2026 Latest Oracle 1z0-071: Reliable Oracle Database SQL Test Pattern

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Oracle 1z0-071 Exam Overview:

Certification Vendor:	Oracle
Exam Name:	Oracle Database SQL
Exam Number:	1z0-071
Real Exam Qty:	70
Certificate Validity Period:	No expiration for this exam/certification
Passing Score:	63%
Exam Format:	Multiple Choice
Exam Price:	$245 USD
Available Languages:	English, Korean, Simplified Chinese, Japanese, Portuguese
Related Certifications:	Oracle Database SQL Certified Associate Oracle Database Administrator Certified Associate (DBA)
Exam Duration:	120 minutes
Sample Questions:	Oracle 1z0-071 Sample Questions
Exam Way:	Pearson VUE testing center (online proctored option available)
Pre Condition:	No formal prerequisites required, but basic knowledge of relational database concepts is recommended
Official Syllabus URL:	https://education.oracle.com/oracle-database-sql-exam

>> Reliable 1z0-071 Test Pattern <<

Pass Guaranteed Quiz 2026 Oracle 1z0-071: Oracle Database SQL – Professional Reliable Test Pattern

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Oracle Database SQL Sample Questions (Q390-Q395):

NEW QUESTION # 390
Choose the best answer.
Examine the description of the EMPLOYEES table:

Which query is valid?

A. SELECT dept_id,MAX(AVG(salary)) FROM employees GROUP BY dept_id;
B. SELECT dept_id,AVG(MAX(salary)) FROM employees GROUP BY dapt_id;
C. SELECT depe_id,join_date,SUM(salary) FROM employees GROUP BY dept_id:
D. SELECT dept_id, join_date,SUM(salary) FROM employees GROUP BY dept_id, join_date;

Answer: D

Explanation:
In Oracle 12c SQL, the GROUP BY clause is used to arrange identical data into groups with the GROUP BY expression followed by the SELECT statement. The SUM() function is then used to calculate the sum for each grouped record on a specific column, which in this case is the salary column.
Option A is valid because it correctly applies the GROUP BY clause. Both dept_id and join_date are included in the SELECT statement, which is a requirement when using these columns in conjunction with the GROUP BY clause. This means that the query will calculate the sum of salaries for each combination of dept_id and join_date. It adheres to the SQL rule that every item in the SELECT list must be either an aggregate function or appear in the GROUP BY clause.
Option B is invalid due to a typo in SELECT depe_id and also because it ends with a colon rather than a semicolon.
Option C is invalid because you cannot nest aggregate functions like MAX(AVG(salary)) without a subquery.
Option D is invalid for the same reason as option C, where it tries to nest aggregate functions AVG(MAX(salary)), which is not allowed directly in SQL without a subquery.
For further reference, you can consult the Oracle 12c documentation, which provides comprehensive guidelines on how to use the GROUP BY clause and aggregate functions like SUM():
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): GROUP BY Clause
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): Aggregate Functions

NEW QUESTION # 391
View the exhibit and examine the structure of the CUSTOMERStable.

Which two tasks would require subqueries or joins to be executed in a single statement?

A. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers
B. listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'.
C. finding the average credit limit of male customers residing in 'Tokyo'or 'Sydney'
D. finding the number of customers, in each city, who's marital status is 'married'.
E. listing of customers who do not have a credit limit and were born before 1980

Answer: A,B

NEW QUESTION # 392
The SALES table has columns PROD_IDand QUANTITY_SOLDof data type NUMBER.
Which two queries execute successfully? (Choose two.)

A. COUNT(*) >10;
SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP
B. SELECT prod_id FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id HAVING
C. prod_id;
SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP
D. BY COUNT(*) >10;
SELECT COUNT(prod_id) FROM sales GROUP BY prod_id WHERE quantity_sold > 55000;
E. BY prod_id HAVING COUNT(*) >10;
SELECT COUNT (prod_id) FROM sales WHERE quantity_sold > 55000 GROUP BY

Answer: B,E

NEW QUESTION # 393
Examine this partial query:

Examine this output:

Which GROUP BY clause must be added so the query returns the results shown?

A. GROUP BY ch.channel_type, ROLLUP(t.month, co.country_code);
B. GROUP BY ch.channel_type, t.month, ROLLUP(co.country_code);
C. GROUP BY CUBE(ch.channel_type, t.month, co.country_code);
D. GROUP BY ch.channel_type, t.month, co.country_code;

Answer: B

NEW QUESTION # 394
Examine the description of the EMPLOYEES table:

Which query is valid?

A. SELECT dept_id, AVG(MAX(salary)) FROM employees GROUP BY dept_id;
B. SELECT dept_id, MAX(AVG(salary)) FROM employees GROUP BY dept_id;
C. SELECT dept_id, join_date, SUM(salary) FROM employees GROUP BY dept_id, join_date;
D. SELECT dept_id, join_date, SUM(salary) FROM employees GROUP BY dept_id;

Answer: C

NEW QUESTION # 395
......

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