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NEW QUESTION # 124
Refer to the code below:
01 const addBy = ?
02 const addByEight = addBy(8);
03 const sum = addByEight(50);
Which two functions can replace line 01 and return 58 to sum?
Answer: C,D
Explanation:
We want:
const addByEight = addBy(8);
const sum = addByEight(50);
And we need sum to be 58.
That means:
* addBy(8) must return a function.
* That returned function, when called with 50, must compute 8 + 50.
So addBy must be a higher-order function that returns another function capturing num1 and later using it with num2 (a closure).
* Option A
const addBy = function(num1) {
return function(num2) {
return num1 + num2;
}
}
Step-by-step:
* Call addBy(8):
* num1 is 8.
* The function returns an inner function: function(num2) { return num1 + num2; }.
* So addByEight becomes this inner function, with num1 closed over as 8.
* Then call addByEight(50):
* num2 is 50.
* The body computes num1 + num2, i.e., 8 + 50 = 58.
Therefore, with Option A in place:
const addByEight = addBy(8); // returns inner function
const sum = addByEight(50); // 58
So sum is 58. Option A is correct.
* Option D (corrected)
const addBy = (num1) = > {
return function(num2) {
return num1 + num2;
}
}
This is essentially the same logic expressed with an arrow function for the outer function:
* Call addBy(8):
* num1 is 8.
* Returns the inner function function(num2) { return num1 + num2; }.
* Call addByEight(50):
* num2 is 50.
* Computes num1 + num2 # 8 + 50 = 58.
So again:
const addByEight = addBy(8); // inner function with num1 = 8
const sum = addByEight(50); // 58
Option D is also correct.
Thus, A and D are the two functions that satisfy the requirement.
* Why B and C are incorrect
Option B:
const addBy = function(num1) {
return num1 * num2;
}
* This does not return a function; it returns a value.
* addBy(8) returns 8 * num2, but num2 is not defined in this scope, which would cause a ReferenceError.
* Also, addByEight would be a number (if num2 existed), not a function, so addByEight(50) would fail.
Option C:
const addBy = (num1) = > num1 + num2;
* Again, addBy returns a value, not a function.
* addBy(8) returns 8 + num2, but num2 is not defined, so this is also invalid due to ReferenceError.
* addByEight would be a number (or error), not a function.
Neither B nor C creates the required closure nor returns a function to be called later.
References / Study Guide concepts (no links):
* Higher-order functions in JavaScript
* Closures: inner functions capturing outer variables (num1)
* Arrow functions vs function expressions
* Returning functions from functions (function factories / currying)
* Scope and ReferenceError when a variable is not defined
NEW QUESTION # 125
Refer to the following code:
Let obj ={
Foo: 1,
Bar: 2
}
Let output =[],
for(let something in obj{
output.push(something);
}
console.log(output);
What is the output line 11?
Answer: C
NEW QUESTION # 126
Refer to the following code block:
class Animal{
constructor(name){
this.name = name;
}
makeSound(){
console.log(`${this.name} is making a sound.`)
}
}
class Dog extends Animal{
constructor(name){
super(name)
this.name = name;
}
makeSound(){
console.log(`${this.name} is barking.`)
}
}
let myDog = new Dog('Puppy');
myDog.makeSound();
What is the console output?
Answer:
Explanation:
Puppy is barking
NEW QUESTION # 127
Which statement accurately describes the behaviour of the async/ await keyworks ?
Answer: C
NEW QUESTION # 128
Given the code below:
Const copy = JSON.stringify((new String ('false') , new Bolean(false) undefined)); What is the value of copy?
Answer: B
NEW QUESTION # 129
......
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