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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I |
| Exam Number: | JS-Dev-001 |
| Certificate Validity Period: | 1 year (maintenance required via Salesforce certification maintenance modules) |
| Exam Price: | USD 200 (may vary by region/tax) |
| Available Languages: | English |
| Real Exam Qty: | 60 |
| Exam Format: | Multiple Select, Multiple Choice |
| Exam Duration: | 105 minutes |
| Related Certifications: | Salesforce Certified JavaScript Developer I Salesforce Certified Platform App Builder Salesforce Certified Platform Developer I |
| Passing Score: | 65% |
| Recommended Training: | Salesforce Trailhead JavaScript Developer I Prep Salesforce Developer Learning Paths |
| Exam Registration: | Salesforce Credentials Page Salesforce Certification Registration (Webassessor) |
| Sample Questions: | Salesforce JavaScript-Developer-I Sample Questions |
| Exam Way: | Online proctored or onsite testing via Kryterion Webassessor |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and Salesforce platform development is strongly recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper1 |
>> Valid Study JavaScript-Developer-I Questions <<
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Salesforce Certified JavaScript Developer I certification is a valuable credential for developers who want to demonstrate their expertise in building complex, scalable, and customizable applications on the Salesforce platform. JavaScript-Developer-I exam covers a range of topics, including JavaScript programming concepts, designing and building custom applications, and using the Salesforce Lightning Platform to create rich user interfaces.
Salesforce JavaScript-Developer-I Exam is a multiple-choice exam that consists of 60 questions. The time limit for the exam is 105 minutes, and candidates must score at least 68% to pass. JavaScript-Developer-I exam is available in English, Japanese, and Spanish, and it is proctored online.
NEW QUESTION # 49
Universal Container(UC) just launched a new landing page, but users complain that the
website is slow. A developer found some functions that cause this problem. To verify this, the
developer decides to do everything and log the time each of these three suspicious functions
consumes.
console.time('Performance');
maybeAHeavyFunction();
thisCouldTakeTooLong();
orMaybeThisOne();
console.endTime('Performance');
Which function can the developer use to obtain the time spent by every one of the three
functions?
Answer: C
NEW QUESTION # 50
Refer to the following code block:
01 let array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11];
02 let output = 0;
03
04 for (let num of array) {
05 if (output > 10) {
06 break;
07 }
08 if (num % 2 == 0) {
09 continue;
10 }
11 output += num;
12 }
What is the value of output after the code executes?
Answer: C
Explanation:
This code uses:
* A for...of loop to iterate over values in array.
* break to exit the loop entirely when output > 10.
* continue to skip even numbers.
* It sums only certain numbers into output.
Let's walk through the loop step by step.
Initial values:
* array = [1,2,3,4,5,6,7,8,9,10,11]
* output = 0
Loop: for (let num of array) { ... }
* First iteration: num = 1
* Line 05: if (output > 10) # 0 > 10 is false # no break.
* Line 08: if (num % 2 == 0) # 1 % 2 == 1, not 0, so false # no continue.
* Line 11: output += num # output = 0 + 1 = 1.
* Second iteration: num = 2
* output > 10 # 1 > 10 is false # no break.
* num % 2 == 0 # 2 % 2 == 0, so true # continue.
* Because of continue, line 11 is skipped.
* output remains 1.
* Third iteration: num = 3
* output > 10 # 1 > 10 is false.
* num % 2 == 0 # 3 % 2 == 1, false # no continue.
* output += num # output = 1 + 3 = 4.
* Fourth iteration: num = 4
* output > 10 # 4 > 10 is false.
* num % 2 == 0 # 4 % 2 == 0, true # continue.
* Skip sum; output remains 4.
* Fifth iteration: num = 5
* output > 10 # 4 > 10 is false.
* num % 2 == 0 # 5 % 2 == 1, false.
* output += num # output = 4 + 5 = 9.
* Sixth iteration: num = 6
* output > 10 # 9 > 10 is false.
* num % 2 == 0 # 6 % 2 == 0, true # continue.
* output remains 9.
* Seventh iteration: num = 7
* output > 10 # 9 > 10 is false.
* num % 2 == 0 # 7 % 2 == 1, false.
* output += num # output = 9 + 7 = 16.
* Eighth iteration would be num = 8, but:
At the top of the loop body, line 05 is checked again:
* if (output > 10) # 16 > 10 is true, so break; is executed.
When break runs:
* The loop terminates immediately.
* No further iterations (for num = 8, 9, 10, 11) are executed.
* Therefore, output stays at 16.
Final value of output after the loop ends is 16.
This matches option A.
Why other options do not match:
* B. 25: Would require adding more odd numbers (e.g., 9, 11) after 7, but the loop stops early due to output > 10.
* C. 11: Would be smaller; the actual sum of 1 + 3 + 5 + 7 until break is 16.
* D. 36: Would require summing many more values (e.g., most or all odd numbers up to 11), but again, the break condition stops the loop once output exceeds 10.
So:
The answer: A
JavaScript knowledge / Study Guide references (concept names only, no links):
* for...of loop over arrays
* break statement in loops (terminating a loop early)
* continue statement in loops (skipping to the next iteration)
* Modulo operator % to test even and odd numbers
* Step-by-step execution and control flow in loops
NEW QUESTION # 51
A developer tries to retrieve all cookies, then sets a certain key value pair in the cookie. These statements are used:
What is the behavior?
Answer: D
NEW QUESTION # 52
Refer to the code below:
Considering that JavaScript is single-threaded, what is the output of line 08 after the code executes?
Answer: A
NEW QUESTION # 53
Refer to the code below:
<html lang="en">
<tableonclick="console.log(Table log');">
<tr id="row1">
<td>Click me!</td>
</tr>
<table>
<script>
functionprintMessage(event) {
console.log('Row log');
}
Let elem = document.getElementById('row1');
elem.addEventListener('click', printMessage, false);
</script>
</html>
Which code change should be made for the console to log only Row log when 'Click me! ' is clicked?
Answer: D
NEW QUESTION # 54
......
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