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| Section | Weight | Objectives |
|---|---|---|
| Performance and Best Practices | 10% | - Optimization techniques
|
| Snowpark API and Development | 30% | - Multi-language support
|
| Snowpark Concepts and Architecture | 25% | - Session management and connection
|
| Data Transformations and Operations | 35% | - DataFrame manipulation
|
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NEW QUESTION # 235
You are tasked with creating a Snowpark UDTF (User-Defined Table Function) in Python to process a large CSV file stored in a Snowflake stage. Each row in the CSV represents a transaction, and you need to parse each row and extract specific fields based on a complex set of rules. The UDTF should return a table with the extracted fields. Consider the following code snippet:
Answer: B
Explanation:
While the provided code snippet might function, it's fundamentally inefficient. UDTFs in Snowpark are most performant when leveraging Snowpark DataFrame operations. Using 'pandas' inside the UDTF serializes and deserializes data between the Snowflake engine and the Python environment, introducing significant overhead. Options B, D and E are all generally incorrect as the code snippet provided is syntactically okay and contains the session parameter. A is incorrect due to performance and lack of optimization.
NEW QUESTION # 236
You have a Snowpark DataFrame 'df sales' containing sales data with columns like 'order id', 'product id', 'quantity', and 'sale_price' You want to persist this data into a Snowflake table named "SALES DATA'. You also want to create a dynamic table on top of this base table for faster analytics. You need to choose the appropriate persistence strategy and consider the implications of using a dynamic table. Which of the following options represents the BEST approach?
Answer: B
Explanation:
Option B is the best approach because it combines the advantages of persistence with the benefits of dynamic tables. Regular Table Persistence: Persisting as a regular table using DATA") ensures the data is stored durably in Snowflake. This serves as the foundation for the dynamic table. Dynamic Table Creation: Creating a dynamic table that uses 'SALES DATA' as its source provides a materialized view that automatically updates when the base table changes. This allows for faster analytics as the data is pre-computed and optimized for querying. Avoidance of Temporary Tables: Option A uses a temporary table, which is not suitable for long-term storage or scenarios where the data needs to persist beyond the session. Views vs. Dynamic Tables: Option C uses a view, which is not materialized. While views provide real-time access to the data, they can be slower for complex queries compared to dynamic tables. Option D isn't correct as 'table_type' is not a valid option for in Snowpark. Option E isnt valid scenario
NEW QUESTION # 237
You have a Snowpark DataFrame named containing order data that needs to be inserted into the 'ORDERS table. However, due to a recent data ingestion issue, some records in might already exist in the 'ORDERS table based on the 'ORDER ID' column. Your goal is to insert only the new orders into the 'ORDERS table while avoiding duplicates. Which of the following approaches, combining efficiency and correctness, is most suitable for this task? Assume 'session' and required libraries are already imported.
Answer: C,D
Explanation:
Options A and C are both suitable and efficient. Option A uses a 'left_anti' join to identify records in 'staged_orders' that do not exist in the 'ORDERS' table based on 'ORDER ID. This is a standard and efficient way to filter out existing records using Snowpark's DataFrame operations. Option C suggests a stored procedure with a MERGE statement, which is highly efficient for upsert operations directly within Snowflake. Option B is inefficient because it collects all the order IDs from the 'ORDERS table into the driver's memory, which could cause memory issues with large datasets. Option D is incorrect as 'on_duplicate_key' is not a valid parameter for insert_into method. Option E is using pandas dataframe to insert, which might not perform well in terms of scale.
NEW QUESTION # 238
You are tasked with creating a Snowpark stored procedure that needs to access a secret stored in Snowflake's Secret Managen The secret contains credentials required to connect to an external API. Which of the following steps are necessary to correctly and securely access and use the secret within your Snowpark stored procedure? (Select all that apply)
Answer: B,D,E
Explanation:
Options A, B, and D are the correct steps. First, the executing role needs 'USAGE on the secret. Second, session.get_secret('secret_name')' is the correct method to access the secret value within the procedure. The stored procedure must be created with EXECUTE AS CALLER for it to use the caller's permissions (which include access to the secret). Option C is incorrect because storing secrets directly in the code is a security risk. Option E is incorrect because Creating a UDF is unneccessary, stored procedures are capable of accessing secret manager directly with provided right access.
NEW QUESTION # 239
You have two Snowpark DataFrames, 'dfl' and 'df2 , both containing customer data, but with slightly different schemas. 'dfl' has columns 'customer_id', 'name', and 'email'. 'df2' has columns 'id', 'customer name', and 'email_address'. You want to perform a set- based operation to find all unique customer IDs present in 'dfl but NOT in 'df2' , considering that 'customer_id' in 'dfl corresponds to 'id' in 'df2. Which of the following code snippets will achieve this, ensuring that column names are correctly aligned before the operation?





Answer: C
Explanation:
Option D is the correct solution. First, 'customer_id')' renames the 'id' column in 'df2 to 'customer_id', aligning it with the 'customer_id' column in 'dfl Then, 'cifl performs the set difference operation, returning only the 'customer_id' values present in 'dfl& but not in the modified 'df2. 'exceptAll' (Option A) will include duplicates. Option B uses 'minus' which does not exist on Snowpark DataFrame. Options C uses 'subtract which also does not exist. Option E will cause unexpected results because the column name of dfl and df2 would be different.
NEW QUESTION # 240
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