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| Section | Objectives |
|---|---|
| Asynchronous JavaScript | - Error handling in async workflows - Event loop and concurrency model - Promises and async/await |
| Salesforce Platform Integration | - Security considerations in Salesforce JavaScript - Calling Apex methods from JavaScript - Lightning Web Components (LWC) JavaScript usage |
| Testing and Debugging | - Debugging techniques and tools - Unit testing principles |
| Browser and DOM Interaction | - Browser APIs (fetch, storage, timers) - DOM manipulation and traversal - Event handling and propagation |
| JavaScript Language Fundamentals | - ES6+ syntax and features - Functions, scope, and closures - Data types, variables, and operators |
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NEW QUESTION # 125
Refer the following code
What is the value of array after code executes?
Answer:
Explanation:
1, 2, 3, 5
NEW QUESTION # 126
Given the code:
01 function GameConsole(name) {
02 this.name = name;
03 }
04
05 GameConsole.prototype.load = function(gamename) {
06 console.log( ' ${this.name} is loading a game: ${gamename}.... ' );
07 }
08
09 function Console16bit(name) {
10 GameConsole.call(this, name);
11 }
12
13 Console16bit.prototype = Object.create(GameConsole.prototype);
14
15 // insert code here
16 console.log( ' ${this.name} is loading a cartridge game: ${gamename}.... ' );
17 }
18
19 const console16bit = new Console16bit( ' SNEGeneziz ' );
20 console16bit.load( ' Super Monic 3x Force ' );
What should a developer insert at line 15?
Answer: B
Explanation:
A subclass created by:
Console16bit.prototype = Object.create(GameConsole.prototype);
inherits all prototype methods from GameConsole, including load.
To override the inherited method, the correct syntax is to assign a new function to the method name on the prototype:
Console16bit.prototype.load = function(gamename) {
console.log(`${this.name} is loading a cartridge game: ${gamename}....`);
};
Why the other options are wrong:
* A assigns something to the constructor function itself, not to the prototype method. Invalid.
* B attempts to call a function in the left-hand side of an assignment; invalid syntax.
* C also uses invalid syntax-prototype methods cannot be defined this way.
* D is the correct definition of a prototype method override.
JavaScript Knowledge References (text-only)
* Methods are overridden by assigning functions to Subclass.prototype.methodName.
* Object.create() establishes prototype inheritance.
* Constructor functions require prototype method attachment using assignment syntax.
NEW QUESTION # 127
Given two expressions var1 and var2, what are two valid ways to return the concatenation of the two expressions and ensure it is data type string?
Answer: C,D
Explanation:
We want to guarantee that the result is of type string regardless of what var1 and var2 are (numbers, booleans, etc.).
Option A:
String(var1).concat(var2)
* String(var1) converts var1 explicitly to a string.
* .concat(var2) calls String.prototype.concat, which:
* Converts var2 to string if needed.
* Returns a new string that is the concatenation of the two.
* Result is always a string. So A is valid.
Option B:
String.concat(var1 + var2)
* String.concat (as a static method) does not exist. concat is an instance method on string objects, not on the String constructor.
* var1 + var2 might be a number (if both numeric) and used incorrectly here. So B is invalid.
Option C:
var1 + var2
* + can mean:
* String concatenation (if at least one operand is a string).
* Numeric addition (if both operands are numbers).
* If var1 and var2 are both numbers, var1 + var2 will be a number, not a string.
* This does not ensure the result is always a string. So C is not guaranteed to satisfy the requirement.
Option D:
var1.toString() + var2.toString()
* var1.toString() converts var1 to a string (for most primitive/object types).
* var2.toString() does the same.
* Now both operands of + are strings, so the result is string concatenation.
* Result is guaranteed to be a string. So D is valid.
Therefore, the two valid ways are A and D.
Study Guide / Concept References (no links):
* String() conversion vs .toString()
* String.prototype.concat
* + operator overload: numeric addition vs string concatenation
* Type coercion rules for primitives
NEW QUESTION # 128
A developer wrote the following code:
01 let X = object.value;
02
03 try {
04 handleObjectValue(X);
05 } catch (error) {
06 handleError(error);
07 }
The developer has a getNextValue function to execute after handleObjectValue(), but
does not want to execute getNextValue() if an error occurs.
How can the developer change the code to ensure this behavior?
Answer: A
NEW QUESTION # 129
Refer to following code:
class Vehicle {
constructor(plate) {
This.plate =plate;
}
}
Class Truck extends Vehicle {
constructor(plate, weight) {
//Missing code
This.weight = weight;
}
displayWeight() {
console.log('The truck ${this.plate} has a weight of ${this.weight} lb.');}} Let myTruck = new Truck('123AB', 5000); myTruck.displayWeight(); Which statement should be added to line 09 for the code to display 'The truck 123AB has a weight of 5000lb.'?
Answer: C
NEW QUESTION # 130
......
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