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| Section | Weight | Objectives |
|---|---|---|
| Testing | 7% | - Testing frameworks and assertions - Test doubles and mocks - Code coverage and best practices - Unit testing concepts |
| Debugging and Error Handling | 7% | - Error types and exception handling - Defensive programming practices - Console methods and logging - Debugging tools and breakpoints |
| Asynchronous Programming | 13% | - Fetch API and HTTP requests - Event loop and micro/macro tasks - Promises and chaining - Callbacks and callback hell - Async/await syntax |
| Objects, Functions, and Classes | 25% | - Function definitions, parameters, and scope - Closures and execution context - Object creation, properties, and methods - Modules and imports/exports - Decorators and advanced function patterns - Class syntax, inheritance, and prototypes |
| Variables, Types, and Collections | 23% | - Type coercion and conversion rules - Truthy and falsy values - Array methods and data manipulation - JSON parsing and usage - Working with strings, numbers, dates, and booleans - Variable declaration and initialization |
| Server-Side JavaScript | 8% | - Module system and require/import - Node.js fundamentals and runtime - Command-line tools and scripts - Core Node.js modules |
| Browsers and Events | 17% | - Window and document object properties - Event handling, propagation, and delegation - Document Object Model (DOM) manipulation - Script loading and execution order - Browser APIs and Web Storage |
>> JavaScript-Developer-I Practice Exam Questions <<
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NEW QUESTION # 17
In which situation should a developer include a try... catch block around their function call?
Answer: B
NEW QUESTION # 18
Refer to the code below:
Const searchTest = 'Yay! Salesforce is amazing!" ;
Let result1 = searchText.search(/sales/i);
Let result 21 = searchText.search(/sales/i);
console.log(result1);
console.log(result2);
After running this code, which result is displayed on the console?
Answer: D
Explanation:
NEW QUESTION # 19
A developer is trying to handle an error within a function.
Which code segment shows the correct approach to handle an error without propagating it elsewhere?
Answer: C
NEW QUESTION # 20
Given the code:
const copy = JSON.stringify([new String( ' false ' ), new Boolean(false), undefined]); What is the value of copy?
Answer: D
Explanation:
JSON.stringify() applies the following rules:
* String objects (new String( ' false ' )) Are converted to their primitive string values . So:
* new String( " false " ) # " false "
* Boolean objects (new Boolean(false)) Convert to their primitive boolean value :
* new Boolean(false) # false
* Undefined values inside arrays According to the JSON specification, undefined becomes null when stringifying an array:
* JSON.stringify([undefined]) # " [null] "
Therefore, the array becomes:
[ " false " , false, null]
And JSON.stringify wraps it in quotes:
' [ " false " , false, null] '
This is exactly option A.
JavaScript Knowledge References (text-only)
* Object wrappers (String, Boolean) are converted to primitives during JSON serialization.
* undefined becomes null inside arrays when stringified.
* JSON.stringify() follows the JSON data-model rules strictly.
NEW QUESTION # 21
function myFunction() {
a = a + b;
var b = 1;
}
myFunction();
console.log(a);
console.log(b);
Which statement is correct?
Answer: D
Explanation:
The correct answer is A , not D.
Inside myFunction(), the declaration:
var b = 1;
is hoisted to the top of the function scope, but only the declaration is hoisted, not the assignment. So internally, JavaScript treats the function approximately like this:
function myFunction() {
var b;
a = a + b;
b = 1;
}
Now examine this line:
a = a + b;
Before JavaScript can assign a value to a, it must first evaluate the right-hand side:
a + b
At this point:
b
exists locally because var b was hoisted, so its value is:
undefined
However:
a
has not been declared anywhere. Reading an undeclared variable causes a:
ReferenceError
So this line throws an error before assignment happens:
a = a + b;
Because the error occurs on that line, the next line inside the function is never executed:
var b = 1;
Also, because the error is not handled with try...catch, the program stops before reaching:
console.log(a);
console.log(b);
Therefore, the accurate statement is:
Line 02 throws a reference error, therefore line 03 is never executed.
So the verified answer is A .
NEW QUESTION # 22
......
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