無料でクラウドストレージから最新のShikenPASS Introduction-to-Cryptography PDFダンプをダウンロードする:https://drive.google.com/open?id=1CITwPGJDroox1lMTn5UjJy9GW8C37ILl
ShikenPASSはあなたの100パーセントの合格率を保証します。例外がないです。いまShikenPASSを選んで、あなたが始めたいトレーニングを選んで、しかも次のテストに受かったら、最も良いソース及び市場適合性と信頼性を得ることができます。ShikenPASSのWGUのIntroduction-to-Cryptography問題集と解答はIntroduction-to-Cryptography認定試験に一番向いているソフトです。
| Section | Objectives |
|---|---|
| Topic 1: Cryptanalysis and Attacks | - Brute Force and Dictionary Attacks - Common Attack Vectors - Social Engineering Prevention |
| Topic 2: Symmetric Cryptography | - Key Management - Stream Ciphers - Initialization Vectors (IV) - Block Ciphers (AES, DES, 3DES) |
| Topic 3: Applied Cryptography | - Cryptographic Best Practices - SSL/TLS Protocols - VPN Security - PGP and Email Encryption |
| Topic 4: Cryptography Fundamentals | - Cryptographic Terminology - History and Evolution of Cryptography - Symmetric vs Asymmetric Encryption |
| Topic 5: Hashing and Digital Signatures | - Hash Functions (MD5, SHA-1, SHA-256) - Message Authentication Codes (MAC) - Digital Signature Standards |
| Topic 6: Asymmetric Cryptography | - RSA Algorithm - Diffie-Hellman Key Exchange - Elliptic Curve Cryptography (ECC) - Public Key Infrastructure (PKI) |
>> Introduction-to-Cryptography勉強方法 <<
ShikenPASSのWGUどのバージョンでも、WGU Introduction to Cryptography HNO1ガイド資料はダウンロード数とIntroduction-to-Cryptography同時ユーザー数に制限がないため、ユーザーは同じ質問セットで複数の演習を練習し、知識を繰り返し統合できます。 学習の過程で、WGU Introduction to Cryptography HNO1実際の試験のテストエンジンは、学習プロセスの弱点を強化するのに便利です。 これは、間違ったIntroduction-to-Cryptography質問を整理するプロセスの代替として使用できます
質問 # 62
(A Linux user password is identified as follows:
$2a$08$AbCh0RCM8p8FGaYvRLI0H.Kng54gcnWCOQYIhas708UEZRQQjGBh4
Which hash algorithm should be used to salt this password?)
正解:D
解説:
The string format $2a$08$... is a well-known identifier for the bcrypt password hashing scheme. In common password-hash notation, the prefix indicates the algorithm and parameters: "$2a$" denotes bcrypt (version 2a), and "08" indicates the cost factor (work factor) controlling how computationally expensive hashing is. bcrypt is designed specifically for password storage: it includes a built-in salt and is intentionally slow and adaptive, making brute-force and GPU attacks far more expensive than fast general-purpose hashes like MD5 or SHA-512. NTLM and MD5 are obsolete for secure password storage due to speed and known weaknesses. SHA-512, while cryptographically strong as a hash, is still too fast for password hashing unless used in a dedicated password-hashing construction (e.g., PBKDF2, scrypt, Argon2) with appropriate parameters and salts. Since the given hash clearly matches bcrypt's encoding, the correct algorithm is bcrypt, which incorporates salting and cost-based key stretching as part of its design.
質問 # 63
(What is an example of a block cipher mode of operation?)
正解:B
解説:
A block cipher mode of operation defines how a block cipher (such as AES) is applied to data longer than a single block, and how blocks are linked (or not linked) to provide certain security properties. ECB (Electronic Codebook) is one of the canonical block cipher modes: it encrypts each plaintext block independently using the same key. While ECB is generally discouraged because it leaks patterns (identical plaintext blocks produce identical ciphertext blocks), it is still a valid and historically important mode of operation and is often used as a teaching example of what not to do for structured data. In contrast, SHA-256 is a hash function (one- way digest) and not a mode for block ciphers. DSA is a digital signature algorithm and provides authenticity
/integrity, not encryption mode behavior. RSA is an asymmetric cryptosystem, not a block cipher mode.
Therefore, among the options, ECB is the correct example of a block cipher mode of operation.
質問 # 64
(A security analyst is using 3DES for data encryption. Which 3DES key size is valid?)
正解:A
解説:
3DES (Triple DES) applies the DES block cipher three times to increase effective security, and its commonly cited valid key sizes correspond to how many independent DES keys are used. Two-key
3DES uses two 56-bit DES keys (K1 and K2) in an EDE sequence (Encrypt with K1, Decrypt with K2, Encrypt with K1), yielding 112 bits of keying material (ignoring parity bits). Three-key 3DES uses three independent 56-bit keys for a total of 168 bits of keying material, but that option is not listed here.
A 56-bit key corresponds to single DES, not 3DES. 128-bit is associated with AES, not 3DES. 2,048-bit is typical for RSA keys, not symmetric ciphers. Therefore, among the choices provided, 112-bit is a valid 3DES key size. While 3DES is now deprecated for many uses due to its 64-bit block size and performance limitations, understanding its keying options remains important for legacy system assessment.
質問 # 65
(Why should an administrator choose lightweight cryptography?)
正解:B
解説:
Lightweight cryptography is designed for constrained environments-devices with limited CPU, memory, storage, bandwidth, and power (battery). Examples include IoT sensors, smart locks, RFID tags, embedded controllers, and industrial devices. Administrators choose lightweight algorithms and protocols to maintain reasonable security while fitting strict resource budgets and real-time constraints. The goal is not "weaker security because data is unimportant," but rather efficient security that can still meet threat models under constraints. Option B captures this: embedded systems often cannot afford the computational cost of heavy cryptographic primitives (large key sizes, complex modes, frequent handshakes) or may struggle with latency and energy consumption. Option A is irrelevant because physical security of a desktop doesn't remove the need for cryptography in communications or storage. Option C is the opposite of lightweight design. Option D is a poor justification; security design should be based on risk, and lightweight cryptography is not merely for
"minimal protection," but for practical deployability under constraints. Therefore, the correct reason is limited resources on embedded systems.
質問 # 66
(Which cryptographic operation has the fastest decryption process?)
正解:C
解説:
Symmetric cryptography generally provides the fastest encryption and decryption performance among common cryptographic operations. Algorithms like AES and ChaCha20 are designed for high throughput and efficient implementation in software and hardware (e.g., AES-NI acceleration).
Symmetric decryption is computationally similar in cost to symmetric encryption, and both are far faster than asymmetric operations for equivalent security levels. Asymmetric cryptography (RSA, ECC) involves expensive mathematical operations (modular exponentiation or elliptic-curve scalar multiplication), making it much slower and unsuitable for bulk data decryption. That is why real-world secure protocols use asymmetric cryptography primarily to authenticate peers and establish keys, then switch to symmetric encryption for the actual data stream. Hashing is not decryption at all; it is one- way, and there is no "decrypt" operation for a hash. Padding is not a decryption mechanism; it is a formatting step used with block ciphers to align plaintext length. Therefore, the correct choice for the operation with the fastest decryption process is symmetric cryptography.
質問 # 67
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