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WGU Applied-Algebra Exam Syllabus Topics:

SectionObjectives
Polynomial and Rational Expressions- Rational Expressions
  • 1. Simplification
    • 2. Restrictions on variables
      - Polynomials
      • 1. Factoring techniques
        • 2. Operations with polynomials
          Foundations of Algebra- Equations and Inequalities
          • 1. Linear equations in one variable
            • 2. Inequalities and interval notation
              - Algebraic Expressions
              • 1. Evaluating expressions
                • 2. Simplifying expressions
                  • 3. Order of operations
                    Functions and Graphs- Graphing Functions
                    • 1. Coordinate plane interpretation
                      • 2. Transformations of graphs
                        - Function Concepts
                        • 1. Domain and range
                          • 2. Function notation
                            Linear Functions and Systems- Systems of Equations
                            • 1. Elimination method
                              • 2. Substitution method
                                - Linear Equations
                                • 1. Slope-intercept form
                                  • 2. Point-slope form
                                    Exponential and Logarithmic Concepts- Logarithmic Basics
                                    • 1. Conversion between exponential and logarithmic form
                                      • 2. Logarithm properties
                                        - Exponential Functions
                                        • 1. Exponential equations
                                          • 2. Growth and decay models

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                                            WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q68-Q73):

                                            NEW QUESTION # 68
                                            The number of people auditioning for a game show is expected to be 3 less than the number of people who auditioned last year. The function A(t)can be used to model the situation, where trepresents the number of people who auditioned last year and Arepresents the number of people expected to audition this year.
                                            Which quantity represents the number of people expected to audition this year, given that 280 people auditioned last year?

                                            Answer: D

                                            Explanation:
                                            The function A(t)represents the number of people expected to audition this year.
                                            The input trepresents the number of people who auditioned last year.
                                            The problem says this year's number is expected to be 3 less than last year's number. Therefore, the function rule is:
                                            A(t)=t-3
                                            We are told that 280 people auditioned last year, so:
                                            t=280
                                            Substitute 280into the function:
                                            A(280)=280-3
                                            A(280)=277
                                            So, the notation that represents the number of people expected to audition this year is:
                                            A(280)=277
                                            This means if 280 people auditioned last year, then 277 people are expected to audition this year.
                                            Therefore, the correct answer is:
                                            # ( " A " )


                                            NEW QUESTION # 69
                                            A music student attempted to learn a difficult new song. Each day, the student would play the song and be scored on their performance. The graph shows the results.

                                            What was the average daily change in performance from day 16 to day 20?

                                            Answer: D

                                            Explanation:
                                            The average daily change is the average rate of change over the interval from day 16 to day 20. From the graph, the performance score at day 16 is approximately 30.1, and the score at day 20 is approximately 57.6.
                                            Use the formula
                                            x
                                            2
                                            #x
                                            1
                                            y
                                            2
                                            #y
                                            1
                                            Substituting gives
                                            20#16
                                            57.6#30.1
                                            The numerator is 27.5, and the denominator is 4, so the average daily change is 27.5/4=6.875, which rounds to 6.88. This means the performance score increased by an average of about 6.88 points per day over the interval. Therefore, the correct answer is B.


                                            NEW QUESTION # 70
                                            The population of fish in a lake is changing according to the function P(t)=31t+438, where t is the number of months since the beginning of the year and P(t) is the fish population at time t. Which interpretation of the rate of change is correct?

                                            Answer: A

                                            Explanation:
                                            The function P(t)=31t+438 is linear and follows the form P(t)=mt+b. In this form, m is the rate of change and b is the initial value. Here, the coefficient of t is 31, so the fish population changes by 31 fish per month.
                                            Because 31 is positive, the population is increasing rather than decreasing. The number 438 is the initial fish population at the start of the year, not the rate of change. Therefore, the correct interpretation is that the number of fish in the lake is increasing at a constant rate of 31 fish per month. That matches option A.


                                            NEW QUESTION # 71
                                            The given function represents the price of a commodity, p, in dollars, based on the number of months, m, since the beginning of 2020.
                                            p(m)=5m+5
                                            What is the average rate of change of the price over the interval m=1to m=10?

                                            Answer: B

                                            Explanation:
                                            The function is:
                                            p(m)=5m+5
                                            This is a linear function in the form:
                                            p(m)=mx+b
                                            For a linear function, the average rate of change over any interval is the same as the slope.
                                            The slope is the coefficient of m:
                                            5
                                            So the price increases at a constant rate of:
                                            $5 " per month "
                                            We can also verify using the average rate of change formula:
                                            (p(10)-p(1))/(10-1)
                                            Find p(10):
                                            p(10)=5(10)+5=55
                                            Find p(1):
                                            p(1)=5(1)+5=10
                                            Now calculate:
                                            (55-10)/(10-1)
                                            =45/9
                                            =5


                                            NEW QUESTION # 72
                                            The number of registered voters in a district is modeled by a decreasing exponential function, where x represents the number of years since 2005 and f(x) represents the number of registered voters.

                                            Which interval is associated with the slowest average decrease in the number of registered voters?

                                            Answer: B

                                            Explanation:
                                            A decreasing exponential function falls quickly at first and then levels off over time. The "slowest average decrease" occurs where the graph is flattest, because the output changes by the smallest amount per year.
                                            Earlier intervals, such as 2005 to 2008, occur when the graph is steepest, so those intervals have a faster average decrease. Later intervals occur after the exponential decay has slowed. From the graph, the interval from 2015 to 2025 is farthest to the right and has the least steep downward trend. Therefore, the number of registered voters decreases most slowly during that interval. This is why the correct answer is D.


                                            NEW QUESTION # 73
                                            ......

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