
Define methods without function keyword directly in the class body.
Use proper JavaScript template literals (backticks).
Evaluate each option:
Option A
Incorrect template literal syntax: uses single quotes with ${} which will not interpolate.
Option B
Incorrect:
The method vehicle() is not recognized as a constructor.
The constructor method is missing.
Option C
Incorrect:
The constructor has no parameters, but uses name and price which are undefined.
Option D
Correct:
Uses proper constructor with parameters.
Correct assignment of instance properties.
Correct template literal using backticks.
This is the valid ES6 class translation.
JavaScript Knowledge Reference (text-only)
ES6 classes require a constructor method for initialization.
Template literals must use backticks.
Methods inside classes are defined without the function keyword.
Omitted constructor parameters lead to undefined instance fields.


NEW QUESTION # 145
Refer to the code below:
letsayHello = () => {
console.log ('Hello, world!');
};
Which code executes sayHello once, two minutes from now?

Answer: D


NEW QUESTION # 146
Refer to the following code:
function test (val) {
If (val === undefined) {
return 'Undefined values!' ;
}
if (val === null) {
return 'Null value! ';
}
return val;
}
Let x;
test(x);
What is returned by the function call on line 13?

Answer: B


NEW QUESTION # 147
static delay = async delay => {
return new Promise(resolve => {
setTimeout(resolve, delay);
});
};
static asyncCall = async () => {
await delay(1000);
console.log(1);
};
console.log(2);
asyncCall();
console.log(3);
Assume delay and asyncCall are in scope as functions.
What is logged to the console?

Answer: A

Explanation:
The correct answer is D, because JavaScript executes synchronous code first, while the code after await runs later after the Promise resolves.
The execution order is:
console.log(2);
This runs first, so JavaScript logs:
2
Then this line runs:
asyncCall();
The asyncCall() function starts executing. Inside it, JavaScript reaches:
await delay(1000);
The delay(1000) function returns a Promise that resolves after 1000 milliseconds:
return new Promise(resolve => {
setTimeout(resolve, delay);
});
Because await pauses the rest of the asyncCall() function, this line does not run immediately:
console.log(1);
Instead, JavaScript continues executing the remaining synchronous code outside the async function:
console.log(3);
So JavaScript logs:
3
After approximately 1000 milliseconds, the Promise returned by delay(1000) resolves. Then the paused async function continues and runs:
console.log(1);
So JavaScript logs:
1
Final console output:
2
3
1
Important JavaScript concepts involved:
An async function always returns a Promise.
The await keyword pauses execution only inside the async function where it appears.
Code outside the async function continues running normally.
setTimeout() schedules its callback to run later, after the current synchronous code has finished.
Therefore, the verified answer is D. 2 3 1.


NEW QUESTION # 148
A team at Universal Containers works on a big project and uses yarn to manage the project's dependencies.
A developer added a dependency to manipulate dates and pushed the updates to the remote repository. The rest of the team complains that the dependency does not get downloaded when they execute yarn.
What could be the reason for this?

Answer: B

Explanation:
In JavaScript server-side development using Node.js, dependency management is typically handled through package managers such as npm or yarn. These tools categorize installed packages into:
dependencies - required for running the application in any environment
devDependencies - required only during development (testing tools, build tools, documentation generators, etc.) When a package is installed using:
yarn add <package> --dev
it is placed under the "devDependencies" section of package.json.
Behavior of Production Mode
Node.js uses the environment variable:
NODE_ENV=production
When this environment variable is set to production, both npm and Yarn follow the standard Node.js convention and skip installing devDependencies. This is done to optimize production builds and reduce deployment size. This is a known and documented behavior in Node.js package management tools.
Therefore, if:
The developer added the date-manipulation library as a dev dependency, and Other team members execute yarn in an environment where NODE_ENV=production is set, then Yarn will not install that dependency because devDependencies are intentionally excluded in production mode.
This explains the behavior described in the question.
Why the Other Options Are Incorrect
Option A:
"YARN_ENV is set to production" is incorrect because Yarn does not use the variable YARN_ENV for dependency installation behavior. Node.js tools use NODE_ENV, not YARN_ENV.
Option B:
This is incorrect because Yarn automatically writes dependencies into package.json. Unlike older npm versions, there is no need for the --save flag.
Option D:
There is no such option as --add. The correct syntax is simply:
yarn add <package>
Missing an option that does not exist cannot be the cause.
JavaScript Knowledge Reference
Node.js uses the environment variable NODE_ENV to determine production or development mode.
Package managers (npm and Yarn) follow the rule that when NODE_ENV=production, only "dependencies" are installed and "devDependencies" are skipped.
Yarn automatically persists installed packages to package.json without requiring --save.
Yarn uses the command yarn add to add dependencies; there is no --add flag.


NEW QUESTION # 149
......

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