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| Section | Objectives |
|---|---|
| Topic 1: User Interface Development | - Building iOS interfaces
|
| Topic 2: App Lifecycle and Deployment Concepts | - Understanding app structure
|
| Topic 3: App Logic and Data Handling | - Data management in apps
|
| Topic 4: Introduction to App Development with Swift | - Swift programming fundamentals
|
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질문 # 30
You have created a view which includes some formatted text:
You decide to extract this formatted text into a subview so that you can reuse the formatting for other texts.
You highlight the Text and choose Extract subview.
You refactor ExtractedView to BigGreenTextView.
You add the line let text: String to the extracted view above the body.
You replace " That ' s all folks " with a reference to text
How should you call this extracted View from the original View?
정답：C
설명：
This question belongs to View Building with SwiftUI , specifically the domain on extracting subviews to simplify the structure of an overlarge View .
When you create a custom SwiftUI view and add a stored property like:
let text: String
that property becomes part of the view's initializer. Since the property name is text, Swift expects you to pass the value using the parameter label text: when creating the view. So the correct call is:
BigGreenTextView(text: " That ' s all folks " )
That makes B the correct answer.
Why the others are wrong:
* A is incorrect because this is not using the expected parameter label.
* C would only be correct if there were already another variable named text in the calling scope and you wanted to pass that variable instead of the literal string shown in the question.
* D is incorrect because it omits the parameter label.
This is a standard SwiftUI pattern: extract reusable formatting into a separate custom View, give it an input property, and then pass the needed value through the initializer using the property label.
질문 # 31
For each statement about Navigation in SwiftUI. select True or False.
정답：
설명：
Explanation:
* You can treat a NavigationLink like a button, and run some Swift code when it is pressed. - False
* NavigationSplitView can be used to do navigation differently on different device sizes. - True
* You can put a header on your present View in a NavigationStack using .navigationTitle. - True
* If you have a NavigationLink that goes to another View with a NavigationLink, you need to declare a NavigationStack at each level. - False This question belongs to View Building with SwiftUI , specifically the objective on creating a multi-view app with navigation stacks, links, and sheets . Statement 1 is False because NavigationLink is primarily a navigation control that pushes or presents a destination in a navigation container; Apple documents it as creating a navigation link that presents a destination, not as a general-purpose action control like Button.
Statement 2 is True because NavigationSplitView is designed for adaptive navigation and can present navigation in different ways depending on platform and available space. Apple documents NavigationSplitView as a container for navigation across multiple columns, and this adaptive behavior is exactly why it is used differently across device sizes.
Statement 3 is True because .navigationTitle(...) sets the navigation title for a view shown inside a navigation container. Apple explicitly describes a view's navigation title as something used to visually display the current navigation state of an interface.
Statement 4 is False because you do not need a separate NavigationStack at every level. Apple describes NavigationStack as the container that manages a stack of views, and NavigationLink pushes additional destinations onto that stack. Nested destinations can keep navigating within the same stack.
질문 # 32
Complete the code that conforms to the View protocol by selecting the correct option from each drop-down list.
Note: You will receive partial credit for each correct answer.
정답：
설명：
Explanation:
This question belongs to View Building with SwiftUI , especially the domain covering positioning and/or layout a single SwiftUI View with standard Views and modifiers and the foundational structure of a SwiftUI view. In SwiftUI, a custom screen is typically declared as a struct that conforms to the View protocol. Apple's SwiftUI documentation shows the standard pattern:
struct ScreenView: View {
var body: some View {
Text( " Hello " )
}
}
Here, struct is required because SwiftUI views are commonly defined as structures. View is required after the colon because the type must conform to the View protocol. body is the required computed property that returns the content of the view as some View. Apple documents that every conforming View type must provide a body property that describes its content.
So the completed code is:
import SwiftUI
struct ScreenView: View {
var body: some View {
Text( " Hello " )
}
}
This is the canonical SwiftUI view declaration pattern and is one of the most fundamental concepts in App Development with Swift.
질문 # 33
Given the function definition, which two statements call the function correctly? (Choose 2.)
Based on the image provided, here is the text for each of the multiple-choice options:
정답：A,E
설명：
This question belongs to Swift Programming Language , specifically the objective on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func schedule(who name: String, from starting: String, to ending: String, _ place: String = " Zoom " ) { print( " Appointment: meeting \(name) from \(starting) to \(ending) at \(place) " )
}
This means:
* the external parameter names are who, from, and to
* the internal parameter names are name, starting, and ending
* the last parameter uses _, which means it has no external label
* the last parameter also has a default value of " Zoom "
Now evaluate the options:
* A is incorrect because it uses place: as an external label, but _ place means no external label is allowed.
* B is correct because it uses the required external names who, from, and to, and it omits the last parameter, which is allowed because it has a default value.
* C is incorrect because it uses who:, from:, and to: correctly, but this function's first three parameters are not declared that way in the provided option set; the valid matching call style from the choices is not this one because the function's labels are paired with internal names in the declaration syntax shown in the question.
* D is incorrect because it uses the internal names name, starting, and ending as if they were external labels.
* E is correct because it uses the external labels who, from, and to, and omits the final unlabeled parameter, letting Swift use the default " Zoom " .
So the two correct answers are B and E .
질문 # 34
When you press ' Show Button ' on your app. a modal View appears.
Complete the code by selecting the correct option from each drop-down list.
Note: You will receive partial credit for each correct answer.
정답：
설명：
Explanation:
This question belongs to View Building with SwiftUI , specifically the domain on creating a multi-view app with navigation stacks, links, and sheets .
To present a modal view in SwiftUI when a Boolean state changes, the correct modifier is .sheet . The matching sheet API for a Boolean binding is:
sheet(isPresented: $showInfo) {
// modal content
}
So the first blank must be .sheet , and the second blank must be (isPresented: .
The logic works like this:
* @State stores the local Boolean that controls presentation.
* Pressing the button calls showInfo.toggle(), changing the value from false to true.
* When that Boolean becomes true, the .sheet(isPresented:) modifier presents the modal view.
* When the modal is dismissed, SwiftUI updates the Boolean back as needed.
There is also a typing issue in the screenshot: the state variable appears as ShowInfo, while the button and binding use showInfo. Swift is case-sensitive, so those names must match. The corrected code should use the same identifier consistently, such as:
@State var showInfo = false
Therefore, the correct dropdown selections are:
sheet
(isPresented:
질문 # 35
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