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Oracle 1z0-071 Exam Syllabus Topics:

Section	Objectives
SQL Retrieval	- Joins and set operations 1. UNION, INTERSECT, MINUS 2. INNER, OUTER, CROSS joins - SELECT statements and filtering data 1. ORDER BY and row limiting 2. WHERE clause and conditions
Relational Database Concepts	- Tables, rows, columns, and relational model basics - Data types and database objects overview
SQL Functions	- Single-row functions 1. Character, numeric, date functions - Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions
Data Manipulation and Schema Objects	- DDL operations 1. CREATE, ALTER, DROP tables and constraints - DML operations 1. INSERT, UPDATE, DELETE, MERGE
Subqueries and Advanced SQL	- Single-row and multi-row subqueries - Correlated subqueries and nested queries

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Oracle Database SQL Sample Questions (Q136-Q141):

NEW QUESTION # 136
You must write a query that prompts users for column names and conditions every time it is executed. (Choose the best answer.) The user must be prompted only once for the table name.
Which statement achieves those objectives?

A. SELECT &col1, '&col2'FROM &tableWHERE &&condition = '&cond';
B. SELECT &col1, &col2 FROM &&tableWHERE &condition = &&cond
C. SELECT &col1, &col2 FROM "&table"WHERE &condition = &cond;
D. SELECT &col1, &col2 FROM &&tableWHERE &condition = &cond;

Answer: D

NEW QUESTION # 137
Examine the description of the EMPLOYEES table:

Which two queries return rows for employees whose manager works in a different department?

A. SELECT emp. *
FROM employees emp
RIGHT JOIN employees mgr
ON emp.manager_ id = mgr. employee id
AND emp. department id <> mgr.department_ id
WHERE emp. employee_ id IS NOT NULL;
B. SELECT emp. *
FROM employees emp
WHERE manager_ id NOT IN (
SELECT mgr.employee_ id
FROM employees mgr
WHERE emp. department_ id < > mgr.department_ id
);
C. SELECT emp. *
FROM employees emp
JOIN employees mgr
ON emp. manager_ id = mgr. employee_ id
AND emp. department_ id<> mgr.department_ id;
D. SELECT emp.*
FROM employees emp
LEFT JOIN employees mgr
ON emp.manager_ id = mgr.employee_ id
AND emp. department id < > mgr. department_ id;
E. SELECT emp.*
FROM employees emp
WHERE NOT EXISTS (
SELECT NULL
FROM employees mgr
WHERE emp.manager id = mgr.employee_ id
AND emp.department_id<>mgr.department_id
);

Answer: C,E

Explanation:
To find employees whose manager works in a different department, you can use a subquery or a join that compares the DEPARTMENT_ID of the employee with the DEPARTMENT_ID of their manager.
A). This query is incorrect because the NOT IN subquery incorrectly attempts to compare EMPLOYEE_ID with MANAGER_ID, and the correlation condition inside the subquery is incorrect.
B). This query is correct. The NOT EXISTS clause correctly identifies employees whose MANAGER_ID matches the EMPLOYEE_ID of another employee (mgr) and where the DEPARTMENT_ID differs from that manager's DEPARTMENT_ID.
C). This query is incorrect because the LEFT JOIN will return all employees, and there is no WHERE clause to filter out those employees whose managers are in the same department.
D). This query is incorrect. The RIGHT JOIN does not ensure that the resulting rows are for employees whose manager works in a different department. It also returns all managers, which is not the requirement.
E). This query is correct. The JOIN ensures that the returned rows are for employees (emp) whose MANAGER_ID matches the EMPLOYEE_ID of managers (mgr), and it correctly filters to include only those employees whose DEPARTMENT_ID is different from their manager's DEPARTMENT_ID.

NEW QUESTION # 138
View the Exhibit and examine the structure of the CUSTOMERS table.
In the CUSTOMERS table, the CUST_LAST_NAME column contains the values 'Anderson' and
'Ausson'.
You issue the following query:
SQL> SELECT LOWER(REPLACE(TRIM('son' FROM cust_last_name),'An','O'))
FROM CUSTOMERS
WHERE LOWER(cust_last_name) LIKE 'a%n';
What would be the outcome?

A. an error because the REPLACE function specified is not valid
B. 'Oder' and 'Aus'
C. an error because the TRIM function specified is not valid
D. an error because the LOWER function specified is not valid

Answer: C

NEW QUESTION # 139
You execute this command:
TRUNCATE TABLE dept;
Which two are true?

A. It drops any triggers defined on the table.
B. It retains the integrity constraints defined on the table.
C. It always retains the space used by the removed rows.
D. A ROLLBACK statement can be used to retrieve the deleted data.
E. A FLASHBACK TABLE statement can be used to retrieve the deleted data.
F. It retains the indexes defined on the table.

Answer: B,F

Explanation:
When using the TRUNCATE TABLE command in Oracle, several aspects of the table's structure and associated database objects are impacted. Here's an explanation of each option:
* A: Incorrect. TRUNCATE TABLE does not drop triggers associated with the table; they remain defined.
* B: Correct. Indexes on the table are retained and not dropped when you truncate a table. However, if the index is a domain index, it may be dropped depending on its type.
* C: Correct. Integrity constraints such as primary keys, foreign keys, etc., are retained unless they are on a disabled state where truncation can lead to constraint being dropped.
* D: Incorrect. A TRUNCATE TABLE operation cannot be rolled back. It is a DDL (Data Definition Language) operation and commits automatically.
* E: Incorrect. The TRUNCATE TABLE operation deallocates the space used by the data unless the REUSE STORAGE clause is specified.
* F: Incorrect. TRUNCATE TABLE operation removes all the rows in a table and does not log individual row deletions, thus FLASHBACK TABLE cannot be used to retrieve the data.

NEW QUESTION # 140
Examine the description of the PRODUCTS table:

Which two statements execute without errors?

A. MERGE INTO new_prices n
USING (SELECT * FROM products) p
WHEN MATCHED THEN
UPDATE SET n.price= p.cost* 01
WHEN NOT MATCHED THEN
INSERT(n.prod_id, n.price) VALUES(p.prod_id, cost*.01)
WHERE(p.cost<200);
B. MERGE INTO new_prices n
USING (SELECT * FROM products WHERE cost>150) p
ON (n.prod_id= p.prod_id)
WHEN MATCHED THEN
DELETE WHERE (p.cost<200)
C. MERGE INTO new_prices n
USING (SELECT * FROM products WHERE cost>150) p
ON (n.prod_id= p.prod_id)
WHEN MATCHED THEN
UPDATE SET n.price= p.cost*.01
DELETE WHERE (p.cost<200);
D. MERGE INTO new_prices n
USING products p
ON (p.prod_id =n.prod_id)
WHEN NOT MATCHED THEN
INSERT (n.prod _id, n.price) VALUES (p.prod_id, cost*.01)
WHERE (p.cost<200);

Answer: C,D

NEW QUESTION # 141
......

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